Deriving The De Broglie Wavelength

[@nellvincervantes6233]

Can you do that math sir? 2:00 hf = sqrt(m^2 c^4 + p^2 c^2) = mc^2 + pc ?

[@TheBrainFiller]

Oh yes thank you for that correction. What you can do is the square root of p^2c^2 and because m=0 in this case the answer doesn’t change

[@marcolee1382]

Amazing Video

[@mrslave41]

2:21 “The photon has no mass“ But we are talking about an electron. 😮

[@timetin]

Looks like what de broglie scribbled at a napkin while he was waiting for his food at a restaurant.

[@Goose____]

Thank you for saving my grades :D

[@maciej12345678]

2:07 how you get 2mcp^3 = 0? Right waving hand but i dont care derive IT from E = mc^2

[@БалжанУтетилеуова-й9ф]

thank you very much Brain Filler

[@drover7476]

nice vid bro

[@estevaogeraldoalvarobraz4907]

Please I have a doubt. Why mc^2 = 0? Thanks.

[@TheBrainFiller]

Although the de Broglie wavelength applies to particles with mass, it was derived for photons which don’t have mass. Maybe that’s something thing else that shows you that this isn’t really full quantum mechanics….you need the wave function and schrodingers equation.

[@2tehnik]

@@TheBrainFiller > you need the wave function and schrodingers equation. ~~which presupposes the De Broglie relation to derive~~

[@TheBrainFiller]

Ha yes, that’s a good point. But I think people often just call Schrödinger’s equation a postulate (motivated by pre-existing theory) and then develop theory from there.

[@sohomchatterjee9353]

​@@TheBrainFillerywa m2c4 was cancelled to derive it, and now it is being applied to matter, strange indeed, does it mean debroglie was wrong about the wavelength?