Very impressive, with great attention to detail (as usual)! I'm probably being over finicky here, but I think a couple of lines could have been added around 15:35. You showed earlier that if n³-2>n³/2 then n>∛4, but now you need the opposite implication. I noticed this detail because of your avoiding two-way implication signs.
@CliffStamp4 жыл бұрын
I often wonder who came up with those approaches, they are often simple when you see it (top is smaller, bottom is bigger, hence the same inequality will hold) but it isn't trivial maybe to come up with that approach.
@tomatrix75254 жыл бұрын
Love these
@sinan4988 Жыл бұрын
Is it false? (3n+4)/(n^3-2)
@tgx35294 жыл бұрын
0
@drpeyam4 жыл бұрын
Except it is not true for all N that N^3 -2 > N^2. For instance it is false for N = 1. And factoring our would mean to factor out n^2 from the numerator and the denominator, which people usually do in calculus
@tgx35294 жыл бұрын
@@drpeyam Thank you.Yes, N> max (7/epsilon;1).
@sidharathsharma61974 жыл бұрын
Sir please help me with this question. " If ∑uₙ be a divergent series of positive real numbers and sₙ = u₁ + u₂ + u₃ + - - - - + uₙ then show that the series ∑(uₙ / sₙ) is divergent.
@Superhumanconsciousness4 жыл бұрын
Use contaposition with cauchy theoreme
@sidharathsharma61974 жыл бұрын
@@aapeli9662 I saw this question in the book I am currently reading. Please help me prove that it is a falsehood , in case it is one.
@sidharathsharma61974 жыл бұрын
@@Superhumanconsciousness Thankyou so much bro!
@orlandomoreno61684 жыл бұрын
It could diverge or not, it doesn't necessarily follow
@Superhumanconsciousness4 жыл бұрын
If Un=1 then sum(Un) diverges => sum(Un/(U1+U2+...+Un)=sum(1/n)=hermonic series
@nullplan014 жыл бұрын
Dumb question, but... N has to be a natural number, right? Because in that case, N > cbrt(2) and N > cbrt(4) are equivalent to N >= 2. So N = max {2, ceil(sqrt(4/e))}.
@drpeyam4 жыл бұрын
Nah, N doesn’t have to be an integer, it’s n that has to be one
@Mateusz-Maciejewski4 жыл бұрын
@@drpeyam But in many textbooks the definition of limit involves N that has to be a positive integer. This is of course equivalent to the definition with any N and is justified, since we deal with natural numbers (indices). If so, we need to use one more condition: N>=1 and use either ceil(sth) or floor(sth)+1.