Since I tutor math, I appreciate that you consider what some teachers would like to see. "if your teacher ... divide everything by the largest power". It's important to be consistant with the classroom teaching.
@WiamWiam401Ай бұрын
I'm from Algeria, all of time i prefer to watch to your vedios that have a different ideas thank you for your efforts and continue in your way🥰💗
@skyethebi7 ай бұрын
9:56 you can also split the sum into two parts one with numerator n and one with numerator 2 and you can show that by the DCT both converge and therefore their sum converges. Obviously it’s important to note that you can only split up this sum because both parts of the numerator are strictly positive for all n in the sum and therefore you wouldn’t have an infinity - infinity case.
@izukanjisukwa89393 ай бұрын
7:16 it's suppose to be greater than or equal to 1/n
@qpgaming94684 ай бұрын
thank you for this!! ❤ I keep hearing "dumber little part" instead of "dominating part"🤣
@Elpsycongroo1130Ай бұрын
is 8:21 correct,? shouldnt it converge according to lhopitals rule??
@AyeAus5 ай бұрын
19:30 was pretty cool 😂
@holyshit9227 ай бұрын
Maybe some homework questions at the end of the video
@bprpcalculusbasics7 ай бұрын
Yes, 100 series! 😆
@brennans15637 ай бұрын
Sweet
@cluelesshands91297 ай бұрын
♥
@cyrusyeung80967 ай бұрын
From the limit comparison test, we know if a_n ∈ Θ(b_n), then both (sum of a_n) and (sum of b_n) converges / diverges. Similarly, can I say if a_n ∈ ω(b_n) and (sum of b_n) converges, then (sum of a_n) converges?