Matrices Ex. 2.1 Part 3 Elementary Transformations | 12th New Syllabus 2020 Maharashtra | Dinesh Sir

[@tanushri130]

Question no 9. answer is in my way = Let A = [1 -1 2 2 1 3 3 2 4 ] R2 changes to R2- 2R1 A ~ [ 1 -1 2 0 3 -1 3 2. 4] R3 change to R3- 3R1 A~ [ 1 -1 2 0 3 -1 0 5 -2 ] R3 Change to R3- 5/3 R2 A ~ [ 1 -1 2 0 3 -1 0 0 -17/3 ] is an upper triangular matrix

[@jmvpianoflute3584]

di hume column tranformation karana hai but aapka try bhi sahi hai

[@madhukarahire6046]

@@tanushri130 di im the same one i comes to know the reason behind your answer

[@jmvpianoflute3584]

How the last step is taken? As in third step you perform R3-5/3R2 then at the a33 position there should be -2-(5/3)*(-1)=-2+5/3=-1/3 plz Explain

[@jmvpianoflute3584]

we can also use the operation in last 3R3-5R2

[@Trending_star555]

But there is condition that we have only do transformation of column

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Apna maths aalg h shydd yeh question toh hai hi na ex2.1 me

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[@prasadjangam4161]

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[@statusmaker8784]

Question no. 9 ans in my way =Let A=[1 -1 2 2 1 3 3 2 4] C1 changes to C1 -C2 Now A=[2 -1 2 1 1 3 1 2 4] R3 changes to R3-R2 Now A =[2 -1 2 1 1 3 0 1 1] C2 changes to C2-C3 Now A=[2 -3 2 1 -2 3 0 0 1] R2 changes to R2 - 1/2R1 Now A=[2 -3 2 0 -1/2 2 0 0 1] Thank you 🙏

[@Rishikesh7892]

Thank you 🙏

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Thanks❤

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Thanks you 👍

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[@sjha2516]

tum pawan wagh se v padhte ho naa.

[@sjha2516]

ek baat bato ki hum kya transformation mai multiplay nahi kar sakte hai kya...ya bas plus , minus he bas....

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Every thing can be sacrificed for truth, but truth can not be sacrificed for anything..... Thanku so much dear sir. 🥰🥰🥰

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very nice quote but I believe not everything must be sacrificed for truth, it depends on your perspective of life

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[@roshanbari6395]

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[@Onlysv]

Your smile letting entire lecture easy :)

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Scored more marks than my crush😅

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[@sketcllion8090]

Sir i have a doubt in Q7 .......... Can we take -3C1 instead of R2---›R2-3R1 Plz reply sir 🙃

[@Dreamcricket24Gamerz]

Yes👍

[@shahidshaikh3216]

It not possible guys if we do so we end up with -9 instead of 0 in the position of 3( i.e. bottom left in the question Q7)

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[@DarshanB18]

in Q no 9 insted of C1 - 2C2 are we able to use C1 - 1C2+1

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Thanks sir aaj toh me tution main ye 2.1 ka 9 Q dekh kar dar hi gya tha ye video dekh kar mera pura daught hat gya. Thanks sir😅

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Bhai/behenji pls yebatao ki sir ish saalka syllabus ke bajaye purane/old sylabus ke videos hi kyu dalte hai

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[@MyDineshSir]

Thanks and welcome

[@chintu85416]

Sir ha 4 me aise bhi kar sakte he C1----------->c2×c1. Ye correct hai kya

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THANK YOU SIR FOR SUCH A EXCELLENT EXPLAINATION 👍🏻👍🏻👍🏻

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Sir aapka jo 1 hour ka video jo dekha hoga wo sare sums khud se solve kar lega love u sir ❤️❤️❤️and thanxx

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By solving 1 question from row transformation and same question solved by column transformation the resulting answer can be same?

[@pratikpadole9324]

🙏🙏 गुरु ब्रह्मा गुरुर विष्णु गुरुर देवो महेश्वर गुरुर साक्षात परब्रह्म कोटि तस्मैय श्री गुरुवे नम 🙏🙏🙏 ❤️ Thanks so much sir ❤️

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[@Aryangaming-xo3yf]

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[@RSH-RAYYAN-YT]

Sir last wale zero ke liye [R1×R2] bhi kar sakte hai (-1×0=0) direct zero ho jayenga

[@SadhanaDwivedi-sq5ys]

sir in Q seven , for making it upper triangular is it allowed to change other elements of matrix like u did ?

[@MdIbrahim-sj1dw]

27:42 sir C1 multiply by C2 bhi kr skte h na??? plzzz reply me

[@shaikhareeb6713]

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[@Trending_star555]

Sir in question no 9th in last we have taken C1>4c1+C3. Sir can we do multiple c1×c2 then also we will get 0 ex: -1×0=0

[@MyDineshSir]

No

[@Trending_star555]

Sir we can do multiple of columns

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[@vigneshmurugaveeran7598]

Sir, we can use are not in 9th sum c1--> c1-2.c2, c2-->c2+2.c1, (c1-->c1.c2)

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[@umagupta9898]

Ques no.9 by column tranformation by me. =Let A = [1 -1 2 2 1 3 3 2 4] C2 changes to C3 - 2C2 A= [ 1 4 2 2 1 3 3 0 4] C1 changes to 4C1 - 3C3 A= [ -2 4 2 -1 1 3 0 0 4 ] C1 changes to C2 + C1 A= [ 2 4 2 0 1 3 0 0 4 ] Hence, proved. Sir, please tell this Right or not? I won't come the ans which ans you received....Plz Tell

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Ok

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