It was extremely helpful to see the correspondence with the linear algebra side. I haven’t seen them side by side like this. Thanks
@warr2015 Жыл бұрын
Excellent video. Watched for a more in-depth look at EV Expansions for my QM class.
@olivermechling79753 жыл бұрын
Hi Nathan, your explanations help out a lot! Very concise presentation, I learned a lot. Thanks!
@miro.s3 жыл бұрын
Nice example of generalized Gramm-Schmidt orthogonalization in new transformed space expressed in natural basis. Then regarding to that basis we need only to add lamda.
@sunghyunkim38814 жыл бұрын
20:05, the summation is from -\inf to +\inf since the dummy index represents for the all possible non-trivial sol's in trig.(sin) function
@inothernews4 жыл бұрын
Thanks for the lecture, it's great. Can I check if the solution to the ODE is correct? Seems like it should be sin/cos of sqrt(lambda)* x (instead of lambda* x). If there is in fact a typo, then the eigenvalues should also be (n pi / l ) ^2, that's the only result that is affected I think.
@miro.s3 жыл бұрын
Generally and imprecisely, it is possible to write lambda instead of sqrt(lambda), to have simple and pretty form as it can happen throughout all Math, but new lambda is not eigenvalue anymore. And the result should be then eigenvalue=lamda^2
@ludviglundgren73532 жыл бұрын
@@miro.s thanks for that clarification
@AlirezaSafaee2 жыл бұрын
Apparently, at 22:14 there is a sin function missing in the formula for Wronskian.
@subhrohalder41047 ай бұрын
Excellent video:)
@nikkatalnikov Жыл бұрын
brilliant explanation
@김유황오리-n7n3 жыл бұрын
Very much helpful ! thank you so much sir👍
@bonbonpony5 ай бұрын
Yeah, that's great, but in order to do all that, we need to have the eigenfunctions and eigenvalues first. For matrices, there's at least an algorithm for that. But how are we supposed to do that with differential operators? :q
@sinahamedi27863 жыл бұрын
You mentioned that using eigenvalues is an easier way of getting Ax=b solution and explained that we should build the sigma expression from right-hand-side to calculate u(x); however, when it comes to the example, you just say the equation looks familiar and the answer is sin(x)+cos(x). If we want to guess the solution at the end, what is the point of using eigen values/functions?
@jamesmarshel17233 жыл бұрын
He used the eigenvalue problem Ax=cx to find the eigenfunctions. The solution to this problem is well known in this case. Then he uses the normalized eigenfunctions to find the solution to Ax=b by expanding x in terms of the normalized eigenfunctions. In general, this technique is based on the idea of “using a known result “ (i.e. the solution to the eigenvalue problem) or “solving a simpler problem “ (i.e. the eigenvalue problem). See Larson or Poyas on mathematical problem solving. It will change your life.
@bonbonpony5 ай бұрын
Yeah, decomposition with inner products is the obvious part. Finding the eigenfunctions and eigenvalues of a particular differential operator (especially when the coefficients are not constant) is the hard part, and no one seems to be explaining that. Without it, all the rest is pretty much useless.
@msuegriАй бұрын
In minute 18, shouldn't it be sqrt of lambda in u(x)?
@kyrilo19933 жыл бұрын
sorry if i missed something but is the end result the fourier series expansion of the function ?
@shoopinc9 ай бұрын
Kinda but not really, Fourier uses complex exponential basis. However the analog of those elements here are the eigenfunctions of the operator itself, solution is written as a sum of the eigenfunctions it is therefore operator dependent what your expansion is.
@hareshsingh8168 Жыл бұрын
Thanks.
@dbf728294 жыл бұрын
Thanks more qm content please??
@alfredomaussa3 жыл бұрын
fourier series, fourier transform, laplace transform, green functions... what's missing?