Dirac Delta Derivative

[@ReCaptchaHeinz]

"It would be interesting if there's a physical significance for that, but, I do not care"

[@andresromero1356]

Maths in a nutshell

[@quinnculver]

Contradiction in terms?

[@melanyponcedeleon2870]

Hahahh

[@ReCaptchaHeinz]

@@melanyponcedeleon2870 la mejor frase de la historia 😂

[@JensenPlaysMC]

Yes there Is, in finding the charge density of the hertzian dipole.

[@statebased]

I love this as it give a glimpse of how the world looks “at an instant”.

[@mohammedal-haddad2652]

I remember reading this derivation in a signal processing book years ago and I forgot it. Your presentation makes it unforgettable.

[@gajrajsingh51]

Reading this sem in Signals and Systems!

[@ManderSeis]

There is a physical significance in this, I just learned about this in electrodynamics :)

[@martinibarra4903]

what is the physical meaning of this ?

[@tylerwu601]

It represents a perfect dipole

[@mariomuysensual]

@@tylerwu601 what

[@aliexpress.official]

@@mariomuysensual when you talk of a point monople, meaning a charge distribution that is concentrated at a point (like an electron) you can represent it as a dirac delta distribution of charge. (Or charge density). A dipole is a configuration of 2 point charges of opposite charge, very close to each other. The dirac delta derivative is a function that models such charge density. You can understand it better when you consider the delta function as the limit of a very narrow Gaussian. (Look at wiki)

[@Marion89gr]

@@martinibarra4903 when you apply a load L of the form L = δ(t) to a structure, then every frequency of the structure will be excited

[@mathwithjanine]

I

[@JorgeMartinez-pc7so]

Just here to love the dropping-mic moment of 'it would be interesting if there was a physical meaning for this but I do not care'. As a physicist, I accept this statement uwu

[@danielmccomas9268]

I Had your Class at ASU back in 2021. I knew you had a channel, but I never expected that one of your videos would help me with my work down the road, but I'm very glad I was wrong. Thank you for uploading this video it was very helpful, probably saved me hours of internet research.

[@drpeyam]

That is amazing!! Glad I could help :)

[@jamesbentonticer4706]

Notice how many notes he uses in each of his videos! Very impressive.

[@mikhailmikhailov8781]

d/dx is anti self adjoint and so -id/dx is self adjoint, which is the momentum operator in quantum mechanics in natural units.

[@SKARTHIKSELVAN]

Your concepts are very useful in understanding electromagnetic communication concepts. Thanks for your efforts.

[@Breggo1]

The cold hearted Master Peyam. 3:55

[@LydellAaron]

Beautiful mathematics. Rotations or oscillations come to mind.

[@azhar07464]

Nice video. Very informative. Keep it up ❤

[@thomasborgsmidt9801]

Great video - only flaw is: I have no clue what a Dirac Delta is! - sounds like an unsuccessfull aeroplane built in a tunnel......

[@jagatiello6900]

You can see it as the derivative of the unit step function

[@الفيزياء-ب2ي]

هذا جميل حقا يا دكتور بيان (:

[@blackpenredpen]

The thumbnail reminds me of yogurtland.

[@drpeyam]

Yogurtland 😂😂😂 I used to go there every Friday during undergrad and regretted it every time! Those cheesecake bites tho!

[@Ither1023]

I love you maaaan , tysm 😭❤

[@FaerieDragonZook]

This also allows you to show the Maclaurin Series as an operator.

[@rikhalder5708]

Like Probability distribution and gamma function

[@a_llama]

man this makes me nostalgic

[@mokouf3]

In the theory of electromagnetism, the first derivative of the delta function represents a point magnetic dipole situated at the origin. Yes, it already has physical significance.

[@jafetriosduran]

And can be extended to fractional order derivatives using double convolutions

[@enriquesahidtenoriorodrigu8979]

"it will be intersting if there´s a physical significance for that, but...I do not care" words from a mathematician

[@drandrewsanchez]

What are the notation? I thought it was a vector at first

[@drpeyam]

Functional applied to a function

[@drandrewsanchez]

@@drpeyam i see. thanks!

[@toaj868]

A lot of times when these kinds of definitions are extended the operator in question is often treated as being multiplied with the input (function, variable, etc). Is that the case for any operator?

[@drpeyam]

No not always true. For the Dirac one you don’t multiply

[@toaj868]

@@drpeyam But you used integration by parts which is for products of functions to define the dirac delta derivative. So in some sense you're treating as a 'multiplication' right?

[@drpeyam]

It’s not a product though

[@toaj868]

@@drpeyam Yes of course.

[@ramanunnikrishnan7354]

finally I get what Dirac Delta means

[@peakpersona-yash]

🔥🔥🔥 I like it.🔥🔥🔥🔥🔥👍🏻👍🏻🔥🔥👍🏻👍🏻

[@veronicanoordzee6440]

@ 3:51 By making this statement, you only show that the only reference point for mathematics is physics. Why would you make the statement otherwise?

[@ajiwibowo8736]

Next why the derivative of signum function is 2*diracdelta

[@diegoffa]

Cool

[@SuperYoonHo]

∫🏆🏆🏆🏆🏆🏆🏆🏆🏆🏆🏆🏆🏆🏆🏆🏆🏆🏆🏆🏆🏆🏆🏆🏆dx

[@themathguy3149]

Stop trying break maths Dr. Peyam 🤣 or else i'll will have to call the math police to show you the chain (Rule)

[@bfnnyelf]

hello! :)

[@jamesbentonticer4706]

Good morning

[@drpeyam]

Hi! (:

[@soutriksarangi5580]

I bet u learnt this in physics class, not math.

[@drpeyam]

Actually in a math class! I haven’t taken physics since 12th grade

[@marccox8977]

@@drpeyam the world of Physics beckons you sir, consider that the function is named after physicist Paul Dirac who predicted anti-matter before it was discovered .. in fact I hope to use the math you demonstrate here to model negative energy and possibly relate it to anti-matter, so Thank *You* for your insights and encouragement sir 👍😊

[@drpeyam]

I hate physics, sorry 😂

[@matrixstuff3512]

Weak 😂😂 also should have made the connection that Fourier transform at 0 is the average of the function

[@drpeyam]

Interesting

[@matrixstuff3512]

@@drpeyam also, hope you got the joke about weak derivatives