Decibel (dB): What is dB, dBm, dBW, and dBV in Electronics? Difference between dB and dBm

[@nurbiyaablat4060]

Super helpful. Now I know what exactly decibel is. For my class, teacher just start using decibel in the graph without explain what it actually is. Like only want us to memorize.

[@noweare1]

I have always been kind of confused about decibels. You have made it crystal clear. Thank you.

[@shivankitss8396]

🔮

[@kippyjohnson]

Thank you for this very clear explanation.

[@sibgha985]

Your video clear my concept about 20bd thanks a lot

[@gangeshgunjan5953]

Thank you so much sir....very easy and understandable explanation.

[@ramakrishnauppala1497]

it is very simple way to understand the concept. excellent

[@happyhayot]

Perfectly clear, thanks!

[@sharondsouza1408]

Thanks for clearing the concept.

[@sugalimathrunaik5256]

tq u sir for this vedio now i have cleared my doubt

[@Zhexss]

Thanks, that was helpful.

[@VADroidTS555]

Thank you. This is very helpful.

[@amansinghbhadauria3574]

Nice explained. Thanks alot.

[@sadafsakib1453]

too much helpful video, highly recomended

[@147bshuvanganadas7]

excellent way u explain.....

[@muddassirghoorun4322]

Great delivery!

[@vikasgupta-hl9sq]

You Made it very simple for me

[@Melody-hm4xy]

Thanks this is really useful

[@PHOEBE_LOVELY]

well explained dude...

[@TechSouls-wn6jc]

excellent explanation...

[@dipalikadam5760]

Very helpful video!

[@dipubiswas8520]

Very Well explained

[@MYCOOLSUPPORT]

Very nice video.... Thank you please keep it up

[@TheUltrasEnd]

excellent explanation

[@palashmalakar2810]

Thanks a lot sir 🙏

[@shahidhameed5980]

interesting....very informative.

[@animalcare6278]

Great explanation

[@user-fe3lm1lb2q]

Спс бро .Я начинающий радиолюбитель и теперь я глубже буду изучать технику .

[@simozy4475]

thank you so much for the explanation

[@alsongadizo1692]

thanks and awesome work

[@bicboss4486]

thanks soo much, good explanation

[@roshinroy5129]

Thank you very much!

[@sciclepodcast4108]

cool explanation sir

[@greencoder1594]

Thanks for pointing out the *contextual difference* of the decibel (voltage, amplitude, … vs power, watt, …). Mathematically speaking, the *equal sign is formally used this way though:* *Power:* A/B = 10W/1W = 10log(10W/1W)dB = 10log(10)dB = 10dB = 1B *Field:* A/B = 10V/1V = 20log(10V/1V)dB = 20log(10)dB = 20dB = 2B

[@lolvivo8783]

I used to think prefix deci in dB stood for the log to the base '10'. But it looks it stood for metric prefix, ie represent multiplier 10 scale, not the base. But if deci is removed how do you say B; is it 'bels'

[@greencoder1594]

@@lolvivo8783 Correct 1 B = "one bel"

[@biswasuna3643]

Thank you so much sir ❣️❣️😍😍😍

[@rajeshkavyaparmar6206]

thank you so much!

[@umravsingh1158]

Good and nice explain

[@ManishKumar-vz2xm]

thanks a ton, buddy!!

[@phisitja01]

Nice. Thank.

[@vishvajeet7064]

Thank you bro

[@attamuhammad1229]

good one.....

[@dheerajkhanna7697]

I'm in love with this channel!

[@muhammadqasimsardar1527]

Thank you very much for Clearing concepts

[@zarsblackhorse123]

excellent explanation of difficult looking easy concept. Thank you. btw... P1 + P2= 10 + 3.162 = 13.162 mW

[@He.Who.Remains.]

In terms of decibel it is 11.193310

[@He.Who.Remains.]

In terms of decibel it is 11.193310

[@AshwaniYadavIIT]

@@He.Who.Remains. power will remain the same, it will not depend on reference

[@aruns_world]

@@He.Who.Remains. P= -18.806 dB

[@dotlinehub9329]

Thanks

[@ALLABOUTELECTRONICS]

Time stamps for the different topics covered in the video: 0:56 Decibel (dB) in electronics 2:15 Representation of Power Gain in dB 6:26 Representation of Voltage Gain in dB 8:40 What is dBW, dBm, and dBV? 11:40 dBm to dBW and dBW to dBm conversion

[@dhirajsavla7805]

ALL ABOUT ELECTRONICS what.is watts power in music amplifier

[@ALLABOUTELECTRONICS]

It is the unit of power measurement. Generally speaking, the amplifier with higher wattage produces a louder sound. (more amplification)

[@aravindanvenkatesh8836]

Bro will you share the video of total harmonic distortion concept

[@mohammedalkhalidi7147]

Thanks. I didnt out find how to convert dB to dBV? Can you please explain?

[@shubhammittal4993]

Please explain BJT, transistors...

[@drivesim2678]

Nice

[@amitahirwal1007]

sir how to measure unknown power of microwave x band in dbm

[@Eshaal1377]

sir i want to ask one question why zero watt can not be chosen as zero decibel level?

[@universalgenius1]

if the input power is -3dBm which suffers a gain of -4dB on insertion . What will be the output power? And if the outpower is equally splitted into 4 branches. What will be the output power per branch in dBm? Please help.

[@deepakdoer8507]

You cleared my doubt why gain in synthesiser always show in negative

[@premchanduvattikala9773]

Could you please explain about dbi

[@jackkabirpotpourricapture3062]

conversion of negative dbm to milliwatt?

[@divyaparameswarip9410]

Good

[@jettiteja5805]

P1=0.01W = 10mW P2=0.00316W = 3.16mW P1 = P2 = 13.16mW

[@karthikeyaprasadnapa8847]

how did 3.16 came ? log 5 is 0.698 right, So 10*0.698 is 6.98

[@KarthiMKM21]

@@karthikeyaprasadnapa8847 you should add that

[@andreanonali4557]

Well explained. I have a question: What happens if I add dB value of a transmitter and a dbW value? Can they be added?

[@ALLABOUTELECTRONICS]

If the reference is same, then they can be added. I mean if both represents the Power in dB then they can be added.

[@andreanonali4557]

@@ALLABOUTELECTRONICS ok thanks. I appreciate your work and the time you spend to help other people

[@manishamanisha318]

Why in voltage gain log of power gain is multiplied by 10? From where this formula is derived?

[@RimantasLiubertas]

"d" in dB stands for "deci", i.e. 1/10th. Log(A/B) gives you 1bel. For the decibel you need to multiply by 10.

[@MRPerfect-zr6mv]

@@RimantasLiubertas ohk. But what about 20. Why 20 is used for voltage gain??

[@umbertofreitas5918]

@@MRPerfect-zr6mv Because P is proportinal to U^2 (voltage raised to 2). This "2" goes multiplying 10 (that comes from conversion of bells to decibels). 2.10 log (V(out)) (for 1V reference voltage).

[@jackkabirpotpourricapture3062]

are we get direct mw from dbm?

[@bickyou4696]

mw = 10 ^ ( dBm / 10 )

[@szabojozsef7873]

Hello. I need explanation of what is dBm in RF communication. For example I have two RF Module. The Transmit Power is 14dBm.What dose this mean? After connection RSSI is -9 dBm.What dose this mean? Can you help me please?

[@ALLABOUTELECTRONICS]

dBm is used to represent the power in milliwatt. 14dBm means the power is around 25mW. When the power is less than 1mW then in dBm it will be negative. -9dBm means power is approximately equal to 0.125 mW or 125 uW. For the calculation, you can use the equation given in the video. Direct conversion calculators are also available on the web. You can also use them. I hope it will help you.

[@krishnaprasad1165]

i think so is that correct

[@bihariallinone4509]

Why are lower cut-off frequency and upper cut-off frequency called -3dB frequencies??? Sir please explain.

[@ALLABOUTELECTRONICS]

Because at that frequency, the output voltage reduces to 0.707 of the maximum value. If you convert it into the dB then Vo / Vin is -3dB. That's why it's called -3dB frequency. I hope it will clear your doubt.

[@mnada72]

My answer to question is 11.2 dBm

[@dilakshankamalathasan6070]

respectable sir please make video, that why are they using 3dB in many place. and how derive that 3db, as much as possible. really i couldn't understand that. thank you

[@ALLABOUTELECTRONICS]

Please check my RC low pass filter. There I have explained. 3 dB frequency is where the power becomes half or the voltage is 0.707 times the input voltage.

[@dilakshankamalathasan6070]

@@ALLABOUTELECTRONICS thank you sir

[@mdf1259]

Can anyone explain about in this video 11.18 1000mw to dbw is 0dbw ? Also dBm to mw?

[@ALLABOUTELECTRONICS]

1000 mW is 1W. 1W in dBW is 10 log (1W/ 1W) = 0 I hope it will clear your doubt.

[@mdf1259]

@@ALLABOUTELECTRONICS Thank you so much sir That convertion of dBm to mw?

[@priyansukushwaha5195]

What about current

[@jackkabirpotpourricapture3062]

13.16 mw

[@prathumnar9635]

sir, Why we are taking -3dB in LPF and HPF?

[@ALLABOUTELECTRONICS]

Because at these points on the curve, the amplitude is 3dB less than the maximum value.

[@prathumnar9635]

thank you sir

[@pksingh823]

It's regarding half power it should be -3db but according u r table it showing -6db , correct me if i m wrong....

[@ALLABOUTELECTRONICS]

The table is for voltage. The voltage becomes 0.707 times the actual value at -3dB. For power, it becomes half at -3dB. The equation for power is Power (in dB) = 10 log (Power in Watt/ 1W). For voltage its Voltage (in dB) = 20 log (Voltage in Volt/ 1V)

[@pksingh823]

@@ALLABOUTELECTRONICS got it thanks..

[@Zer-us4wq]

Anyone got the answer for the last question?

[@ALLABOUTELECTRONICS]

Let me know your answer here: If P1= 10 dBm and P2=5dBm Then P1+P2 = ?? Is it 15 dBm or something else?

[@amansinghbhadauria3574]

Directly addition to nahi hoga. I have tried in 2 ways but don't know it is correct or not . Pls give solution.

[@ALLABOUTELECTRONICS]

Yes, that is true. Direct addition nahi hoga. First you need to convert each power into mW or watt. And then you can add them. So, P1 in mW will be equal to 10 mW and P2 will be equal to 3.2 mW. So, P1 + P2= 13.2 mW And if we again convert it back into dBm then it would be equal to 11.2 dBm. I hope its clear to you.

[@drishtyrani6807]

sir plzz explain..i did'nt get it. how u get 3.2..plzz rpy

[@ALLABOUTELECTRONICS]

convert 5dBm into mW. In mW, it will be equal to 10^(5/10). If you calculate, it will come out around 3.16 mW. Or roughly 3.2 mW. Rest of the procedure I have already mentioned in the earlier comment. I hope it will clear your doubt.

[@drishtyrani6807]

oh..thanks a lot sir

[@-Rishikesh]

I don't understand why 20 for voltage and 10 for power P prop to v square So if v =10 Then log means p = 20 ? Please explain

[@vybefm8873]

P(out) = (Vo^2/Ro). P(in) = (Vi^2/Ri2), dB = 10log(Po/Pi) = 10log((Vo^2/Ro)/(Vi^2/Ri)) -> (if Ro = Ri) -> -> 10log(Vo/Vi)^2 => 20log(Vo/Vi)

[@neatpolygons8500]

B for? Begetables

[@tasnimulislamtaseen5207]

Intro music madhosh kar deta hain😂

[@dae3xt]

3.16mw

[@glowingfacestrust]

15 dBm

[@venkatarajasekharpatina5795]

45dBm

[@TruthWillSF]

p1,+p2= 10mw+3.162mw=13.162mw

[@karthikeyaprasadnapa8847]

bro, how did 3.162 came ?

[@TruthWillSF]

@@karthikeyaprasadnapa8847 I forgot all these things. I don't know 😁

[@MRPerfect-zr6mv]

Why 20 is used for voltage gain????

[@ALLABOUTELECTRONICS]

Power P = V^2 / R. So, when we replace P with V^2/ R then in the log, 2 will get multiplied with 10. And hence for voltage, there is a 20 in dB equation.

[@adnanmalik6703]

Needs correction at 3:09

[@ManojKumar-cj7oj]

P=11.16dB

[@claudiomejia6429]

I'm stupid I didn't understand nothing.

[@krishnaprasad1165]

13.162 is the answer

[@bestofbest8213]

Ans : 15 dbm

[@300pnl]

Talk slower please good video

[@anvitiu7278]

How to write 100dB =_______kw

[@ALLABOUTELECTRONICS]

dB = 10 log (P), for the power. For 100 dB the power is 10^10 W. Or 10^7 kW.

[@abrarshafi6780]

Sir i want to join ur whatsapp group

[@pulasaniaswini4253]

P1=10 dBm(gain) P2=7dbm (gain) Total=17 dBm sir plzz tell me it's correct or not

[@vinaykumarkv5830]

I think its

[@umbertofreitas5918]

@@vinaykumarkv5830 I also think it is the right answer. 10dBm ~ 10mW 5dBm (half of prior potence) = 10dBm - 3dBm = 7dBm Total potence in dBm is 10dBm + 7dBm = 17dBm Also ask you to say if this is correct. Thank you in advance!

[@babarmpa4653]

Bai Jan urdu ya hindi mein btatay to behter hota

[@FloofyTanker]

P = 15 dBm P = 15 - 30 = -15 dBW

[@rupalipatil173]

p1+p2=16.989

[@nobitech7235]

50dbm

[@brandsplanet4381]

Please explain why cats are so lazy.

[@eng.abdurahmanmostafanasr2987]

8:46

[@karthikvenkata6484]

(10+10^0.5)milliwatts

[@mizanrahman5632]

P(dBm)= P1+P2= 11.1933 dBm

[@mizanrahman5632]

not 10+5 = 15dBm

[@dipakbhalodia7155]

हिन्दी मे lecture लीजिए क्रूपिया

[@nitinverma2475]

Sir hindi me bolte to samjh ata

[@MANOJKUMAR-ve9qx]

40db+50db=90db is not correct. In db u cant add directly..

[@ALLABOUTELECTRONICS]

The thing is it's converted into dB so that the quantity can be added directly without involving any further complexity. If two quantities are in dB then they can be added directly.

[@tariqislam9388]

@@ALLABOUTELECTRONICS If two quantities are in dB then they can be added directly. Then why can't we simply add P1 and P2 to get P i.e. why is P=10+5=15 not true? Please explain.

[@ekremfidan6311]

@@tariqislam9388 hi, 40db+50db=90db is correct, because this is a system of two amplifiers in series and amplification can be represented as Pin * A1 * A2. P=10dBm + 5dBm =15dBm not true because we just want to make addition powers (not multiplication) (this is the key) to sum up, multiplication in normal scale is equivalent to addition in dB (LOGARİTHMİC) scale.

[@tariqislam9388]

@@ekremfidan6311 Hi. Thanks for your explanation. But I still do not understand this thing well. Apparently it seems easy but I think I have problem some where in the basics. Can you please tell what background knowledge should I have in order to understand this db, dbm etc thing. Thanks.