Direction of a point from a line segment

[@SauravKumar-xg4zr]

Another approach is- 1) Find slop of line AB then draw a line passing through P and having slop equal to AB. 2) check the x-intercepts of AB and line through P to decide left or right.

[@rajatmaheshwari916]

upload more! i am well aware from the death of a great teacher humblefool, but guys someone needs to continue his legacy... you (most probably his friends or colleagues) have to upload more content and regularly in order to show our respect and honour to him.

[@tityseptiani8584]

wait, you mean the guy who originally and mostly created the videos in this channel passed away already?

[@spacesuitred3839]

yea

[@venkateswarans1012]

No he is working in Microsoft

[@AMITSHARMA-oh1nq]

He passed away 5 years past

[@unknownman1]

@@venkateswarans1012 This guy passed away, but the other guy who also makes the video is working in Google

[@AbhayKumar-cz2fc]

@Manikanta The convention is like that . For point above line we take it as left so for that point cross product is positive and so on.

[@carmelraj2158]

Very good tutorial. Love it. Please upload more kind of programming with maths

[@NiazMohammad]

how to define left or right i.e. on what basis are we defining the directions? is it dependent of the Line direction? from POV of observer or from POV of the line itself?

[@dannywest749]

Niaz Mohammad At A looking in the direction of B, where does P lie?

[@wildpasco]

@@dannywest749 😮😮 Makes sense now, thanks !!!!

[@latifurrahmanzihad]

Nice explanation

[@harimanikanta1]

If the cross product is positive then point is right side to the line segment,negative then its left. But in the program its like this if(cross_product>0) return LEFT; else if(cross_product

[@NiazMohammad]

I assume he meant it is on the left of the line segment, but when he mentioned to the right it is to be from the viewers i.e. our vision perspective

[@lasttemplar7720]

//dot product version vec2 A; vec2 B; vec2 P; vec2 dir = B-A; dir.normalize(); vec2 dirNormal = vec2(dir.y, -dir.x); //right normal, in 3D use cross product float hyperPlaneDist = dot(A(or B), dirNormal); if(dot(P, dirNormal) > hyperPlaneDist) //right side else //left side //equals = on the line float Dot (vec2 a, vec2 b) { a.x*b.x + a.y*b.y;} //cos between 2 vectors

[@atiqorin]

At last I was able to watch the video. Great video. Keep up the good work.

[@wildpasco]

4:40 I have a question BOP is counterclockwise, so that means POB would be clockwise. Then how do you know how to chose BOP instead of POB?

[@wildpasco]

Quoted from a comment: At "A" looking in the direction of "B", where does "P" lie. Makes sense now! Thanks

[@krushnnabaviskar2170]

Completed ]

[@gauravbhardwaj7907]

How to find the convex hull of the points using the directions of the points.

[@xof8256]

Cauvery Emporium, Was this a snapshot from the map of Mysuru?

[@prabinpanthee1928]

nice content

[@atiqorin]

Something is wrong with this video. Its not playing. I tried to watch it ever since it was uploaded but it's showing error every time.

[@mycodeschool]

Thanks a lot ***** .. glad that it finally played for you :)

[@akshatrb]

Is this humblefool's voice?

[@Bread_Cheeze]

i wish this was longe like 20:00 more lol