Control volume example problems (momentum)

Lectures from Transport Phenomena course at Olin College.
This video works a few examples of using control volumes in conservation of momentum.

[@simonpeacock6621]

Thank you so much! Got me un-stumped from about 4 key concepts just by watching examples explained so well!

[@laeken-7642]

Thank you so much ! Clear, precise and well paced !

[@mehrannikahmadi8766]

Thank you so much this really saved me, my lecturer didn't even teach us this but is asking us questions harder than the examples you gave

[@lohitdhungana9384]

Thanks for uploading......your explaination is great

[@MrMenzza]

Very good video! Clarified things for me

[@SAURABHKUMAR-lw7dz]

Thank you very much, sir. I appreciate your effort 💟😊

[@astafzciba]

what if u2 is different tha U and we are given the function u(x,y), what should we do? does the expression on the second side of the pipe becomes "integral(rho*u(x,y)^2*dA" or "integral(rho*U*u(x,y)dA"?, i ignored the sign here btw.

[@HritikJain]

The force Fx in the first sum is the force on the fluid provided to the control volume, Correct?

[@eleazarzavala9008]

God bless to you. Thanks.

[@suyashsharma5027]

Hello Sir, I find at 8:16 the explanation that force gets "stronger and stronger" with the steeper angle of the wedge a little confusing as the same force will instantly disappear when the angle theta turns 90 (in the absence of gravity) , as the jet would be pushing the wedge with purely horizontal component and zero vertical component. Wit further increase in the angle the force will change the sign, thus at angle 90 we see a discontinuity in the force curve.

[@nadjizzidjan7340]

Hello there. If you listen to what he says right after, he'll add that (quote)" it would be a faulty assumption for high angles", so I guess that would explain the Theta=90° case, though I find it a bit intriguing. You might wanna consider the fact that neglecting some terms in our equations could affect the results. This is an assumption, once again. Have a good day sir. Oh damn, I'm 11 months late XD

[@benkadir179]

thank you, it is so quickly but ı understand

[@kavishdaya3594]

why is the normal at 2 a plus, if its normal to the velocity, shouldn't it also be a negative

[@williamblake20]

22:27 P_atm should be added negative because goes against normal direction and there is still negative sign outside the brackets?

[@user-ec1lc1ut8x]

Thank you, this was simple and easy to understand :)

[@evank8939]

Thank you so much :)

[@MichaelARiggs]

My hero

[@robertc1313]

At 24.01 the sign of P1 and Patm changes from the previous equation and was wondering why that is?

[@brianstorey7830]

It is because I moved it to the other side of the equation. I had 0 = termA - termB + f and I rewrote as f = termB-termA It is easy to mess the signs up in these problems so let me know if you think this is still an error.

[@robertc1313]

I see now thank you

[@8u88letea]

thanks

[@ahmednaji4375]

Small mistake happened here, the pressure is atmosphere, yes, but the outlet pressure force will never cancel that for inlet because of the cosine function found

[@logan8374]

still Patm, doesnt matter about the angle. still 0.

[@ntorres1152]

buenardo bro