I'm loving this whole series, thanks a lot professor for putting forward a whole course!
@peter_b.1337 Жыл бұрын
Thanks for not cutting fire alarm!
@ErikScott1282 жыл бұрын
This is how I wish differential equations was taught when I was in undergrad, and methods 1 and 3 are the approach I'm taking for a video I want to make on rotorcraft flapping. Around time 31:42, you start trying to solve c1 and c2 in terms of the initial values x0 and v0. My response to this is, why bother? You already established that c1 and or c2 must be complex valued in order to make the final equation real. They are arbitrary constants, and i is a constant as well. So, when I demonstrate this, I just say "let a=c1+c2, let b=(c1-c2)i" and then establish a=x0 and b=v0. No need for complex analysis, and the result matches the intuitive guess (assuming you were able to guess the sine component) and the Taylor series result, while still being completely general.
@FA-tq9ip2 жыл бұрын
Around 17:28 I think you left the minus sign out on the board which I have put in single quotes (although you do say it): => C3 = '-'1/3! * V0 - (from an example I calculated it also seems like there should not be a minus here: => C5 = '-'1/5! * V0)
@FA-tq9ip2 жыл бұрын
Just saw that you spotted and corrected these later on in the video :)
@danieljulian4676 Жыл бұрын
Linear operator! Superposition! Great! 27:50 So, I guess we're assuming some linear algebra already. Not the first time in this series that I've seen messages from the future. It's not that free stuff is useless, but anyone watching these is sinking a half-hour at a time into following the presentation. It seems more that these videos are intended as refresher, or as quick review of formal lecture material given in a physical classroom by Steve himself. Anyone else is going to have to forego any pretense of rigor or fill in a lot of blanks with a lot of legwork. This series is not a substitute for a complete course.
@bitterthread67942 жыл бұрын
Keep uploading the content Professor. I am taking Engineering courses and this has been very useful for even providing motivation how all things are fundamentally related .
@seabasschukwu698817 күн бұрын
Have you graduated yet?
@hoseinzahedifar15622 жыл бұрын
A perfect topic by an excellent teacher... thank you.
@Buyson2 жыл бұрын
What about Laplace Transform? I think we could use it as well.
@BarkanUgurlu2 жыл бұрын
I came to write this. :)
@TheRsmits2 жыл бұрын
The Laplace Transform is basically guessing a mixture of exponential solutions (3rd way) and converting analytic problems into algebraic problems. In this case, the guess is also that it is a discrete mixture.
@halilibrahimEgilmez11 ай бұрын
in time 30:00 if λ is complex like a±ib then the answer should be x=e^at (x_0 cos(bt) + v_0 sin(bt) ) and here a=0 and b=1 then x=x_0 cost+v_0 sin(t)
@Pedritox09532 жыл бұрын
Great video! Would be great videos of Lagrangian's dynamics
2 жыл бұрын
Seems like magic. Thank you very much!
@TorqueinxdirectionАй бұрын
Every time I need to counter differential equation in my Engineering journey I come here to refresh the stuff.
@yoyoyowazupperson11 ай бұрын
hello. Can someone please explain how x0 got divided it by 2 at 32:35? this makes no sense to me… method III after the fire alarm in particular is very confusing to me
@hilalvenus10 ай бұрын
Because c1=c2.
@riteshparmar4687 Жыл бұрын
Thanque very much for this beautiful lecture.
@salah3beed11 ай бұрын
28:00 ✨ok that was just the fire alarm✨
@curtpiazza16889 ай бұрын
I learned so much in less than 40 min.! Thanx! ❤ 😂
@benarcher372 Жыл бұрын
Strange. In Method II the answer is x(t) = cos(t)x_zero + sin(t)v_zero. But here we are adding a length to a velocity!? The answer x(t) is a length. Perhaps the second term should have been multiplied by 't'? Am I missing something here?
@Oberbremser Жыл бұрын
the simplification not to write (k/m) which has dimension 1/second^2 causes the "problem" with units. I had same thought as you to add length and velocity which is not possible due to different units. But considered the (k/m) factor and the units are then correct as in corresponding terms of the taylor serie (1/second^2) (1/second^4) ... appears forcing each term to have dimension of length. i.g: - 1/(3!)*v0*t^3*(1/second^2) (1/second^2) stems from k/m and so on.
@benarcher372 Жыл бұрын
@@Oberbremser Thanks for your comment. I need to think about this. Old brain..
@xiangwenyan37722 жыл бұрын
jajaja, a fire alarm short break
@VTdarkangel2 жыл бұрын
There is also the characteristic equation. That being said, I suspect that he is going to hit in that with the eigenvalue determinant or if he covers Laplace Transforms.
@timgorringe6668 Жыл бұрын
great lecture! is x_o cos(t) - v_o sin(t) soln dimensionally incorrect? (taylor series soln)
@aris.mavridis Жыл бұрын
I'm having a bit of trouble using the second method for any k/m instead of just 1. Would the Xo and Vo terms be multiplied by k/m as well? I tried to find such solutions online but had no luck.
@carultch Жыл бұрын
In the general solution: x = x0*cos(w*t) + "v0*sin(w*t)" v0 isn't really the coefficient on the sine term, unless w=1 (which would be the case if k/m were 1, since w=sqrt(k/m)). I put this term in quotes, because it really needs to be something else. We want dx/dt to equal v at t=0. Let A and B be defined such that the general solution is: x = A*cos(w*t) + B*sin(w*t) Take the derivative: dx/dt = -A*w*sin(w*t) + B*w*cos(w*t) Evaluate at t = 0: x(0) = A dx/dt at t=0 = B*w So as you can see, v0 = B*w. Thus, when we solve for the coefficient B, this really is equal to v0/w. Thus, the general solution is: x = x0*cos(w*t) + v0/w * sin(w*t)
@aris.mavridis11 ай бұрын
Hello @@carultch, thank you for the reply. I was asking about the second method followed in the video, that is, the Taylor series solution.
@hsenagrahdeers6 ай бұрын
Hi, did you find what you were looking for somewhere/figured it out somehow? I'm attempting the same rn.
@waynelast1685 Жыл бұрын
Please tell me how you use this display board technology?
@dibyasreekantbisoyi4695 ай бұрын
they write normally on a transparent board, and then flip the video, so we are to read it
@bendavis2234 Жыл бұрын
I jumped at the fire alarm at ~27:30
@hilalvenus10 ай бұрын
I was looking for this comment!
@klammer752 жыл бұрын
I was sooooo close to skinning that cat…phew!🧐😉😆
@muthukamalan.m6316 Жыл бұрын
how do we visualize second order DE equations like we understand by seeing slope field in 1st order DE ?
@seannibecker55009 ай бұрын
Are you actually writing left to right from your perspective?
@coraltown1 Жыл бұрын
A mathematical magic carpet ride !
@fryingpanm6977 Жыл бұрын
thank you so much sir
@joseluizpereiradacunha7244 Жыл бұрын
MUITO OBRIGADO
@sumrak22ableАй бұрын
Why F = - kx?
@lioneloddo2 жыл бұрын
And there are also 2 other ways to establish the differential equation of the oscillator. 1. From the conservation of the energy : d/dt(1/2.m.V**2 + 1/2.K.X**2) = 0 then mV*d/dt(V)+KX*d/dt(X)=0 and then ... 2. From the momentum : d/dt(mV)=kX then ... Many ways to establish the equation, many ways to solve the equation. Why are there so many ways to deal with the oscillator ? Why are there so many points of view to deal with the oscillator ? I really don't know what it means ...
@peterkim53942 жыл бұрын
Why? I think Jesse Pinkman summed it up best, "Yeah, science bitch!"
@navsquid322 жыл бұрын
Don’t forget the Lagrangian formulation.
@lioneloddo2 жыл бұрын
@@navsquid32 L=1/2.m.V**2 - 1/2.k.X**2 dL/dV= mV dL/dX=-kX So from eq of Lagrage : d/dt(dL/dV) = dL/dX and ... You're right !
@mintakan0032 жыл бұрын
The Taylor series is too tedious for most humans. But if it's general, isn't it something that can be handled by computers? Computer solvers? (And I mean "symbolic" solvers, not "data fitting".) Or is the "suspend variables" method actually used?
@arthurcoward69792 жыл бұрын
So how do you get the notes you're writing to appear correctly? That is, writing right to left when I'm pretty sure you would have to be writing backwards to achieve that since you're facing the viewer. Enjoying the talks, btw!
@carultch Жыл бұрын
He probably mirrors the video, so it appears normal. If you saw him in person, your side of his writing would appear backwards.