Discrete Math 9.3.1 Representing Relations Using Matrices

Please see the updated video at • Discrete Math - 9.3.1 ...
The full playlist for Discrete Math I (Rosen, Discrete Mathematics and Its Applications, 7e) can be found at • Discrete Math I (Entir...

[@gvaidya1]

0:00 representing relations with matrixes 4:46 Properties of matrices - reflexive 6:04 Irreflexive property of matrices 6:33 Symmetric property of matrices 7:30 Antisymmetric property of matrices 8:27 Operations on matrices 15:30 Transitive property of matrices

[@saadafm]

This video will be of relevance for at least another decade on KZbin and I will be here 10 years later looking at my comment and remembering how grateful I am for this woman

[@sm1ley732]

cant we just fire my professor and bring you to my university to teach me ? :)

[@SawFinMath]

Sm1LeY ! Depends on where you are located :)

[@sm1ley732]

Asia - Palestine :D

[@SawFinMath]

Sm1LeY ! That’s pretty far! Going to have to stick with the videos!

[@vishwaksenreddydareddy3523]

Ma'am you inspired me to become a mathematian, I'll never forget you. You just changed me

[@voiceofthewolf3528]

Studying for the FE exam and I sometimes run into concepts that I didn't cover (or remember) in class. This video is super straightforward and explains it well. I also appreciate that the sections are defined pretty well, so it's easy to jump ahead if you feel like you have a handle on that section.

[@4leafclover202]

I’m also prepping for the FE exam, have you taken it yet?

[@saadafm]

Professor Brehm. You are so good at teaching its inspiring.

[@Arjit_IITH]

Quick and Understandable. Great work mam.

[@thilinadhananjaya6878]

My lecture just read slides that we never knew and, gave us the example question as an assignment .... No examples, No graphical explanations nothing... just read a bunch of symbols to us... Thank you for this lesson.....

[@SawFinMath]

Glad it helped! Be sure to check out the updated videos!

[@StoneColdMagic]

Excellent video. However, there is a mistake 17:38. You said that if it's symmetric then it is not anti-symmetric. However, that's not necessarily true. Consider the matrix that represents the relation R = {(1,1), (2,2), (3,3), (4,4)}. It is both symmetric and anti-symmetric. :)

[@SawFinMath]

Thank you for letting me know! I will fix the error in my updated video

[@yazeedalhokail1011]

An absolute Queen, Thank you so much

[@yoyosingh9801]

You are the best! You deserve the world for free and knowledgeable education unlike my professor who gets paid and doesn’t teach for life

[@SawFinMath]

Thank you! I get paid to teach, too, but I load these on to KZbin to help out students like you who want to learn the topics a bit more in depth. Don't forget that this is the old playlist/video. Any errors I made in these videos I fixed in the new playlist.

[@yoyosingh9801]

Kimberly Brehm thx for the info:)

[@sarahaaliya9459]

Thank you for sharing. This video helps me a lot.

[@ookami7726]

u just saved my life thanks

[@user-el7qr8pw1u]

thanks a lot , very help full

[@mk_scar-4485]

thank you , you helped me a lot :D

[@4leafclover202]

Amazing, thank you 🙏🏻

[@TheLordTech]

very useful!!!!!

[@Themostbeautyful]

Great video thanks :D

[@peerless3538]

Umm your videos.....😳💕.....really too useful and understandable....💫❣

[@allanonyango6447]

Thanks alot for the clarification

[@elajgorgui3364]

very useful, my english is not very strong (i speak french) but i understand very well your explaination... merci beaucoup madame

[@shakarak]

Great video! My professor also requires we know how to determine Asymmetric and Transitive matrices, so that would have been helpful to have as well.

[@SawFinMath]

Transitive is included in this video. For asymmetric, it must be anti-symmetric and NOT reflexive.

[@samimahassan1716]

thanks mam i was about to cry watching this nice video

[@akeelmedina7559]

Can you explain why we square a matrix to check for transitivity?

[@isaacsilva8787]

Hi, can you do Mg o Ms even if they dont have the same size?

[@zeyaddessouki890]

Thank You Sooo much

[@Atom-Mercury]

Thank you very much indeed.

[@chathurawimalasiri5920]

very usefull thank you

[@raghad-zn9xn]

THANK YOU SO MUCH!!!!!!!

[@mohibfayyaz4582]

You are doing Great Job Ma'm.. but please try to make a videos on solving problems of exercises in the end of topics.. Problems are far more difficult than examples, and i'm getting so much confused..

[@shriram6115]

thank you

[@sky-fly4067]

very very thanks mam

[@ersahyousuf469]

Superb explanation. Thanks

[@SawFinMath]

So nice of you

[@august-hg9vw]

in 16:33 , what if the Ms has an additional 1 but the (Ms)² stays the same, can it be called transitive?

[@KiranKumar-kd4su]

nice class

[@semagnyirdaw7745]

thanks

[@rawandrandomgameplay9672]

How am I suppose to find ''R''.... Is it already given? because I'm not able to see any kind of specific rule to find that. I went on wiki they simply used 'AxA' with A having 4 elements. R = { (1,1), (1,2) , (1,3) , (1,4) , (2,2) , (2,3) , (2,4) , (3,3) , (3,4) , (4,4) } and Relation R defined as ''aRb'' with no reminder. I believe there would be something that would be saying ''find R'' or It would be given. Correct me If I'm wrong. PLEASE!

[@ludyrod3557]

think yoooooou 😭😭

[@samratalha.]

You apologize ALOT! :p Nvm, really like the way you teach. 🌸

[@laibii264]

👌🏻👍🏻

[@got_shortlovers]

nice

[@SawFinMath]

Thanks

[@AarushUpadhyay5588]

Let A=\ 1, 2 , 3} and let R and S be the relations on A such that : M_{R} = [[1, 0, 1], [0, 1, 0], [0, 0, 0]] and M_{S} = [[0, 1, 1], [1, 1, 0], [0, 0, 1]] (ii) M R - 1 (iv) MROS Find: (i) M * R' (iii) M R cup S Please provide its solution 😢😢

[@asifimtiaz9310]

thank you