Determine the maximum intensity of the distributed load w

[@observer4322]

Even if the force at A wasn't calculated correctly, this video still was of tremendous help.

[@whitedancer5866]

Reaction A is not perpendicular to line AB, break A into x and y components and you get exactly 2.67kN/m given by solution manual.

[@craftaburger]

This is actually incorrect. The distance you found is NOT the perpendicular distance. If you do the calculations correctly, the perpendicular distance is 3+4cos30. Since this number and the 6.77 achieved in the video are so close, your answer will only be slightly off, but is still incorrect if you use this method.

[@oqhr]

I was about to write the same comment. I am not sure about it, but it seems incorrect

[@craftaburger]

alsogooraa my statics professor confirmed that it is

[@ryanvance1767]

Thank for clearing that up.

[@shlovaski8393]

Abbie Bush thank you soooooooo much for that ive been spending the whole day trying to disprove this only to read this comment, what a waste of time

[@alfredjrtovar1499]

Sir you did not do the A part correct. A is perpendicular to the bent part of the beam NOT AB

[@joeltshite5279]

that line AB cannot be perpendicular to Force A unless if you talking about a third dimension

[@mmast1898]

4:29 I know this video is 6 years old but I am trying to study for a midterm and just want to tell you it is so fucking frustrating that you did not go through and solve for A. You state "plug in 4W for B" which there is no B but I assume you meant F as you drew an arrow to it, but even then you are left with an equation with two unknowns and no way to solve for W yet. Very frustrating and confusing to someone attempting to learn

[@RoyalRook]

If you just extend FA out then the perpendicular distance from FA to B would be 3 + 4cos30. Then counter clock positive ΣMB = FW(2) - FA*(3+4cos30) = 0

[@JoeMegolonyo]

How do you determine the largest intensity of the distributed load Wo that the beam can support to withstand a maximum shear force of Vmax=1200Ib and maximum bending moment of Mmax=600Ib.ft

[@JamesGG]

from -Fx2+Ax6.77=0 how do you get this equation? I dont get it. A force is not perpendicular to C=6.77. this is way too wrong

[@tommysapundjieff4496]

to find the perpendicular distance to calculate the moment, you must [3/cos(30)] + 4...lets say that =a.....next, to find the distance, distance=(a) * cos(30) so now you have the perpendicular distance to the force so m=F*distance

[@tommysapundjieff4496]

there are multiple ways to findthis moment, you just need to make sure that the length is perpendicular to the force.

[@tommysapundjieff4496]

i am actually finding it easier to just find the length in the x direction of the entire assembly and then finding the y component of the force to find the component since you will need the x and y components later.

[@tommysapundjieff4496]

i am actually finding it easier to just find the length in the x direction of the entire assembly and then finding the y component of the force to find the component since you will need the x and y components later.

[@mr.berries4060]

you got the wrong answer

[@ThisAccountIsNeverUsed]

says FinalAnswer, not RightAnswer

[@iya3952]

@@ThisAccountIsNeverUsed omg 😭😂😂😂😂😭😭😂😭😂😭😭LMAO

[@simontereszko2335]

this is correct, even according solution manual

[@Hlock84]

No its not.

[@kaursingh637]

EXCELLENT =THANK U SIR