Differentiation of Functional Relations | JEE Maths Lectures by Ghanshyam Tewani

Buy JEE Maths video lectures : Call 07814166606, 0172-4280095, Visit our website www.tewanimaths... Prof. Ghanshyam Tewani is author of many books on IITJEE mathematics published by worlds one of the most renowned publisher CENGAGE LEARNING. These books are appreciated all over INDIA and abroad. These books are now one of the top selling books in INDIA. Some books authored by Prof. Ghanshyam Tewani are 1. Algebra 2. Coordinate Geometry 3. Trigonometry 4. Calculus 5. Vectors and 3-D Geometry Prof. Ghanshyam Tewani has experience of 15 years for training students in Mathematics for IITJEE and other competitive examinations. He has worked for four years for FIITJEE Ltd., Delhi , the renowned name in IITJEE coaching. He is a rare genius, acknowledged as one of the best national level teachers in mathematics. His intense and concise lectures are aimed at clearing the student's fundamental concepts in mathematics and at the same time, laying a strong foundation for better understanding of complex problems. A man of uncommon devotion, he leaves no stone unturned to help out needy and deserving students. Every single word he speaks is weighed, for he believes in precision. In his own words, "For me each student counts, each one must learn to the best of his / her capability." Being a perfectionist, he doesn't tolerate even a minor error. It is not surprising that the best & most brilliant of student community hold him as their ideal and an adored mentor. Our Mission To develop a strong base with deeper understanding, and strengthen theoretical and applied dimensions of mathematics. To equip the students with a set of conceptual skills, intuitive tricks and fast methods to make them more confident and consequently expel the baseless fear of mathematics. (Buy iitjee videos : Call 07814166606, 0172-4280095, Visit our website www.tewanimaths.com)

[@shivanshnigam4015]

-Teaches amazingly -Leaves Absolute Gigachad

[@abhrasnataray8098]

Legendary teacher ! Hats off !!!

[@vaidikjhawar3475]

Truly a legend.. his books are god books for jee awesome

[@tushargoyaliit]

Sir plz make proper playlist of videos By chance we found this video It is very awesome

[@gtimeducation]

Check following playlist : kzbin.info/www/bejne/oKaan599eseqepY kzbin.info/www/bejne/mGOmnoR-Z75sf6M kzbin.info/www/bejne/jIKWqWZrpa6tjtU kzbin.info/www/bejne/jYLReaNmr9mjbJY kzbin.info/www/bejne/gJ7bZIOlr6ekl9U

[@tushargoyaliit]

Ghanshyam Tewani JEE Maths Video Lectures Sir plz make maximum videos till jee advance 2018

[@Dropped2024]

the author of legendary books....G.TEWANI

[@manishmadan5543]

Awesome lecture, you have discusses about amazing tricks that hardly any teacher does!

[@adityayerram8129]

Sir I think I got an easier solution for 3rd question: g'(X)=g(y)g'(x-y)---- eqn 1 X=0 and y=3 a=g(3)g'(-3) Now in eqn 1 substitute X=y g'(X)=g(X)a Hence g(3)= g'(3)/a Therefore g'(-3)= a²/b

[@protyaydeepshee]

Awesome mathematical manipulation techniques😃

[@aditipatil119]

Sir at 15:30 We can solve the que. without actually finding the fxn .. Sir after first derivative... We can put x=3,y=3 ...and v can obtain g(3)=b/a... Then we can put x=0 and y=3 And obtain g'(-3)=a*a/b Very simple and easy....

[@shang_chi4651]

Bro its really wonderful that you found an easy method by some mathematical manipulation to solve the question.but it is not always going to be so easy that you will be able to solve by these kind of manipulations .This is why sir has shown us a general method of finding the function itself and calculating derivative afterwards.

[@mathscreative4548]

Sir apna pura lecture initial se dal dijey

[@ultrasonictycone2140]

14:38 Doing this by differentiating and substituting 1. x=0 and y=3 2. x=3 and y=3 and solving the two equations would make the question much shorter

[@pranit1802]

Sir surjective injective functions pe video banaiye. Really need it.

[@tariqkhan-dj5sq]

Sir inverse functions for the different conditions ka derivative please

[@MdAsif-ym3uk]

Thanks a lot sir...❤

[@naraharimv]

Sir your teaching is extraordinary and exceptional, please make proper playlist of your teaching videos

[@rajravi9549]

thanku....so much sir...it is helping us alot 🙏🏼🙏🏼🙏🏼🙏🏼huge respect for u 🙏🏼🙏🏼

[@dikshajain8695]

Legendary lecture....👍

[@nournote]

At 15:45 I wonder wether it was necessary to prove that g(x) > 0, for every x, in order to be able to divide by g(x) and then write log(g(x))? Any idea?

[@Ayush-Bajpai]

very good explanation thanx sir

[@Aman_iitbh]

at 47:34 its holders inequality

[@reeshav4955]

at 45:38, the function can be linear for some region and be non linear for other right? Like, say a piecewise function, how can we say that f is always linear?

[@siddhartharaja9413]

We can't have non linear function(piecewise) since f((x+y)/2)=f(x)+f(y)/2 must hold for all x,y €R ,in case of non-linearity at any point ,the given condition gets invalid ,hence only linearity is possible!

[@sureshmeena-wk6pl]

Thanks sir

[@digamber70]

Very very helpful veidieo thank you sir

[@vnikhil5844]

excellent video for differentiational functional equation

[@everythingatonce6417]

In the case you don't know he has written cengage book series

[@shang_chi4651]

A wonderful lecture as all your video lectures .sir its really a pleasure to learn from you.thank you so much sir

[@ishan__001]

✍️✍️✍️ enjoyed it

[@mohitsawane6241]

ur God for us sir !!

[@abhinavsharma1175]

How f'(x+y)=f'(x)*f(y) Rather it should f'(x)*f(y)+f'(y)*f(x)?

[@paulbinu3537]

f(y) is treated as a constant. Y is taken constant, hence f(y) is a constant

[@nidhitiwari6325]

Very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very thanku sir..

[@pranav_sutar]

15:25 sar if you have assumed to be constant ,then how can you put y=x , where x is a variable.

[@banothjawaharlal6127]

Excellent

[@pramilachhetri2847]

Great teacher

[@AbhimanyuKumar-zu9yn]

Very nice and helpful

[@KuldeepSingh-lg5bh]

चरण स्पर्श सर् आप केवल students का ही भला नही कर रहे मेरे जैसे लांखो teachers का भी भला हो रहा है, मैं सोचता हूँ सर् मुझे आपका 5 प्रतिशत भी आ जाये

[@banothjawaharlal6127]

U r awesome sir

[@itsadityagupta2110]

Thank you veryyyy much sir

[@Hemant-Singh-31dec]

Great sir

[@pritammishra3360]

thnx sir very much

[@ArunKumar-vu5xe]

Sir i bought cengage book Of maths And got the byju cover page and not got the online access of book What could I dooo

[@kunjarora5126]

At 22:18 how can we differentiate without knowing that the function is continuous and differentiable?

[@nidhitiwari6325]

Sir at 44:22 both are f(x1+x2/2) generate from same equation thus why you take different value at different place

[@Dilip077]

Jensen's inequality

[@therockstar8201]

Is this G Tewani, the writer of Cengage Mathematics for JEE ADVANCED? 😱

[@gtimeducation]

The Rockstar Yes

[@therockstar8201]

@@gtimeducation Oh my god. Really thankful to you sir. I don't know how I'll perform in this JEE, but I follow your book. Awesome content.

[@manoharhedaoo1604]

Thank u sir

[@trisanjitcreation786]

I want to buy your solved book of advanced jee

[@humanhuman9228]

Sir is this sufficient for jee advance ?

[@varundixit6426]

No

[@Ravi-tq7mv]

20

[@pramilachhetri2847]

Best teacher ever

[@shivanshutiwari5646]

Sir first derivative method ke bina bhi sare qu ban sakte h kya

[@gtimeducation]

Shivanshu Tiwari Not all but some of the questions can be done by direct differentiation

[@shivanshutiwari5646]

Sir question no.-5 ,28:00 kisi dusare method se ban sakta h kya (mtlb kisi logic se).

[@omkarpatil3178]

brand

[@trisanjitcreation786]

Se

[@rudrapratapsingh8904]

Content is good. But pronunciation is little erratic. Derivative is pronounced as f’ (f primed) and not f dash.