Differentiation : Implicit Equations (Using the Product Rule) : ExamSolutions

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[@ExamSolutions_Maths]

Because I was differentiating the 3x^2 with respect to x not the y^4. You only do that when you differentiate a function of y with respect to x.

[@norah7281]

Thank you so much Sir, you're the best!

[@ExamSolutions_Maths]

@ObviouslyRyan That's good. Thanks for your comment.

[@ExamSolutions_Maths]

@naruto2710 Yes, but I always suggest multiplying both sides of the equation by the fraction and therefore remove the option.

[@pinkette4gd]

you have helped me so much during GCSE and now my ALEVELS thank youu.

[@loganduong5056]

Damn old but gold thanks a lot sir!

[@Cyno7]

you've shown how chain and product rule can be incorporated with implicit differentiation. can quotient rule be used also?

[@ExamSolutions_Maths]

@pinkette4gd Thank you for your support.

[@AK476056]

Thank you for this tutorial.

[@lilianaenriquez5704]

Thank you this helped so much

[@ObviouslyRyan]

That was great, thank you so much.

[@Nathan-xp4rv]

When doing the product rule why didn't you have to write dy/dx for (6x)(y*4)?

[@Nathan-xp4rv]

Wait, was it because, for that part, it was the x term that was differentiated?

[@ExamSolutions_Maths]

That is correct.

[@Nathan-xp4rv]

+ExamSolutions awesome thanks!

[@lifewithdylan]

ohhhh, was hoping somebody asked that question still

[@spag5296]

dang didn't expect you here

[@TheOmgOwnage]

Thanks G

[@mrantonioc3566]

how did you find the common factors??

[@TwistedMentality089]

cheers mate

[@igext]

Subscribed.

[@desirepirahde3986]

Its a nice video keep it up sir , thanks .sir we can i get ur past exam papers

[@aric7726]

It won't help you now, but for anyone else looking, they have exam questions in each topic here: www.examsolutions.net/a-level-maths/edexcel/c4-tutorials/#diff and you can get past papers from your exam board's webiste.

[@labibatahsin4873]

Will we lose mark if we don't completely factorise? Ex. That last part I left it as 2+ 12x^2y^3 whereas you done 2(1+6x^2y^3)

[@ExamSolutions_Maths]

I would doubt it. However, factorising is always a good habit to look for as it can often simplify things.

[@Successful2o12]

2:50 ...... (3x^2)(4y^3) dy/dx + (6x)(y^4) why didnt you add dy/dx after (y^4) as well or why didn't it go there rather than after 4y^3. thanks

[@samyuktaamsarajan7409]

8 years later i have the same doubt

[@al-anoud-123]

I have got the same answer but with opposite signs ! Does it matter ? Thank you

[@ExamSolutions_Maths]

+‫العنود محمد‬‎ Can you write down your answer and I will be able to tell you.

[@al-anoud-123]

+ExamSolutions So I've got dy/dx = (6xy^4-3x^2-5) / (2(-6x^2y^3-1)) it's the same but the signs are different

[@ExamSolutions_Maths]

+‫العنود محمد‬‎ That's okay then. If you multiply top and bottom by -1 you will then get my version. The reason you got your version I suspect was that you collected the dy/dx terms on the left hand side as opposed to me collecting on the right hand side.

[@al-anoud-123]

ExamSolutions cool .. Thank u ^^

[@TrexieBerna]

Whats the derivative of 2y?

[@ExamSolutions_Maths]

If it is with respect to y then it is 2. If it is with respect to x then it is 2 dy/dx