SFD and BMD - Problem 1 - Part 3 - Shear Force and Bending Moment Diagram - Strength of Materials

[@Ekeeda]

Hello Friends Please watch the updated version here - kzbin.info/www/bejne/oqCag4ivnJ2Co68 Watch complete video series of subject Strength of Materials only on Ekeeda Application. Download Ekeeda application to get 1000 Studycoins and use it to access free courses. Steps to follow:- 1. Download Ekeeda application from the link given below. 2. Sign up or Log in to your account. 3. You will get 1000 Studycoins worth Rs 1000. 4. Add the courses to your cart. 5. Select Study coins option to get free access. Android App : play.google.com/store/apps/details/?id=student.ekeeda.com.ekeeda_student iOS App : apps.apple.com/in/app/ekeeda/id1442131224

[@alokshukla3167]

sr point of contrflexure x2 value is 2.60266 not 0.4

[@ankushjaswal1992]

right one.

[@stockideas7]

Yupp

[@mohammadzafar4802]

your are right. And X1 = 2.977 not 2.8 ???

[@Vickys_food_channel]

Same doubt

[@Princekumar-oy6dy]

Yupp!

[@austin_tiyani]

Never trusted this channel cause i thought it won't show me what i want since I'm from south africa 🇿🇦 but it helped me a lot by trying it out. Thanks!

[@Ripon045]

U teach so well sir... Need & clean... Just wow... & u solved my problm

[@meshackwachiuri566]

I have called myself lazy. I have never solved this before but this video is a game-changer.

[@Ekeeda]

Thank you for appreciation. Visit Ekeeda App where you will get all the concepts from basics, practice problems and doubt asking facility. Visit - ekeeda.com/ Download App - ekeeda.com/download.html

[@TheWorldThinkers]

Thank You Sir for this video. i found an error in calculation...the point of contraflexure value X2 from B is 2.604 not 0.4. 0.4 is from D and 2.6 is from B which makes it total of 3.0. Thanks.

[@nitishsharma7504]

sir u explained this thing in a very very simple way thanku sir for your efforts i always recommend your online lecture videos to my friends keep making such types of videos

[@sauravshetty2516]

Sir ur teaching skill is awesomeeeeereeeeeeeee

[@gomathisankar9472]

X1=2.977 X2 =2.60

[@midnightson787]

exactly

[@soewai9278]

Sir,in BMD calculation x2 value should be 2.6m in my calculation.Right?

[@uuvsbkhisisihsb]

Sir please dont use subtitles..it's too disturbing.

[@jayantnalla4910]

Yeah

[@junaidyousufdar]

Yeap.but in point of contraflexure

[@athulk8343]

explanation was very clean and neat sir. thank you very much

[@aoemezi]

Saving lives since 2015👏🏻

[@rajukambale4708]

Sir,. Second point of contraflexure X2 is 2.604m not 0.4 m

[@emmanuelchibambo3367]

Excellent work sir 99.98%

[@ssebuggwaworamadhanahmad5577]

wow thanks for the brief and nice explanation.

[@sai799oo]

Thank u.so much great work.thankss

[@Ekeeda]

Thank You so much for your appreciation .If you like our videos then you can share your review with us - www.google.co.in/search?q=ekeeda&rlz=1C1CHBF_enIN820IN820&oq=ekeeda&aqs=chrome..69i57j69i60j69i61j69i59j0l2.2618j0j7&sourceid=chrome&ie=UTF-8#lrd=0x3be7cef39a0bcb1f:0x695389d0b57989f4,3,,,

[@gauravjoshi7245]

@@Ekeeda point of contraflexure value is wrong 0.4 correct value is 2.6 and bending moment at D is 6.84 not 6.87 Too much mistake is done while solving.

[@shubhamdiwakar863]

sir point of contrafacture me x2 ki value 2.602 aayegi

[@abhijitbera007]

Shubham Diwakar what's parking question when you have nots in properly this distance from be so you can calculate 3 - 2.6 ok is equal to 0.4

[@shashankkumar6955]

X2ki value from point b se 2.6 hai or point d se .4 hai

[@omprakashgunarat]

X2 2.6 hi h

[@irzaanshaik1403]

U explain very easily sir Thank u sir .ur method of teaching is great sir

[@saltanattolebay510]

Awesome explanation! Thank u !

[@Ekeeda]

Saltanat Tolebay You are most welcome. Stay tuned with ekeeda channel for more videos. Saltanat Tolebay we request you to share our work with your friends and family. BECAUSE YOUR LOVE GIVES US POWER TO PRODUCE MORE AND MORE GOOD CONTENT TO SPREAD THE QUALITY FREE EDUCATION. You can Subscribe by clicking on below link kzbin.info Saltanat Tolebay you can Help Us to Improve our Service. #Saltanat Tolebay #Ekeeda #YourVirtualTeacher #LoveEducaion #OnlineLectures For more Educational Information Visit ekeeda.com You can also provide us Financial Help to continue this good work www.patreon.com/ekeeda

[@Ekeeda]

You are most welcome. Thanks for watching, stay tuned for more videos.

[@keralacodingacademykca4597]

great videos all of them sfd bmd...gonna help me in my university exam..thanks man...i found an error in calculation...the point of contraflexure value x3 is 2.604 not 0.4....thanks

[@abhijitbera007]

STEVE ARMSTRONG ....o ok I can calculate this 2.6 is that X to answer and their answer also separated from the distance before this distance 3 - 2.6 is equal to 0.4

[@Diganta_Khati]

@@abhijitbera007 which means we can write the contraflexure point as 2.6 respect to B??

[@abhijitbera007]

@@Diganta_Khati normally we can do this

[@88geetabhat73]

Sir you have to clear my all dobuts. Thank you so much sir your great reaching 🤗🤗. I love your teaching way.Once again thank you so much.

[@Ekeeda]

We are happy that our content is helpful to you and it motivates us to keep focusing on the content. Download Ekeeda App where you will get courses with all the concepts from basics, practice problems and doubt asking facility from top educators. Download App - ekeeda.com/download.html

[@rajglasshousemansa]

X1= 2.97m and X2= 2.4 m

[@Sunildevk]

hi bro x2 value in video is wrong i think m i right?

[@kshitizarora93]

X2 = 2.6

[@mahendrasigdel8360]

gagandeep bansal how x2=2.4 I think x2 must be 2.6

[@MrSakshamsharma]

yes x2=2.6 and 0.4 will be from point D not from B

[@mohammadzafar4802]

X1=2.977 and X2=2.6

[@bhargavgohil32]

Thank you very much Sir

[@Ruhujusu]

Enjoyed ur Lecture sir, grt. If possible sir keep it one video instead of part 1,2,3.

[@Ekeeda]

Hello Thank you for commenting. Share the video with your friends and colleagues and stay tuned to our channel for more videos. Thanks and Regards Ekeeda Team

[@anurooppatidar1718]

Sir you explain very good sir but this Black box disterbed me

[@soumipatra2308]

sir the video was very very helpful. thank u sir

[@sureshsonofgod9072]

Very thanks sir. Nice explanation.

[@Ekeeda]

Keep supporting us and Thank you for yours precious words! Download Ekeeda Application and use coupon code 'FIRSTTIME' and you will be able to watch any one subject free for one month Android:- play.google.com/store/apps/details?id=student.ekeeda.com.ekeeda_student&hl=en iOS:- itunes.apple.com/tt/app/ekeeda/id1442131224

[@sampsonerasmus5219]

I noticed the way you take your sign convention. It is a bit different but understable, still I appreciate the refresher

[@Batman_the_greatest_Warrior]

An ideal teacher 👌

[@Ekeeda]

Welcome.

[@MehediHasan-mj6vx]

Thank you sir

[@diveshmore7861]

Very well explained thank you sir

[@omprakashtiwari1246]

A lot of thanx sir...

[@alagbeolabisi3777]

Even though I couldn't do shit in the exam with all this videos Thanks

[@saiganesh4399]

Thanks for you great leature Sir

[@sidarthalongjam]

Best teacher

[@Ekeeda]

Thank you! We are giving any one subject free for one month, If you want to access the free subject just download the Ekeeda app and use coupon code ''FIRSTTIME" (This offer is valid through app only) Download Ekeeda Application and take advantage of this offer. Android:- play.google.com/store/apps/details?id=student.ekeeda.com.ekeeda_student&hl=en iOS:- itunes.apple.com/tt/app/ekeeda/id1442131224

[@saudkhan2870]

do you have any video regarding coupler forces?

[@-LE-Ganesh]

heart full thanks sir

[@VYOMISTRY]

Sir, point of contraflexural of overhanging is in bmd ..... Why not u calculated in sfd because in sfd also from point A to B Shear force changes its sign .... Plez help me

[@RohitKumar-wt3rg]

sir from where can I get the notes of this chapter

[@rahityakolla788]

Sir your way of explaining I'd good and some videos are private how can I access to it sir

[@Ekeeda]

To get access for the videos you will have to download the Ekeeda-Learning Application by going on this link bit.ly/353lpP2 .Besides just getting the access to the videos you can directly ask the queries if any.Hence downloading the app can be more beneficial.

[@sayakghosh5938]

thank u very much sir

[@Sunildevk]

hello every one any can please explain how to solve the equations from above that is 80-20 x1 = 6.87 x1 =2.8? and also 135-45 x2 = 6.87 x2 =0.4? please reply?

[@abhijitbera007]

K Sunil dev Chowdary sad sad what's a distance from beach distance from bliss 360 - 2.6 whatever 0.4 please contest Please concentration this.

[@paulbass6805]

It's a mistake, maybe from the calculator ..x1 is = 2.97m and X2 is = 2.6m .. U can cross-check by calculating by urself

[@erreemas3098]

80-20 x1 =6.87 x1 80 = 6.871x1+20 x1 80 = 27.87 x1 80/26.87 = x1 2.97 = x1 X1 = 2.97 ............._________.......... 135-45x2 = 6.71x2 135 = 6.71x2 + 45x2 135 = 51.71x2 135/51.71=x2 2.61 = x2 X2 = 2.61

[@mr.matrix20]

It's 0.4 m from *D* i.e. 3-2.6=0.4

[@criticalworld1664]

Sir the value of x2 in your slide is wrong . As you find it as 0.4m but it will be 2.60m as per correct calculation

[@Earthplanet360]

sir why few videos are not available here in your . . . .

[@Ekeeda]

You can get all videos on our app and you can access any one course free for one month! We are giving any one subject free for one month, If you want to access the free subject just download the Ekeeda app and use coupon code ''FIRSTTIME" (This offer is valid through app only) Download Ekeeda Application and take advantage of this offer. Android:- play.google.com/store/apps/details?id=student.ekeeda.com.ekeeda_student&hl=en iOS:- itunes.apple.com/tt/app/ekeeda/id1442131224

[@amritanandpathak1112]

when do we do SF left and right and BM left and right

[@mohamedabuthakir1752]

hi u r saying the X2 distance incorrectly. It has to be mentioned first x2 then 3-x2..... Please correct me if I am wrong

[@ex6tamim345]

2.60 from the point B.

[@yogeshwaranm9341]

We need to find max. BMD or not?

[@Ekeeda]

Hello For asking your doubt directly to our Professors please download Ekeeda Application. Android App : play.google.com/store/apps/details/?id=student.ekeeda.com.ekeeda_student iOS App : apps.apple.com/in/app/ekeeda/id1442131224

[@kallolbiswas8603]

thank u very much sir...

[@Ekeeda]

Kallol Biswas You are most welcome. Stay tuned with ekeeda channel for more videos. You can Subscribe by clicking on below link kzbin.info Kallol Biswas you can Help Us to Improve our Service. #Kallol Biswas #Ekeeda #YourVirtualTeacher #LoveEducaion #OnlineLectures For more Educational Information Visit ekeeda.com

[@YoungFetty]

I thank u sir for teaching me shear force and bending moments

[@ankuryadav2290]

The value of x1(distance of point of contraflexure from A) should be 2.97m and x2(distance of point of contraflexure from B) should be 2.6 m...

[@saudkhan2870]

thank you

[@SkAli-ol4hn]

Supper sir

[@Ekeeda]

"Thank you so much for your words. We are here with our new android app for our subscribers. Now you can watch our more videos of all subject on our app. Download Ekeeda Engineering Learning App from Google Play Store - play.google.com/store/apps/details?id=student.ekeeda.com.ekeeda_student&hl=en"

[@abhijitbera007]

Thanks

[@chaitanyaarunkumar4029]

X2:-2.86

[@pj_1812]

Can u tell in detail how to calculate eqn of x1 and x2 😢

[@IntradayActions]

nice

[@sumanthbharadwajanantharaj6761]

sir x2 is 2.6 from B

[@mandlasiddhartha6531]

Nice sir ❤️👍

[@Ekeeda]

We are happy that our content is helpful to you and it motivates us to keep focusing on the content. Download Ekeeda App where you will get courses with all the concepts from basics, practice problems and doubt asking facility from top educators. Download App - ekeeda.com/download.html

[@pj_1812]

Can u tell in detail how to calculate eqn of x1 and x2 😢

[@namanmathur9183]

just cross multiplied them

[@tejashreemohite4154]

x2=2.6

[@SoudagerAamer]

x2 is 2.603 from point B. How come he gets 0.4?

[@midnightson787]

exactly

[@manthankahar496]

3-0.4 = 2.6

[@SoudagerAamer]

@@manthankahar496 Bro. 4yrs later 🤣🤣 I've completed my engineering. Thanks anyway.

[@SoudagerAamer]

@@manthankahar496 And no, the answer is still 2.60266 or 2.603 (simplified). 45 ÷ X2 = 6.87 ÷ (3-X2) Doing cross multiplication, 45 × (3÷X2) = 6.87 × X2 135 - 45 X2 = 6.87 X2 Taking X2 terms on one side and simplifying them, 135 = 51.87 X2 Taking 51.87 on left side in denominator's position (135 ÷ 51.87) = X2 2.6026604974 = X2 OR 2.603 = X2

[@148shraddhagawai5]

Sir, it should be ( - 20/x1) instead of 20

[@SalmanKhan-vi4gi]

U should have to find maximum bending moment..

[@vikaspatil003]

Poc from B is 2.60 m not a 0.4 m

[@nasai5157]

Sir x2 value was wrong it is 2.6

[@mdarshad7571]

Sir both the value of x1 and X2 are not correct

[@mdarshad7571]

Plz update the value

[@shamulailatpamnilachandras9271]

From point B how can be 0.4 it will be 2.6

[@yathishchandra7700]

Sir x2value is not .4 is 2.6026 please correct sir 😭😭😭😭🙏🙏🙏🙏

[@bikersunel]

X2 is 2.6 m

[@shivuhnshivuhn7198]

X2 calculation is !?? 2.60 is the answer ryt

[@Yuvrajmohanty_]

X2=2.6 hoga sir..

[@SaurabhPonkshe1]

x2 should be 2.602

[@royalsurya7068]

ye screen pr likh jata h to figure nhi bna pate hh, dikhta hi nhi hhhh thora time de likhne kaaa

[@wanassaben8269]

💜💜💜🇩🇿🇩🇿🙆‍♀️

[@Afroz218]

Thanks sir