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Пікірлер: 87
@aliibrahimshabrawy67457 жыл бұрын
I wonder why B1(t) = B11(t) = 0 you say that it doesn't exist yet but how can this be possible isn't region 1 and 11 have fluid so where there is a fluid there must be a property for it this is how i think if there is something wrong i want to know what is right?
@CPPMechEngTutorials7 жыл бұрын
Initially the system and control volume coincide at time t. Regions I and II have zero volume at this time, so they do not have mass (or any other extensive property) yet.
@srimanvallakatla60307 жыл бұрын
at time t B1 is not equal to 0 i think sooo
@CPPMechEngTutorials7 жыл бұрын
The volume occupied by region 1 is zero at time t. If there is no volume, all extensive properties are zero within the region.
@pro.navalarchitect7 жыл бұрын
How is volume occupied by region 1 is zero at time t ??
@CPPMechEngTutorials7 жыл бұрын
If you look at the image at time t, there is no B1. B1 is the region in which new fluid flows into the CV. So some time needs to pass (for example, time dt) in order for new fluid to enter the CV.
@DP-sq7lw4 жыл бұрын
What a beautiful video!! I love it! Beautiful theorem with a great explainer!
@Driftking0093 жыл бұрын
You saved the value of my degree man, thanks!
@waleedkhan85904 жыл бұрын
This has to be the best explanation of RTT ! And that too in a little more than 15 minutes. Amazing. Thank you!
@lamarjacksonallah10053 ай бұрын
ozan ozcan benim lan!!!!!
@furquanmohammed30863 жыл бұрын
Sir, At 10:38 while deriving the value of B' in should there be a negative sign since after taking after the dot product the whole value would be negative anyways, and initially when we said B'(out)-B'(in) are we not just considering their magnitudes only. and its exactly same as B'(out)+B'(in) when considered them as vectors. the result does not change anyways
@adriangonzalezsuaret93688 жыл бұрын
You are the best, I learn a lot with you. Thanks!!!
@CPPMechEngTutorials8 жыл бұрын
More videos are development. You will be able to learn a lot more soon. :)
@shailendrarana40733 жыл бұрын
Beautifully explained !
@j.gordonleishman640111 ай бұрын
Very nice explanation. A little robotic narration in places, but one of the best explanations of the RTT I have seen in 30 years. Well done!
@CPPMechEngTutorials11 ай бұрын
Beep bop boop
@ozzyfromspace4 жыл бұрын
That was a brilliant video! So well explained!
@CPPMechEngTutorials4 жыл бұрын
:)
@arijitsaha14725 жыл бұрын
Clean explanation leads to a better understanding and that happened with me. Thanks for sharing the information. But I have a doubt and that is why are you considering dB=b*rho*dA*dLn whereas the dV considered is in the direction of V vector?
@robertoneto6984 Жыл бұрын
What an awesome video! Quick question. You said that the inflow region of the CS is AFC and the outflow region is ADC, but AFC and ADC are 2d curves and not 3d surfaces. Shouldn't the inflow and outflow regions be 3D surfaces, since they contain a volume (and not an area)?
@prabhakartripathi44744 жыл бұрын
While factoring out mass, you have written m=m(1), why you considered (1) as intensive property? Please do explain.
@fourier07able7 жыл бұрын
BTW, mass ``m'' is not a property neither ``extensive'' nor ``intensive'' since it is the connection: B=mb, where ``B'' is extensive and ``b'' is intensive properties. For example, pressure and temperature are not neither intensive nor extensive, although they are properties of any (thermodynamical) system. On the contrary, the specific volume v=V/m is an intensive property of the system (open or closed!).
@siddharthprakash89426 жыл бұрын
Brilliant video. Gave me a very clear picture. Thanks a lot
@CPPMechEngTutorials6 жыл бұрын
Our pleasure.
@BTCIVSangharakshitKadam2 жыл бұрын
@@CPPMechEngTutorials Explained very nicely thank you.
@nidalal-sayed40193 жыл бұрын
Plzzz help me: I am trying to remember a theorem that study the movement of water particles. This theorem compasses two parts one is real and the another is imaginary part. If you know plz reply by the name of theorem or if you have a video share here as a link because I am tired from searching a video about this
@tabishkhan30944 жыл бұрын
Can we get these notes written somewhr
@drelina19382 жыл бұрын
Thanks very well ! Good Exceptional
@surryyaanjum82755 ай бұрын
Good explanation ❤
@ahmadahere36797 жыл бұрын
These videos are spectacular. They are helping me refresh and prepare for courses in my graduate program. Is it possible to get ahold of the slideshow material? I can't find any lecture slides of this calibur on this topic.
@CPPMechEngTutorials7 жыл бұрын
At the moment, the slides are provided to students enrolled in certain sections of ME 311 at Cal Poly Pomona. We do not know whether the slides will be available to the general public in the future though. However, the videos will remain on KZbin for the foreseeable future.
@trololollolololololl4 жыл бұрын
Grad program? We got it in undergrad first sem of second year :/
@mymathmates44095 жыл бұрын
Very good defined..go on..
@siavosheskandary28666 жыл бұрын
thank you it was very helpful
@nabadas80852 жыл бұрын
nice explanation,Thanks a lot
@martinjosealvarez3 жыл бұрын
Thanks from Mexico
@atakan7167 жыл бұрын
Awesome indeed!
@muhammadmehran71733 жыл бұрын
sir can u send this slides
@alejandroarias4735 жыл бұрын
Are there any videos of concepts and derivations but for thermodynamics?
@CPPMechEngTutorials5 жыл бұрын
We have thermodynamics videos at www.cpp.edu/meonline
@alejandroarias4735 жыл бұрын
@@CPPMechEngTutorials Thank you very much
@anjumshahzad785 жыл бұрын
great explanation
@mrunaldharbathula98725 жыл бұрын
excellent work...….keep going
@CPPMechEngTutorials5 жыл бұрын
We will.
@DipayanPyne5 жыл бұрын
The momentum of a system is conserved only when there is no net external force on it. The same is true for energy w.r.t a given system. So then dont you think the laws should not really be named as 'conservation' laws ? I mean I do understand the idea behind these laws, but the term conservation sounds a bit misleading, isn't it ? For eg: If the property under consideration is the mass of the system, we know that it doesnt change over time, coz the amount of matter in the system is fixed, as the system has been 'identified'. So the term on the LHS of the RTT drops to zero and we then rightfully say that the mass is 'conserved'. But the same is not always true for momentum or enery of a system, as they often change, given a net external force or an energy transfer. What do you think ?
@mohammadabedy24784 жыл бұрын
perfect teaching , thanks for video
@CPPMechEngTutorials4 жыл бұрын
Thanks!
@belisariogonzalez77938 жыл бұрын
When will Biddle's ME415 lectures be posted?
@CPPMechEngTutorials8 жыл бұрын
+Belisario Gonzalez Probably by F2016. They are still in post-production.
@CPPMechEngTutorials7 жыл бұрын
Update -- The ME 415 videos likely will be available by early W2017.
@saimsiddiqui15443 жыл бұрын
Very good
@paulboughosn61743 жыл бұрын
thank you !
@joyaljoshi50732 жыл бұрын
Why is at time t, B1(t)=0
@bacharobeid74303 жыл бұрын
perfect
@mohibahmadsiddiqui6597 жыл бұрын
Amazing.
@CPPMechEngTutorials7 жыл бұрын
Thanks!
@raymond-andrade5 жыл бұрын
Thanks, this helps
@CPPMechEngTutorials5 жыл бұрын
Great!
@timnguyen13296 жыл бұрын
4:20 , I confuse that what region is for Bcv(t+dt) , thanks!
@CPPMechEngTutorials6 жыл бұрын
The CV is fixed, so Bcv(t+dt) is the amount of B (mass, momentum, or energy) within the red dashed line at time t+dt. This can be different that the amount of B in the CV at time t. For example, let's say B is mass and imagine a denser fluid enters the CV in region I during time dt. In this case, Bcv(t+dt) > Bcv(t).
@aliallaou44155 жыл бұрын
Thank you very much
@CPPMechEngTutorials5 жыл бұрын
We're glad the video helped.
@amandadube1566 жыл бұрын
Thanks!!
@CPPMechEngTutorials6 жыл бұрын
No problem
@Inamullahkhan62947 жыл бұрын
Excellent
@CPPMechEngTutorials7 жыл бұрын
Glad you like the video.
@viclopez53636 жыл бұрын
Excelente!
@CPPMechEngTutorials6 жыл бұрын
Gracias!
@viclopez53636 жыл бұрын
Muchas gracias!
@ANKITKUMARchb-gn7xc7 жыл бұрын
nice video
@CPPMechEngTutorials6 жыл бұрын
Thanks
@sourabhyadav23634 ай бұрын
India se h koi
@usernumbereighteen3 жыл бұрын
why did I choose engineering
@ranajitmajumdar78365 жыл бұрын
nice 1
@CPPMechEngTutorials5 жыл бұрын
Thank you.
@allandavis61163 жыл бұрын
I think the eq. at 4:43 should read Bcv = Bi + (Bsys-Bii) which you rearrange to Bsys = Bcv - Bi + Bii
@acruzp5 жыл бұрын
I don't concur with my peers, I think this is a lousy explanation: It would be much better if you started out by giving an intuition of what the theorem attempts to solve, a general picture if you will. Then, if your objective is to impart a working, operational understanding of the subject, you can progress in the way you did. I would, though, prefer if, at every point, you stopped and explained where you're heading and why.
@CPPMechEngTutorials5 жыл бұрын
Follow-up videos show the application of the theorem to derive conservation laws for control volumes.