3 Properties of Laplace Transforms: Linearity, Existence, and Inverses

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Dr. Trefor Bazett

Dr. Trefor Bazett

Күн бұрын

Пікірлер: 55
@shemsnow3711
@shemsnow3711 3 жыл бұрын
Man I would be so screwed without these videos. Thanks Dr Bazett!
@osebrainquestfoundation9631
@osebrainquestfoundation9631 2 жыл бұрын
I have found the simplest way to solve inverse of laplace transform. Thank you for the impact
@1-10-1-4
@1-10-1-4 3 жыл бұрын
bounced here from the calculus III playlist. very beautifully taught, but was expecting some visualization and real-life examples same way you did there. still amazing nonetheless ♥ thank you a lot
@africatothetop3366
@africatothetop3366 Жыл бұрын
I really loves his explanations, who else was deeply focused to the extent of hearing the ambulance voice @ minute 3:49 - 3:53😂😂😂
@MohamedOmar-z1s
@MohamedOmar-z1s Ай бұрын
I need you to inteoduce the proof of the inverse existence in the videos to come and big thanks for your effort!
@prideolea
@prideolea 4 жыл бұрын
I love you broski. Thank you for these videos.
@saadalabbad5484
@saadalabbad5484 3 жыл бұрын
Great channel, definitely deserves subscribing
@DrTrefor
@DrTrefor 3 жыл бұрын
Thank you!!
@continnum_radhe-radhe
@continnum_radhe-radhe 2 жыл бұрын
Thank you so much sir 🙏🔥🙏
@Rihanna8K
@Rihanna8K 3 жыл бұрын
I love this channel 😍
@theproofessayist8441
@theproofessayist8441 Ай бұрын
Where can I see a more elaborate write up or paper of the inverse proof for the Laplace Transform Dr. Bazett?
@ahmedghallab5342
@ahmedghallab5342 2 жыл бұрын
Thank you very much ❤️❤️
@doomslayer4276
@doomslayer4276 6 ай бұрын
Thanks! Short and precise
@stefano.a
@stefano.a 2 жыл бұрын
There is a problem in existence (minute 3:25): "s" is a complex number so it can not be greater than another number because the Complex set is not sortable
@DrTrefor
@DrTrefor 2 жыл бұрын
In the development of this series, I've been working exclusively over R. Yes, this can be extended to the complex numbers and these can be modified accordingly.
@stefano.a
@stefano.a 2 жыл бұрын
@@DrTrefor thanks for the reply. It would be very useful a video that explain these concepts in the complex plane; In my opinion it is the most confusing part about Laplace Transform
@Norm7264
@Norm7264 4 жыл бұрын
This is very clear and well presented, Trefor. It would be even better if you could improve the sound. Room acoustics are not good.
@austinfritzke9305
@austinfritzke9305 4 жыл бұрын
@3:50 do you mean "continuous and of* exponential order"? @4:28 I didn't quote follow that step. @5:25 the slide was a bit quick had to rewind and pause. Still a great video. Thank you.
@carultch
@carultch Жыл бұрын
Continuous means there are no sudden jumps, or gaps, or vertical asymptotes, or other problem points. "Of exponential order" means that the function grows no faster than an exponential function, such that multiplying by an exponential decay function makes the integral converge to a finite (i.e. non-infinite) value. For instance, tan(t) is not of exponential order, whereas polynomials are, no matter how high the degree of the polynomial.
@samridhyadav4794
@samridhyadav4794 3 жыл бұрын
Really Helpful...Thank you so much!!
@knowledge90s93
@knowledge90s93 10 ай бұрын
Which of the following sequences could represent the impulse response of a stable discrete-time system? k^2 (-0.65)^k 2^k ksin(k)
@j.o.5957
@j.o.5957 3 жыл бұрын
Linearity, existence and inverses. Seems like something linear algebra would love getting its hands on. Question to self: how do we calculate the inverse Laplace? I'm assuming I'll figure it out soon enough.
@spyrosmanolidis8516
@spyrosmanolidis8516 Жыл бұрын
2 years too late probably, but en.wikipedia.org/wiki/Inverse_Laplace_transform
@nyilynnseck
@nyilynnseck 4 жыл бұрын
Impressive presentation ! Could you show the way how you write and add these equations in videos too please?
@subaruyagami2327
@subaruyagami2327 4 жыл бұрын
Thanks, it was really helpful!
@DrTrefor
@DrTrefor 4 жыл бұрын
Glad it helped!
@usamabinmuzaffar692
@usamabinmuzaffar692 3 жыл бұрын
Not to be rude... But how many denoisers did you put on the audio in premiere? lol
@robertviragh6527
@robertviragh6527 2 жыл бұрын
very interesting overview, for the unique answer on getting inverses, for practical inversions how precisely do you have to know the result of the laplace transforms to get to the nearest integer of the original values say? (e.g. for normal floating point numbers can nearest integers where the input domain is -100 to 100, can they be recovered based on the floating point convluted result)? what's the algorithm for deconvoluting? Thank you for your informative and interesting video.
@virgenalosveinte5915
@virgenalosveinte5915 Жыл бұрын
amazing videos
@shabbysing9175
@shabbysing9175 4 жыл бұрын
Make video on Function of exponential order in laplace transform
@brandonmohammed9092
@brandonmohammed9092 4 жыл бұрын
So for the inverse of a laplace transform, I am guessing it is not as simple as doing the lapalce transform. How would one go and compute the inverse without using the tables?
@ermyastanru3335
@ermyastanru3335 3 жыл бұрын
Thanks D.R
@rounakdas804
@rounakdas804 6 ай бұрын
Sir, What is your research area??
@freemind.d2714
@freemind.d2714 3 жыл бұрын
Maybe you could apply some Fourier transform to filter out that wind : )
@DrTrefor
@DrTrefor 3 жыл бұрын
well played
@kianushmaleki
@kianushmaleki 2 жыл бұрын
Here is my question: k and x are two vectors and n is the dimension then F(k) = \int e^{- k \cdot x} f(x) d^n x The dot product is defined by a metric i.e. k \cdot x = g_{ab} k^a x^b where Einstein sum convention is used. I know that the Fourier transform is not valid for a general metric. Fourier transform is certainly valid in Euclidean space. Why is the Fourier transform not valid for a generic metric? 🙃
@minuklee6735
@minuklee6735 3 жыл бұрын
Awesome!!
@AmitVermais
@AmitVermais 4 жыл бұрын
Hi ! Sir , please defined with graph and also discussed picewise continuous.
@austinfritzke9305
@austinfritzke9305 4 жыл бұрын
I can't really read the red font. Why not use blue? But still, great videos. The khan academy videos were pissing me off this is much better. Thank you.
@Iman-you
@Iman-you 2 жыл бұрын
Sir i am from India🇮🇳 Sir i have a question that why inverse Laplace transform have not any prove ? Sir do we not get Laplace function after solving it's inverse? (Actually sir my English is not much good so please try to understand my question problem 🥺)
@ArsalanKhan-i7c
@ArsalanKhan-i7c 2 ай бұрын
The inverse Laplace transform lets us take a function in the frequency domain (like 𝐹 ( 𝑠 ) F(s)) and convert it back to the original time-domain function (like 𝑓 ( 𝑡 ) f(t)). When we apply the inverse Laplace transform to 𝐹 ( 𝑠 ) F(s), we don't get 𝐹 ( 𝑠 ) F(s) back; instead, we recover the original function 𝑓 ( 𝑡 ) f(t) before the Laplace transform was applied. It might seem like there's no "proof" because we often use tables or shortcuts instead of directly calculating it, but there's actually a formal mathematical definition involving complex integration. In simple terms, think of it as a two-way translation: the Laplace transform moves from time to frequency, and the inverse brings it back from frequency to time!
@tramquangpho
@tramquangpho 4 жыл бұрын
I have a question why plug in big number to t and the limit is M/(c -s) at the existence part
@nickthepostpunk5766
@nickthepostpunk5766 2 жыл бұрын
Just a quick question about existence: for existence the video states the condition s > c, but I thought s was in general complex (not real) in a Laplace transform and so I'm a little puzzled about how the (possibly) complex number s can be greater than another (possibly complex?) number c?? Thank you
@carultch
@carultch Жыл бұрын
In this context, he's referring to the real component of s, being greater than c. The imaginary component of s, is out of the picture.
@DanomaWakgari
@DanomaWakgari Ай бұрын
What is existence of the Laplace transformation?
@simphiwemalinga-mz8vg
@simphiwemalinga-mz8vg Жыл бұрын
So is there a one way method to find the the unique solution of f(t) such that L{f(t)} = F(s)?
@carultch
@carultch Жыл бұрын
The most efficient way to do it in practice, is to use a reference library of standard Laplace transforms, and match the given Laplace transform expression to a linear combination of standard Laplace transforms. There is an integral that does it more directly, but it is complicated. As an example of how to invert a Laplace transform, consider: (s - 1)/[s^3*(s + 1)*(s^2 + 1)] Construct a partial fraction expansion: A/(s + 1) + B/s^3 + C/s^2 + D/s + (E*s + F)/(s^2 + 1) Skipping ahead to the solution: 1/(s + 1) - 1/s^3 + 2/s^2 - 1/s - 1/(s^2 + 1) Known Laplace transforms that are relevant to this example: L{e^(a*t)} = 1/(s + a), which means the first term is e^(-t) L{t^n} = n!/s^(n + 1), which means the 2nd terms are polynomials of t, from a constant up to t^2 L{sin(b*t)} = b/(s^2 + b^2), which means the final term is -sin(t) 1/s^3 needs a 2 upstairs, since L{t^2} = 2!/t^2. Multiply by 2/2 to get: 1/2*(2/s^3). Its inverse is 1/2*t^2. 1/s^2 is good to go, as t 1/s is also good to go, as a constant of 1. Result: e^(-t) - 1/2*t^2 + t - 1 - sin(t)
@chanakyasinha8046
@chanakyasinha8046 3 жыл бұрын
Inverse laplace is weird, if integral of f(t) is F(s) then shouldn't have differentiation of F(s) be f(t) 😳 though it is definite... I don't get it 😔
@user-uw8rn9pc5m
@user-uw8rn9pc5m 4 жыл бұрын
Can you make it clearer with a graph?
@AmitVermais
@AmitVermais 4 жыл бұрын
Sir also make video on real analysis, complex analysis and modern algebra please sir please. And please comment on my message.
@larshaji6117
@larshaji6117 2 жыл бұрын
thanks a lot but there is a strange background sound distracting me
@rodericksibelius8472
@rodericksibelius8472 2 жыл бұрын
I wish you can give real world examples real world application using Electronic circuit and go trough all the detailed steps on how Laplace Transform to the time domain, and vice versa. Frequency domain to the Time domain,
@SHAHHUSSAIN
@SHAHHUSSAIN 4 жыл бұрын
👌
@osebrainquestfoundation9631
@osebrainquestfoundation9631 2 жыл бұрын
Knowledge
@aniketpattnaik5757
@aniketpattnaik5757 4 жыл бұрын
yo look like kevin petersen
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