Do You Know Functions? Take This ALGEBRA POP QUIZ and Test Your Math Knowledge!

[@panlomito]

Crunshing a tough quadratic equation 12x² + 17x + 6 = 0 and found an easy way to solve: 12x²/12 + 17x + 6.12 = 0 or x² + 17x + 72 = 0 with 72 = 72.1, 36.2, 24.3, 18.4, 12.6, 9.8 with 9 + 8 = 17 So (x + 9) . (x + 8) = 0 then divide with 12 (x + 9/12) . (x + 8/12) = (4x + 3) . (3x + 2) = 0 so x = - 3/4 or x = - 2/3

[@coolkitty2075]

Was nt sure how to do these, but I can now. Thank you x

[@Stylux-z1p]

f(x) = x² + 1 inverse -> y = x² + 1 x = y² + 1 x - 1 = y² √(x - 1) = √(y²) y = ±√(x - 1) Find the inverse : flip the (x, y) pairs to (y, x) set of ordered pairs: {(1,3), (2, 5), (7, 9)} Inverse (y, x) ---> {(3,1), (5, 2), (9, 7)}

[@russelllomando8460]

woo hoo got all 3 thanks for the fun

[@laurendoe168]

A set of points is not a function. The number of functions that could produce this output is infinite.

[@cheriem432]

It seems to me that, in the process of "simplifying" a problem, you always make it more complicated than it originally was, before you finally solve it. I "simply" don't understand why you do this.

[@gillianrolland4305]

Yes using 10 words when 1 will do.

[@TonyFisher-lo8hh]

Starts out by inventing a whole range of terminology.

[@danolson1467]

Those who comment complaining that there is too much explanation need to consider a couple of things. The first thing is that this is not designed specifically for you, but rather is intended to benefit people with a wide range of math experience. The second thing is that these videos are meant to be seen as lessons on relevant math topics, not merely as instruction for solving a particular problem. I hope that helps.

[@mintusaren895]

One is square how many but same.

[@panlomito]

This is just a quadratic equation: y = f(x) = 1.x² + 0.x + 1 so a = 1 b = 0 c = 1 While a > 0 it will be a top down parabola Discriminator D = b² - 4ac = (0)² - 4 . (1) . (1) = 0 -4 = - 4 meaning there are no crossing with the x-axis or y = f(x) = 0 Combined with the positive a = 1 this means that the parabola is all above the x-axis. To conclude we can calculate the top of the parabola (xtop , ytop) with xtop = - b / 2a = 0 / 2.(1) = 0 and ytop = f(xtop) = f(0) = 1.(0)² + 0.(0) + 1 = 0 + 0 + 1 = 1 so top ( 0 , 1 ) Now we know the parabola is symmertical on the y-axis with the lowest point on ( 0 , 1 ) so crossing the y-axis at y =1

[@mintusaren895]

X number chahiye.

[@redblack8414]

Not impressed by the answer to the third question.