Differentiating hyperbolic functions containing sinh, cosh & tanh(x) | ExamSolutions

[@SS-pn7ss]

Thank you so much! your videos have been helpful for years!

[@robertgoodman2902]

I'm learning hyperbolics now in Further Maths and this video definitely helped. Thanks!

[@ExamSolutions_Maths]

You're welcome. Good luck with the rest of the course.

[@CrimsonDevil_Rias]

I just used this video to verify my differentiations. d/dx cosh(u) = sinh(u) du/dx Substitute u = ax: d/dx cosh(ax) = a sinh(ax)

[@skzislifefr419]

Thank you so much for this

[@tuneese2561]

So differential of sinh5x would be 5cosh5x ? all you have to do is bring the 5 to the front and change sinh to cosh? Is this the same with normal sin and cos?

[@ExamSolutions_Maths]

That is correct. It is not the same though for sin and cos.

[@damienrichards7216]

for sin and cos you do the same thing except when you swap from cos to sin you also swap the sign

[@leepatrick1756]

Thanks 😊

[@yooniekaye_1316]

wait.... I thought (4x³)² is equal to 16x⁵ since you just need to add the exponents.

[@yooniekaye_1316]

@Jamiu Muritala okay, do we need to use chain rule tho?or nah?