Derive the Henderson-Hasselblach Equation

[@gibran8959]

I don't get what's the algorithm property that's making the split of two different logarithms

[@nazgulwraith2281]

thank you ... I forgot you need to flip the log when changing the sign and I was wondering why my calculations were wrong

[@thelittlemaster007]

One question sir. When the negative log is multiplied with (H3O) & (A-), the denominator (HA) should be come both for H3O and A- as a denominator, but you put only for A- , while multiplying with -log on RHS of the equation . I m mentioning my doubt at 1.40 mind of the video. Kindly help me out professor

[@smutib2863]

I think he fucked up somewhere and got a slightly different equation from what I have seen, but his heart is in the right direction

[@hisyamhasbi8257]

Isnt this a multiplication? So the denominator should only come for either h30 or a-

[@eliashowe8418]

It looks different because we're used to seeing pH on the left side of the equation, not pKa. Rearrange the equation so pH is on the left, and you will see that his derivation is correct.

[@favouronah1261]

Great video!!! Understood it at once Thank youuu🥰🤝

[@favourafinni]

Thanks so much, so simplified

[@DaViDsMoMmA11]

it's supposed to be pH=pka + log([A]/[HA])

[@thefenerbahcesk4156]

so many damn versions

[@diamonds5990]

@@thefenerbahcesk4156 I think that is why Henderson hasselbalch is just an approximation.

[@mohamudomar5828]

This is the right equation.

[@Hyerayuna]

That's bcs he wrote ([HA]/[A]) not ([A]/[HA])

[@brightbright4318]

is pH -logH+ or -logH30-??? 😔

[@kristinawashington1773]

Truly enjoyed the video.

[@jonqn07]

Thanks for explaining!

[@simranjoharle4220]

In this equation...why don't we consider the ions contributed by the salt?

[@chemistNATE]

If you are adding salt, I assume the question has you adding the weak acid and conjugate base directly. For example, acetic acid and sodium acetate. The salt brings the conjugate base of the acid (A- in the video's case) and it definitely contributes to the [A-]=[base] part of the equation.

[@simranjoharle4220]

Got it......can we also put it this way ......the concentration of ions furnished by the salt is way more than that produced by the acid , so we ignore the concentration of ions produced by the acid and directly plug in the concentration of the salt in the equation.....I was actually confused about how do u included the concentration of committee base as well as the salt in the equation....and ur explanation makes sense....thank u so much.

[@ProPlayer-ey2dw]

Thanks boi

[@kripashankarshukla4073]

Super helpful video

[@manarsaleh282]

Thank you very much 👌👌

[@lostxtwis]

The Bestt everr ,thanks🙌

[@jawardamara9103]

There was a little error though

[@efangnsan3074]

Thanks boss.

[@balarajbingi1733]

Good and thank you

[@jaiprakashnirala5288]

Tq so much sir

[@charleszack1329]

Is that a Canadian accent?

[@Дэни-д6ю]

Nah, sound American to me

[@WinkThatCouture]

I hear it too lol and I'm not even Canadian, mostly when he says "ouuuuwt"

[@pradeepkumarsrivastava6561]

Thanq so much

[@Дэни-д6ю]

Nice fingers

[@fetramuhammadfeysal1083]

U are like woooow