Derivative of a function using the Quotient Rule

In this video, I showed how to use the Quotient Rule for taking the derivative of a rational function

[@holyshit922]

sqrt(1+sin(x))y = cos(x) sqrt(1+sin(x))= cos(x)/y y' = -1/2 cos(x)/y and we have separable differential equation y'+tan(x)y = -1/2sec(x)y^3 Bernoulli differential equation Your function is particular solution of these differential equations

[@francaisdeuxbaguetteiii7316]

I hope you don’t forget me when you eventually do reach 250k :)

[@PrimeNewtons]

You are unforgettable ❤️

[@francaisdeuxbaguetteiii7316]

@@PrimeNewtons you too mr newtons ❤️, I watch every video for a reason you know

[@utuberaj60]

Very nice practice for the Quoteint Rule. However, we can do it faster by using the trig identity Cos X =Sqrt(1-Sin^2 X) = Sqrt{ (1-Sin X)* (1+Since)} which makes the expression= Sqrt (1-Sin X). Differentiating this is very simple and gets to the answer in one step.