Moment Distribution Method for Sway Frames | Portal frames

In this video lecture you will understand how to analyze a simple portal frame with side sway using moment distribution method. Moment distribution method is an iterative method, in this lecture we will first find non sway moments, then sway moments and then combine both the results. Moment distribution method is a versatile method and can be used for continuous beam , overhanging beam, simply supported beam, portal frames, sway frames and various indeterminate structures.

[@mikexbox1]

Am i the only one who enjoyed the birds? Great video, thank you

[@souvik.fingtore]

The word" teacher" meaning define by ur teaching style and explanation & thanks fram JADAVPUR UNIVERSITY.....😍

[@shahidrahaman1325]

AGN sir searching ur location

[@mayuriassai7424]

This must be the most beautiful video that I've ever seen..... Beautifully presented.... 10/10 for this. Lots of love

[@sahilrooplall2970]

You made this topic very easy to understand. Thank you very much.

[@souvik.fingtore]

Thanks a lot for creating such a helpful video. U r doing great for students, keep going.

[@mixedgsforsscje3742]

Crystal clear explanation...sir

[@mthokozisimthembu7982]

Thank you sir. Nice explanation. I'm busy with exam preparations, it helped me a lot thankyou

[@emmyemtiyax8224]

It was fully clear satisfaction for me Nyc work sir How can i thanks u sir

[@DCBAonline]

Your kind words are more than enough to thank me.

[@annamalaisuresh5997]

Thank you bro, you made it simpler

[@indiramishra7013]

Thanks for all these "gyan ke moti" !!!

[@anjangaire6262]

Bohot badhiya explained🧨🧨💥💥

[@saninduteshan3656]

great explain sir. I got it on my first watch.

[@hariomchandra9048]

I think it is stiffness 4EI/L,not the relative stiffness because it isl/L

[@RR_official-wt8qx]

Thank you so much sir.... These video is helpfu for many students.

[@ahmedhyd867]

Thanks friend, the way you explain everything in detail is very nice, it is very helpful . Kindly solve the same frame but with hinge/pin support at both ends by KANI's method *****I have solved the same problem by KANI's method and the result matches to your moment distribution method....Thanks again for this sway frame MDM

[@naraharimanne5240]

excellent explanation sir

[@mbalimadonsela8305]

loved the video. omw it made things so much clearer

[@madhavreddy3489]

well done bro... thankyou so much .. kindly do SWAY ANALYSIS for SLOPE DEFLECTION METHOD and also KANI'S METHOD

[@marthinusdekock7089]

Thank you for the tutorial, brilliant

[@raysaha1893]

Sir thanks a lot.... Helped me in my test💜

[@subinas7333]

Well explained.. Loved your video

[@srinurao3327]

what about joint load 16KN at joint B..you didnt consider load 16KN at calculations of fixed end moments and at calculation of moment distribution..what is the concept of joint load? will it ignore? pls clarify

[@devgupta1217]

Formula for correction factor(x) is P+Qx =0

[@llendymanulat2659]

THANK YOU SO MUCH. GOD BLESS YOU PO

[@sreenithya6383]

Sir, What about the 16kN load acting at B, it's not included in the first step(while calculating fixed end moments in non-sway analysis) calculations

[@DCBAonline]

That load will not contribute in fixed end moments as it is at the end of the beam.

[@constanzagil9712]

Thanks mate, very helpful!

[@ayushvishwkarma1876]

Brilliant step by step description....🫡

[@discovernepal6830]

Tq for this knowledge video.what to do for the joint that constant 3 member.make video on this

[@dusaripraneethbabu7202]

Thank you sir understood perfectly 👍

[@shutterbeat5426]

Nice Explanation 👌

[@monir111monir]

Great video

[@misszas1396]

Sir there is a a sign convention mistake in your drawing you have mixed clock wise and anticlockwise moment directions ,thus it creates confusion.

[@dipendrakumardas5939]

Thank u so much..really.. It's been very helpful to me..😜😜

[@pramodredekar736]

Explanation is very good. But how you can decided the moments direction. On which basis. Plz rply me sir.

[@jbator10]

seems clockwise is negative

[@PS-te7qc]

Sir why is relative stifness 4EI/L & not EI/L as in your other videos of beams. I think 4EI/L is the formula for stifness & not relative stifness. Please reply

[@DCBAonline]

Actually you can take either 4EI/L when far end fixed and 3EI/L when far end hinged or you can take EI/L when far end fixed and 3EI/4L when far end hinged it will give you same answer.

[@PS-te7qc]

@@DCBAonline thank you sir

[@sagarmaniraut7490]

Clear explanation

[@raviraj7383]

amazing 😍😍😍😍😍😍😍

[@ADITYARAJ-gl9ox]

Very good video ❤️

[@yuvrajkumar6792]

Awesome sir g, but where is next lecture

[@munawarhussain7878]

awesome broh

[@naveen6893]

Sir here both P, Q force direction was same. What to do if directions are different? Should we take the ratio as negative?

[@mannenirakeshchowdary8513]

yes

[@C_O_LAIS]

if you arbitrarily substitute "EI delta" Value, then everyone will get a different final answer right?

[@DCBAonline]

Yes

[@ritamdas9114]

Sir... what would be the number of no. of iteration? Is there any criteria?

[@DCBAonline]

Generally 5 iteration should yield a fairly accurate answer

[@subakaranr.9252]

hy I have a doubt, all the end joints are considered to be fixed, only in portal frame or in any situations like, if we consider a simple horizontal beam????

[@raviakash2955]

The intermediate joint are considered to be fixed for all the cases(for the horizontal beam as well)

[@fasdffd4771]

Hi there. Can I ask you how to solve an indeterminate frame whose legs are not equal and have a support hinge. Thanksss. Any Idea could help me thanksss

[@raviakash2955]

Bro I have a doubt...for continuous beam you said that the relative stiffness is EI/L but now you are saying that relative stiffness is 4EI/L(for fixed far end)why???

[@DCBAonline]

See you can use either of these formulas 1) far end hinged =3EI/4L 2) far end fixed = EI/L OR 1) Far end hinged =3EI/L 2) Far end fixed = 4EI/L both set of formulas are correct in the first set 4 is take common.

[@raviakash2955]

@@DCBAonline thanks bro...got it

[@GAMMASTAR321]

hey can i know why the horizontal 16Kn force was not included in the FEM calculations in the beginning?

[@DCBAonline]

Because its not acting on any member. Its acting on rigid joint

[@Sully...]

Do we have to release if the end supports are simply supported in case of a beam?

[@DCBAonline]

Ashton Benjamin yes if ends are pinned than you need to release the moments.

[@chandanrajjoshi6257]

Relative stiffness for fixed end is EI/L and you have used 4EI/L while calculating...

[@ashmakarki1426]

no 4ei/l is correct

[@chandanrajjoshi6257]

@@ashmakarki1426 but how

[@chandanrajjoshi6257]

There should be EI/l and the value of I=4l then It is 4EI/L but not 16EI/L

[@joetube6208]

That is method for fixetion= 4EI/l And for fixed hinge =3Ei/L As const in this method

[@dr.j.thivya6916]

how can you assume H1 and H2 force directions

[@DCBAonline]

you can assume any direction but generally just see logically in which direction the frame will deflect and then draw H1 H2 forces as reactions.

[@PS-te7qc]

Sir,Would there be deflection at A due to sway force if end A was hinged?

[@DCBAonline]

If A is a type of support especially fixed or hinged then there is no possibility of translational deflection at that point.

[@sharadmanikpuri8016]

thank you so much Sir

[@tejaswinipatil4799]

Thank u so much sir....

[@gowrisankararao8827]

GOOD VIDEO

[@sremix2818]

What will be the sign of P/Q? + or -?

[@suravarapuharika5214]

You have found fixed end momend for MfAB as 9.6 but in the free body diagram you wrote 9.13 how is that possible

[@DCBAonline]

Because you have to use non sway moments for that and not fixed end moment

[@subinas7333]

What is the delta value substituted

[@Mighty3000]

can you do the same question in Kani's method, please??????

[@venkatkrishna7943]

What was the software you used ??

[@sailendranathpal8]

😊❤

[@kzero9714]

Any example for frame with bracing?

[@sajasy3563]

thanks very much

[@allarjun956]

sir why H1*5 moment positive at 12:10

[@DCBAonline]

Ap subliminals it is because H1 is causing a sagging moment.

[@mayuriassai7424]

mind nut because it's clockwise w.r.t B

[@Alma127]

Thank you very mucy

[@roham1981]

Thanks alot

[@UserNameEuouae]

Why is it that the sidesway moment became clockwise in 21:37 when it is supposed to be counterclockwise just like in 14:33. Illuminate my minddd huhuhu

[@DCBAonline]

It is shown considering the sign conventions

[@vishalchaudhari4866]

Sir -9.13 h toh voh anticlockwise hoga na?

[@baishya775]

Yes thankgod.. That doubt was eating my head. It should be anti clockwise

[@vivek9763]

I guess he assumed the directions of moment and mentioned them with +/- sign. You see he took all moments as clockwise with +/- sign

[@DCBAonline]

You can either show the moment with the correct direction and a positive value ot you can show the moment with negative value and its incorrect direction. The thing here is i have shown all moments to be clockwise but i have written their values correct with the signs

[@kalyanvenkatesh1431]

MFAB was -ve and MFBA was +ve in Non sway analysis. But you took both of them in the same direction. Please look.

[@TanveshDabholkar]

Although directions are shown same, but the values are written with signs in consideration.

[@kalyanvenkatesh1431]

@@TanveshDabholkar Oops, sorry, I didn't see the minus. Yes you are correct. Thank you 👍🏻🙏🏻

[@faizankamal6844]

Sir I need your help. Can you please tell me how to solve a frame having 2 or more storey and 2 or more bays by MDM? PLEASE SIR, I have been trying to look for it for many days but I haven’t found it yet. Please make a video on it or at least tell me the procedure to solve it. PLEASE DO ANSWER SIR PLEASE

[@DCBAonline]

It is a little bit difficult and lengthy process, the procedure although remains same finding distribution factors and other, i will try to make video but its difficult to get time these days out of other commitments of videos.

[@faizankamal6844]

DCBA online Please do make it whenever you get free time sir. I’m pretty sure it will be very helpful to many students and we will also get a clear picture of using this method on real life structures which usually have more storeys and bays.

[@dr.j.thivya6916]

thank u

[@fazelally1049]

can you solve a question where there is a arch resting on columns using a compatibility method

[@energeniq-sahilpatra7401]

Tnx

[@biswaranjanpradhan6248]

Q force ka direction to galat liye ho.... Its is towards left... Because h1, h2 both are towards left

[@BejjankiGaneshChary]

Tq

[@JM-lw1dr]

why is 4EI/L = (4E * 4I)/L?

[@DCBAonline]

Because moment of inertia of that section was 4I

[@JM-lw1dr]

@@DCBAonline yeah i noticed it a couple of hours after thanks man!

[@Sully...]

Please reply asap as I have exams tomorrow.

[@ImranKhan-qs6st]

Sir MDm method m overhang frame ka analysis ap ny n kea.plzzzzzzzz sir do it

[@amnakulsoom7214]

Have you gone maddddd??? I though id learn something but you dont know basic math, I m stopping at 2.59, like seriously 4EI =4E .4I like seriously what is this ... Its multiplication not addition or subtraction.

[@DCBAonline]

Woman are you idiot? Do you understand what 'I' stands for in 4EI/L, its moment of inertia of the cross section and that particular cross section is having 4 times moment of inertia as compared to a section having MOI of 'I'. So its perfectly correct numerical, go and check it with any software and before commenting mind your tongue. Think for a moment understand engineering and then comment.

[@ashokchoudhary4805]

Are method ko pura complicated bana diya yarr

[@knowledge-er2et]

Thanks a lot sir