CSEC Maths - Factorizing Quadratic Expressions

[@BrianGhitar]

Best Math tutor in the world! God bless you!

[@lindsaycallender19]

Thank you so much this helped a lot I am a form 3 student and trying CXC for the first time. I am just reading the sub titles and it's very helpful.

[@ayannalewis8470]

BEST TUTOR in the world SIR👍

[@aleek9180]

im preparing for the cxc in jan ‘18. Im going to try my best. Thanks to you i understand more. 👏🏽

[@CSECMathematics]

Thanks...good luck.

[@noire.k]

@@CSECMathematics what two numbers when added give you -16 but when multiplied gives you 6

[@CSECMathematics]

@@noire.k Are you sure about these numbers you are giving me....the only combinations that gives a product of 6 will be 2,3, and 1, 6....I can't see how you can get a sum of -16

[@suieannamiller2295]

Your videos are extremely helpful.

[@laslayede-mattos4368]

Thank you so much sir.... God will bless you. I am weak in maths but this made me understand more..... Nuff love coming from Donella

[@aly2324]

Math cxc tomorrow !

[@Romecrome999]

It’s tomorrow again 💀

[@Swagger-p7987]

​@@Romecrome999same yo, same💀

[@E5_Mayor]

i just had to sign in to say thank you i didnt do to well in maths csec this year but im positive i'll get a 2 in jan because of you

[@CSECMathematics]

Good luck...I like the positive attitude.

[@ayannalewis8470]

8x x-10x-3 sum =10 the product which is ac= 8×-3=-24 so them which two numbers will give us minus 10 and minus 24 2 , 12 so then 8x +2x -12x -3x = 2(4x-1) 3(4x+1) that's distributive law = (4x+1) (2x-3)

[@ayannalewis8470]

3x-5x-2 sum =-5 product = 3x-2=-6 the two numbers are (1-6) which is 3x+×-6-2x=>x(3x+1). -2 (3x+1)= (3x+1 (x-2)

[@peterwalker5980]

For the question at 15:05 can I use 6,1 as my common factors? Because 6-1 will also give me +5.

[@CSECMathematics]

You can't use 6 and -1. The sum will be 5, but the product is -6. In this example the sum must be 5 and the product must be 6. Only 3 and 2 will give you that.

[@peterwalker5980]

Ok thank you for clearing that up.

[@spartanhero2683]

thank you terry this enlightened me

[@CSECMathematics]

I'm glad to hear.

[@spartanhero2683]

CSEC Mathematics I would also love to see some new content on your physics channel

[@CSECMathematics]

I know. Me too....unfortunately no time available to do it.

[@DinishaJoseph]

3×2-5×-2 sum-5 product 1,-6 3×+×-6×-2×(3×+1)-2(3×+1) = 3x+1

[@1_cqc]

Sir can you do a video on completing the square? Please?

[@DinishaJoseph]

× 2+7×+10=sum 7and product ac 1×10=10 =×2+5×+2×+10=5,2

[@demoyaaa]

hey sir, does it matter what order u write the final answer in? for example (x+3) (x+5)

[@CSECMathematics]

multiplication is commutive, so the order doesn't matter.

[@ayannalewis8470]

Afternoon sir

[@CliounPlayz]

have exam in the next 3 weeks

[@Ackhi]

1week sadly

[@Needbackupasap]

@@Ackhi couple hours

[@Ackhi]

@@Needbackupasap sigh in kerwin we trust

[@Needbackupasap]

@@Ackhi yah good luck we will pass

[@camronqt]

in mid term mark we trust

[@okaylexxi]

thankyou so much

[@DinishaJoseph]

Afternoon sir qns students

[@DinishaJoseph]

Product =ac 8x-3=24

[@DinishaJoseph]

2×+7×+5= sum=7 product ac -2×5=1

[@aliciaregis1744]

thanks so much

[@DinishaJoseph]

2x+5×+3 product ac =2×3=6

[@DinishaJoseph]

X2+5+3×15

[@ayannalewis8470]

Good morning sir

[@DinishaJoseph]

×2+×-6 sum =1 product 1×(-6)=-6

[@DinishaJoseph]

Sum =-8 product 1×15=15

[@DinishaJoseph]

2x(×+1)+3(×+1)

[@DinishaJoseph]

×2-5×-3+15= x(×2-5)3(×-5)

[@DinishaJoseph]

8×2+2×-12-3=2×(4×+1)-3(4×+1)

[@DinishaJoseph]

(4×+1)(2×-3)

[@ayannalewis8470]

3x2(-6×+1)=8×+4+4×+2, =8×2+4+2

[@DinishaJoseph]

X2+ 7x +10

[@DinishaJoseph]

×2+10×+21 sum 10 product 1×21=21

[@DinishaJoseph]

2×+5×+3

[@DinishaJoseph]

7,3

[@ayannalewis8470]

X2 +7×+3×+21= x =(×+7)2(×+3)

[@DinishaJoseph]

×2+3×-2(×+3) 3-2

[@DinishaJoseph]

×2+8+15 5,3

[@DinishaJoseph]

-5,-3

[@DinishaJoseph]

2×2+2×+5×+5=2×(×+1)5(×+1)

[@DinishaJoseph]

×2+7×+3×+21=(×+7)(×+3)

[@DinishaJoseph]

=×(×+3)-2(2+3)

[@DinishaJoseph]

(×-5)(×-3)

[@DinishaJoseph]

×(×+5)+2(×+5)=(×+5)(×+7)

[@DinishaJoseph]

=(×+3)(×-2)