Thank you very much Zeeshan for your upload, I went looking for help with factoring quartics as I was struggling with the challenge in section 1.3 of the Pearson book which I am currently self teaching and xame across your video which was very helpful with this - substituting x^2 for y makes a lot of sense in this context. P_S_ At 17:00 I believe you left (x^2-y^2) which could be factorised further as it is another difference of two squares? So final answer (x^2+y^2)(x+y)(x-y)?
@revnaza2 жыл бұрын
True 👍
@unknown-wl6be Жыл бұрын
Yeah thats true but couldnt you also simplify the (x^2+y^2) to (x+y)(x+y) so that it would be (x+y)(x+y)(x+y)(x+y)
@denuwan76884 жыл бұрын
Please make more videos on AsLevel Pure Maths. God bless you!
@DanGBP13 жыл бұрын
for e does anyone know if you must always reduce the quartic or whatever it maybe if a multiple of 2 down to a quadratic?
@abz47984 жыл бұрын
Very Helpful!
@bxyc39 ай бұрын
hi thanks for the vid, for question e, at the end before factorising, does it matter which number in the bracket goes before/first? because putting 6y before 8y instead of 8y then 6y changes the factorisation as they're split off differently so I got a slightly different answer. Just wanted to know thx
@mik.mazherulislamkhan65092 жыл бұрын
16:35 I think you missed a point! here we can continue factorising even more. Like instead of keeping (X2 -Y2)(X2+Y2) we can do (X+Y)(X-Y)(X2+Y2) ...I HOPE you read this comment and get what I meant and reply as soon as possible .SIR!! 😁😁
@tenbr0s3442 жыл бұрын
i agree with you, are we right sir
@charb9719 Жыл бұрын
Agree! I also get (x^2+y^2)(x+y)(x-y)
@unknown-wl6be Жыл бұрын
Yeah thats true but couldnt you also simplify the (x^2+y^2) to (x+y)(x+y) so that it would be (x+y)(x+y)(x+y)(x+y)
@playbouicarti5 ай бұрын
@@unknown-wl6be not thats not correct it has to be DIFFERENCE of 2 squares keyword difference which means the operation in the middle has to be -