CSIR JUNE 2019-Statistical and Chemical Thermodynamics | Detailed Solutions

[@1965dsk]

Hello Sir In the last question , the problem can be solved in a simple way like this we know that change in Internal energy = nCv (T2 - T1)...T1 is already given and we can find out T2 by using the temperature volume relationship....No of steps and calculation will be very simple if we do in this way.

[@AllBoutChemistry]

Thank you so much for sharing the method, indeed it can be done in that way as well

[@1965dsk]

Sir, In the calculation of free energy of mixing at 20:38...you have not used the EXCESS MOLAR GIBBS FREE ENERGY OF THE SOLUTION....how to incorporate the value of - 1.5 KJ/mol in the above calculation?

[@vanitak4739]

Sir it was much needed video for all of us bcz this time many new types of ques came nd i prsnally dont knw to solve them.so thnku very much.keep uploading such type of videos.

[@rachnajoshi1567]

Sir in question 115. If we determine T(2) with the help TV relation. We get T2 temp. Then we use u= n c(v)dT this is quite easy. is it right or wrong?

[@samankhan2519]

Same ques arises in my mind as well

[@baishwarya3760]

i did with this formula answer is same

[@mansimasoun5160]

The answer for the calculation of Gibbs energy is mixing is -12.9 not -6.

[@raju45656]

Sir question no 109 can be solved by sackur tetrode eqn as well...and that will be more easier than this

[@manpreetrana4484]

In last qus, why don't we use first law of thermodynamics..?

[@brijesh_shah]

Sir in last question why u use both formula ? P1V1=P2V2 & P1V1^gama=P2V2^gama....?

[@rajkishorepatra9632]

1s is for ideal Gas... And 2nd is for adiabatic condition

[@juberchoudhury9881]

Sir, In question no.14,you have not apply excess molar Gibbs energy,and ans is not -6.0. Answer is in fact -12.9. Which is Options 1. According to CSIR answer key

[@juberchoudhury9881]

Sir,plz verify me

[@dhanduaravind]

Yes, you are correct ✔️

[@reehanakhan8690]

We have to add it by 4×1.5

[@juberchoudhury9881]

@@reehanakhan8690 means???

[@reehanakhan8690]

@@juberchoudhury9881 means u have to add it by excess molar Gibbs energy n for 4 moles it will be 4×1.5

[@ashutoshblockbuster2.0]

So helpful ❤️❤️ thanks

[@chemeasytips]

In case Q 14. Excess molar Gibbs energy, answer was reported as option 1. Please justify the answer.

[@tandrimabanerjee6617]

How to remind the all values like (2.5)^(1/5) !!??

[@chemchallengers9920]

So Nice explanation sir

[@vipinhdr4911]

Nice explanation sir....... Make video on physical spectroscopy problems June 2019 .. Pls.....

[@chemicalsciencecsir536]

Respected....Sir...I think Gibbs free energy calculation is wrong....

[@subhadipbarman1822]

Yes sir its a wrong one....its ans is nmbr 1

[@zacpoonenshortclips4786]

Very useful, please make such videos

[@priynkajaale8113]

Thanku so much sir jiii very very helpful sir ...😍🙏🏼🙏🏼🙏🏼

[@nba9604]

Sir in one of your series. You did this same question( no. 14 ) and the answer is -12.9 Its confusing now..

[@AllBoutChemistry]

The video in which will be uploaded later will have correct solution and explanation. It happens in very rare cases, but plz follow the video which is uploaded recent

[@preetigupta5402]

Very well explained sir!!

[@geetanjalichopra2651]

Sir nice explanation. Please make more videos of previous year questions. Thanks for such a nice vodeo

[@manjotk8239]

thanku so much

[@gourabsaha1078]

In Q. 114 the answer is option 1 given in answer key

[@simrankakkar9281]

Suggest book for it

[@dipankarsahoo739]

Well explanation.

[@nba9604]

At 21:41

[@pritisurvaseofficial1400]

Tq so much solve more question..sir

[@shilpab.kulkarni2101]

Statistical thermodynamics is really a difficult part sir😢

[@manishajain1078]

114 one is wrong ans wil be -12.9

[@rosa-fr5fo]

Thanks sir 😊

[@anupamchaurasia2781]

Sir if you make vedios in Hindi that would be better.

[@nikkipatelvijaybhai2636]

Sir please make on video privious year paper solutions in physical chemistry 🙏🙏🙏🙏🙏 please

[@ManishaYadav-fk3sk]

Thanks sir

[@ekalavyaacademy599]

nice

[@chinkygangwar5967]

👍👍👍👍

[@juberchoudhury9881]

Sir, plz verify me

[@sahibsingh198]

Please check your facebook messenger 😊

[@manishajain1078]

114 one is wrong ans wil be -12.9