Resultant of Couples Example

[@inchanyoon1477]

This helped me a lot. Thank you so much, and your voice is so good to hear!

[@ib_en]

Thank you I am study this ..... I am from Iraq

[@abdoooo4875]

You are the number one because I have been trying 2 hours and I’m stack in how I find the direction

[@ivoryas1696]

@abdoooo4875 Liking for the _painfully_ relatable statement.

[@SassynSaxy]

Thank you sooooooo much for this video. You really saved my ass on an assignment due in 3.5 hours. Love from Canada

[@yourbreakchannel6607]

Very well explained. Thank you (salamat) from philippines.

[@catgirlputin3147]

This was very clear thank you

[@robbiecrawford4345]

Love this voice omg,great explanation

[@Castrean]

Your explanation is great! Thank you so much for this, leaving a like and subbing.

[@irishrearcon2635]

Thank you so much. You should know how much I needed to learn this. Keep making great videos

[@SSSSKKKKTTTT]

Thank you from KR It was really helpful for me

[@ivytechengineer]

Thanks for a great video

[@m-course4260]

Thanks a Lot mam🙂 i like the way you teach and also your voice sounds lovely🙂

[@huzaifahmasood5876]

Very good explanation, thank you so much!

[@richardafari3981]

Hi teacher love your lectures

[@88GTA]

Easier for me to under stand that the further force in the couple moment from the origin will have a stronger moment and thus will decide the direction of rotation, vs imagining a steering wheel but this was a nice video to review right before my statics exam

[@azmanazurah4133]

I thought about the same! Btw, I have a problem. What if I have a couple of forces that acting horizontally (one to the right and one to the left) at the end of the beam. How to tell its direction? Thanks in advance!

[@88GTA]

@@azmanazurah4133 if the forces are acting parallel to the line of action there is no resulting moment, a torque/moment will only result from forces that aren’t applied parallel to the line of action for a straight beam.

[@azmanazurah4133]

@@88GTA OHhhh!!! Understood now! Thanks for the explanation! I really appreciate it

[@kingafahaene1159]

Please can you explain why your negative directions are clockwise and your positive directions are anti-clockwise?

[@brooke7721]

It's arbitrary

[@hudaaqeel3471]

Thank you for your video. I am a bit confused as to why you added the x-axis moment in your calculations? I thought we have "moment" only if the force is perpendicular to the arm of the moment. In this example, the force in the x-axis is in line with the point of action, so there should be no moment in that direction? Could you please explain, thank you very much again!

[@brooke7721]

The force in the x direction isn't exactly on the x axis, it's still offset by 1m vertical distance (1m perpendicular to x axis.) So it still creates a slight moment.

[@afiqaiman6828]

you are good on explaination.

[@arnavmahajan6101]

Which textbook is this question from?

[@janellajoydulatre2979]

Why did you used sin instead of cos in Mc2?

[@dumbledorrito]

Haha i thought that voice sounded familar, legit studying for EGB121 now and stumbled upon these videos lol

[@vegeta_toe6038]

Can you describe about the triangle you have created in the 5KN couple segment? It would be of very much help :)

[@matthewboxberger5932]

This reply is way late but basically it's just to relate the direction of the force vector without giving you the actual angle. For instance, tan of the angle between the vector and the bar would be 4/3

[@Hjmn711]

كيف جعلت 6sin وهي جيب الزاوية تكون 6cos30° على المحور x السالب كيف حسبتيها في sin الموجب والعكس صحيح بالنسبة للقوة المتعامدة معها؟

[@amalkardaly1652]

Thank you

[@sahirat9293]

Thanks ❤️

[@kaursingh637]

my lord --please solve =find moment of force F = 3i-2j +6k newtons acting at r= 2i-2j about R= 7k

[@shalsabilayeri1233]

AHHH THANK U SO MUCH!!

[@iamimran5880]

Thank you

[@Salman-jk6li]

really more helpful

[@cristhyandavidojedadiaz6293]

MUCHAS GRACIAS!!!!!!

[@aliabdulhassan4971]

Thanks a lot!

[@cedrickansus5428]

How did you find the separation distance 1 meter in the horizontal component?

[@theryderproject5053]

It's from the dimensions given on the diagram (0.5+0.5=1 m)

[@ilanSniping]

thanks

[@bennyni9361]

Shouldn't Mc1 be clockwise instead of anticlockwise?

[@theryderproject5053]

The directions are correct in the video. I recommend rewatching.

[@kaursingh637]

my lord - pls give lecture on virtural work

[@johnrexsalcedo]

Ma'am, why do we have to add the two 0.5 m ?

[@theryderproject5053]

We want the total separation distance between the two horizontal forces that form the couple.

[@amitshohan1378]

wow i am gratifying mam to you :-*

[@aradan4955]

I don't understand the cw and ccw if they are 90 degrees opposite direction then how can it have a spin

[@theryderproject5053]

You need to look at the pair of forces that form the couple. Together they will try to rotate either CW or CCW. I have other videos earlier in the mechanics playlist that discuss in more detail.

[@moniquetan8061]

@@theryderproject5053 im confused too😩

[@omarayyad4686]

I’m just confused about how could you determine it’s a clockwise or anticlockwise turn

[@theryderproject5053]

There are earlier videos in the playlist introducing this in more detail. Basically if you use a pencil (or similar) to represent your member. Use one finger to hold it at the point of interest. Use the other finger to push it in the direction of the force. Whatever direction it rotates gives you the answer.

[@adanriz1970]

@@theryderproject5053 how

[@adanriz1970]

wtf

[@fadhelalafoo6002]

Why is it negative if it's clockwise?

[@theryderproject5053]

That is the convention that comes from the "right hand rule". Rotation for these 2D problems occurs about the z axis which points "out of page". If you put your right hand's thumb in this direction, where your fingers point is the position direction for rotation.

[@mahmoudsalah9258]

@@theryderproject5053 if there is z axis then it is 3D not 2D so now I'm more confused

[@eng.3li613]

Thaaaaaaaaaaanks alooot♥️♥️♥️♥️

[@jikaikas]

Why can you seperate the forces

[@theryderproject5053]

Do you mean separate into x and y components? There are some earlier videos which cover that.

[@jikaikas]

Oh i just didnt knew that you could just seperate two couples and solve their moments normally I wouldve just solve the moment @ Point B

[@theryderproject5053]

@@jikaikas You could also do this too. If you're not given the distance to a reference point though you're probably better to do it the other way.

[@brandonclowes629]

Just so everyone knows, even though she is going backwards by convention for directions, the answer still comes to be the same as she stayed consistent. By the right hand rule, CCW rotations result in a positive moment as your fingers curl CCW and the moment points upwards (your thumb) along the z axis and produces a positive moment. CW rotations give a negative moments as you have to flip your hand upside down. You can even google this, CCW rotations are most commonly given as positive and CW as negative even though she showed the inverse during this video

[@HouseTre007]

huh

[@sofiadominguez5369]

「動画の音が良くない」、

[@dabooz8893]

That high pitch voice you use is very annoying but it's a good learning video nonetheless.

[@catgirlputin3147]

ure annoying as well, god bless

[@birdsunion3294]

go to hindi very enjoyable vids then