Shear force and bending moment diagram practice problem #1

Check out www.engineer4free.com/structur... for more free structural analysis tutorials. The course covers shear force and bending moment diagram review, method of superposition, moment area method, force method, displacement method, slope deflection method, and 3 moment equation.
This tutorial goes over how to draw the shear force diagram, bending moment diagram, and deflected shape of a simply supported beam with a distributed load and a point load.
If you found this video helpful, please consider supporting my work on Patreon: / engineer4free
Looking for software? I highly recommend checking out SkyCiv. They make a full suite of online structural analysis software and tools that are useful for both students and professionals, including calculators for beams, trusses, frames, moment of inertia and more. It’s great for checking your work: bit.ly/skyciv-e4f
Don’t forget to subscribe on KZbin and join the Engineer4Free mail list:
Subscribe: kzbin.info_...
Mail List: www.engineer4free.com/newsletter
Social Media:
Facebook: / engineer4free
Instagram: / engineer4free
Twitter: / engineer4free
Thanks for watching, The Struggle Is REAL!

[@matta7829]

Statics final tomorrow, wish me luck!

[@Engineer4Free]

Ahhhh good luck for real Matt!!! Check out engineer4free.com/statics for all my statics videos and then also the first section of engineer4free.com/structural-analysis if you ned more practice with SFD/BMD!

[@argenisperez3467]

Same here friend, best of luck to you

[@eddiemartin2268]

Hope it went well! Got statics in a few days!

[@azamkhan1526]

how was ur result?

[@venchanpiseth1321]

@@Engineer4Free what is the program that u used to draw this?

[@maryn392]

You made it look so easy to understand. I used to struggle really hard drawing this diagram but you made it look simple. Thank you very much

[@sammiemay138]

I was so confused about this and found it hard until i watched the video. Fantastic explanation clear and easy to understand.

[@cpaulcervantes]

Looking up old notes for a job interview and left my notes at my parents house in California. I now live in Washington. This was a lot better than digging through notes and more straightforward and easy to understand. Thanks for the help!

[@Engineer4Free]

Glad I could help! Check out engineer4free.com/structural-analysis for some more examples if you haven’t already, and good luck with the interview!!

[@0skulllittle]

you taught me what all my teachers failed to teach me! thanks

[@Engineer4Free]

Glad I can help

[@edwinakwemoh9547]

4 years later and the video still helps. God bless you!

[@Engineer4Free]

Can't believe it's already been 4 years! Thanks for still watching in 2021! =)

[@sarahhassan4953]

UR A LIFE SAVING GENIUS!!! I have watched so many videos to try to figure out how to determine the location the sheer diagram crosses zero and all of them were so messy and complicated! - this was so easy and straight forward! May God bless ur soul!

[@Engineer4Free]

Thanks Sarah 😊. You might find the rest of the examples helpful too, they are here: www.engineer4free.com/blog/ultimate-guide-to-shear-force-and-bending-moment-diagrams

[@tkc056]

Four years of undergrad ME, and this is the cleanest statics beam bending video I've seen. Good stuff

[@Engineer4Free]

I got 8 more right where that came form: engineer4free.com/structural-analysis 😂😂. But thanks tho

[@nadiaditta4647]

thank you so much for these amazing videos!! my structural mechanics exam tomorrow and i’m terrified but a bit less so now that i’ve found these

[@Engineer4Free]

Hope it went well!

[@yadrzgar9980]

I have mechanics of materials finals tomorrow and I want to say my teacher tried to explain this for 2 weeks and couldn’t do what you did in 10 mins! Thank you

[@Engineer4Free]

That's unfortunate that you got that professor, but great feedback about my videos.. Thanks for sharing and glad I could help =)

[@yatogami5598]

That's the most humane explanation (simplest) ever. Thank you so much!

[@Engineer4Free]

Thanks Yato! 😊

[@rmrafsanzanilabib6881]

Your BM calculation and BMD was super helpful. Thank you

[@tahiratarr9647]

You sir are a whole legend. A method I can finally understand completely. Many blessings!

[@Engineer4Free]

Thanks Tahira!!!

[@Iriee242]

You sir, are a hero. Thank you for this labor of love.

[@Engineer4Free]

Thanks friend 🙂

[@aroom995]

You are helping generations man keep it up

[@sserwaddajoseph5869]

This explanation has saved my life. Big thank you sir. God bless you with whatever you want

[@gladys5753]

Hey cousemate,we a test today hopefully u still remember

[@deepakbriglall5845]

Explain so much better than my professor. Thank you for all that you do

[@Raniaska0306]

Sir please know that you are a great teacher, keep it up, I love your videos!!!

[@abisber]

idk how many times i go back to see this explanation, much helpful than the teachers slides

[@Engineer4Free]

Glad to hear its helping!! =)

[@tyleryatco6591]

Thank you! Saved me. Fell asleep in my statics lecture and was so lost in this

[@Engineer4Free]

😂😴

[@josipvlahovic326]

This was great! You explained it in a very good and understanding way. Thank you. I will become a civil engineer in a few years and this has helped me a lot.

[@Engineer4Free]

Awesome! Th aks for commenting, and good luck in your studies! I've got a lot of videos that can help you 🙂🙂

[@bars1734]

I have a statics quiz tomorrow. Thank you for the information. You, sir, are a hero.

[@Engineer4Free]

Good luck!!! =)

[@BlessedGPlays]

I have CVE test in like 2 hours 😂😂 this was a huge help

[@Pikapchuu]

What a helpful video! Thanks for helping me review for the FE :)

[@Engineer4Free]

Thanks for the feedback Priscilla, good luck on your exam!!

[@eliasmakanyire3939]

you are the best ,my lecturer never explained where the area came from

[@Engineer4Free]

Thanks Elias. I definitely recommend checkout out the other videos I did on SFD and BMD for more practice too: www.engineer4free.com/blog/ultimate-guide-to-shear-force-and-bending-moment-diagrams =)

[@harshsaini9537]

Quality stuff. just lovin' these lectures

[@Engineer4Free]

Thanks!! =)

[@book9687]

You saved me! Thanks a lot. wish me luck for the exam in 6days 😭

[@Engineer4Free]

Yeah good luck!! Check out 8 more examples in section one of engineer4free.com/structural-analysis 🙌🙌

[@raulmishiyev]

Thank you so much! Studying for the FE exam after years away from school and struggling with this section

[@Engineer4Free]

Hey Raúl, happy to help! Make sure you check out the rest of the vids on engineer4free.com this is from the Structural Analysis playlist

[@gowthamthotapalli8867]

@@Engineer4Free can u elaborate support reaction A.

[@Valantis_Stylianou]

Sir you are the best! Thank you very much for sharing this video! You've helped me a lot

[@Engineer4Free]

Awesome! Glad to hear it, hope you find my other vids helpful too 🙂🙂

[@boyka712]

thank you my friend for this simplify and hope you the best

[@Engineer4Free]

You're welcome bud!

[@christinesison5638]

I was little confuse to determine if it is concave upward or concave downward if you sketch in moment diagram but i really appreciate your video 😊

[@Engineer4Free]

Where the BMD is positive, the curvature will be concave up, where the BMD is negative, the deflected beam will be concave down. At points where the BMD switches from positive to negative, you have an inflection point in the curvature. This is a good example that highlights it: engineer4free.com/4/shear-force-and-bending-moment-diagram-practice-problem-8 but I also recommend just watching videos 1-9 here: engineer4free.com/structual-analysis for more examples and practice to get the hang of these

[@melissaleffingwell9501]

Thank you for this!

[@beryamin8815]

You’re amazing thank you so much 😊

[@Engineer4Free]

Thankssssss =) =)

[@jamesschroeder2040]

Good job man! helped me a lot :)

[@Engineer4Free]

Awesome glad to hear it!!

[@gamersworld6591]

thank you very much My Teacher , your student from Syria

[@Engineer4Free]

You're welcome, I hope you can find more of my videos helpful!

[@norielgarcia9379]

Nice presentation. May i ask what software are you using?

[@babakiani]

Thank you very much Sir for the great content!

[@alexnelson8]

Good PE exam review. Thanks bud.

[@Engineer4Free]

Thanks for the feedback, hope the exam goes well!

[@joeyjaboli1641]

You earn my subscription. Thanks a lot man!

[@Engineer4Free]

Honoured to have it, thanks Joey!! 🤜🤛

[@mathsconceptspashto8959]

Thank you sir. Your teaching method is easy to understand for a common person like me🤗🤗

[@Engineer4Free]

Awesome, that's the goal!

[@greatpharoh0303]

God bless you my brother, Thank you so much!

[@Engineer4Free]

Your welcome Phil!! 😊

[@sourblve]

Duuuude you are the OG of statics!

[@Engineer4Free]

Hahaha thanks Menyota 🤜🤛

[@ahmedmuawiyah8985]

Absolutely grateful, thank you.

[@Engineer4Free]

Awesome Ahmed!! 🙂

[@michaelhunt2222]

As an architect student, this is really useful (im learning how to do this before its taught in a lecture lol)

[@Engineer4Free]

Smart move my friend, it will make your life much easier to be ahead both in the sense of time, and understanding with this stuff!!

[@ahmedyehia9560]

Where do u use structural analysis as an architect ?

[@michaelhunt2222]

@@ahmedyehia9560 nah lol

[@gadieloros6280]

@@ahmedyehia9560 you dont haha its more for the arch. engineers not much architects

[@ancy200]

It's more useful to Civil engineers not Architecture

[@karimalsaid1951]

I have a question, we were taught (long time ago, already forgot alot) that for all structural analysis on civil engineering problems, we are to put the positive moments at the bottom side of the axis, so that the bmd correlates with tension, and whenever there is a distributed load, bmd has to be parabolic, with the arc bending with the direction of the dis. load, now looking at other people's examples, haven't seen anyone mention the inverted signs on bmd; so now im trying to wrap my head around if that holds true (specifically the arc bend going with the direction of udl) in all examples ?

[@pine4pple808]

cant thank you enough, truly appreciated

[@opokuprince253]

God bless you for your nice explaination.

[@mcho1094]

You a hero who save my assignment

[@Engineer4Free]

Awesome!!! =) =)

[@mhammadsinjer9313]

thanks from all of my heart

[@nickkakavitsas1394]

Great videos. Do you know anywhere one could find shear and moment diagram practice problem videos like this for distributed loads of varying shapes, such as parabolas, triangles, etc?

[@Engineer4Free]

I've got some videos for finding reaction forces with triangular/parabolic etc distributed loads under the "centroids and distributed loads" section of engineer4free.com/statics that would be a good starting point, as that is the first step in drawing the SFDs and BMDs. I should include some actual examples through on doing full problems. Thanks for the suggestion, hopefully I can get around to making some soon!

[@alantam4579]

thank you, I understand shear force and bending moment much better.

[@Engineer4Free]

Glad to hear it!! 🙂

[@spencerpearson168]

THANK YOU FOR THIS VIDEO

[@-surah4505]

You are a mazing thank you so much Good luck From Egypt 🇪🇬

[@Engineer4Free]

Thanks and welcome =) =)

[@moviesfreak154]

It is helpful. Thank you sir.

[@brenkolenicolas4186]

Wow, thank you, sir, It's hard for me to understand the mechanics of deformable bodies in this online class. I'm glad that I found your playlist sir thank you very much 💚💚

[@Engineer4Free]

Glad I can help!! I have 3 playlists related to structures. Depending on the topic, the videos may be in one or another: engineer4free.com/statics engineer4free.com/mechanics-of-materials engineer4free.com/structural-analysis =)

[@brenkolenicolas4186]

@@Engineer4Free oh thank you very much I appreciated all your effort to help us learn about these lessons thank you very much sir :)

[@oseikuami5430]

THANKS FOR SUCH A NICE LESSON.

[@Engineer4Free]

UR WELCOME

[@snazzytiktok4223]

just so you know you're still saving lives

[@somtoobienu5081]

Yep

[@Engineer4Free]

Glad to hear it =) =)

[@whiterice6663]

You are a lifesaver! had so much trouble with these questions but it all makes so much sense now, thank you :)

[@Engineer4Free]

Glad I could help!! =)

[@hannahnkunika1976]

The video is really helpful

[@noor_alkhamiri3213]

this is so helpful thank you so much!

[@Engineer4Free]

Thanks for letting me know, glad to hear it!! I have more examples like it at engineer4free.com/structural-analysis check them out!!

[@NoOne-cg9im]

Sir you have just saved my life

[@Engineer4Free]

Glad to hear it! You can check out more examples here: www.engineer4free.com/blog/ultimate-guide-to-shear-force-and-bending-moment-diagrams =)

[@yukson8209]

thank you very much, it helps a lot

[@Engineer4Free]

Hey thanks for the comment =)

[@muhammadzaidhasan1426]

thanks a lot sir.........keep up the good work.....may you propsper more and more

[@Engineer4Free]

Thanks friend!!!

[@shreyashshankar9819]

Bro you are a real Engineer!!

[@Engineer4Free]

Hahaha, thanks!! 💪

[@geraldinepaulinelucas6894]

thank you so much

[@tehshowtime]

You Sir are a legend

[@Engineer4Free]

Thanks Nadeem =)

[@limliyong9873]

Appreciate your work thanks

[@Engineer4Free]

Thanks Lim!! =)

[@mohannadzaaza5162]

thank you. clear and informative.

[@Engineer4Free]

Glad it was helpful! =)

[@zhengyangsong]

Thanks for the useful video!!!

[@Engineer4Free]

You're welcome, glad I can help!!

[@gabbyproeh7158]

how did you get 10(3)(6) where is the 3m coming from if the point load is at 6m

[@Engineer4Free]

(10kN/m)*(6m)=60kN is the magnitude of the entire distributed load. It’s centroid (location of resultant) is in its middle, which is 3m from either side of it. That means the resultant is 3m away from point A. So (60kN)*(3m)=180kNm is the magnitude of the moment that the distributed load causes about A. Note that the units check out too for the units of a moment!

[@lemitowfik5881]

Engineer4Free ....so we only multiply centroids for distributed systems cases??

[@WetPig]

@@lemitowfik5881 It's physics, the moment is the force times the moment arm(distance). So what happens is you have an integral F(force)x(distance)dx, from in the case of the video from 0 to 6. That integral's solution is (Fx^2)/2 = (10(kN)6^2)/2 = (10x360)/2= 180kN. It could be -180kN, but you have to look if that makes sense in the specific problem. I have this as a one time course in my computer-related physics major (can't translate it) I've had only 2 lessons, don't know anything.

[@alupha_216]

Just as lost as you are mate, I’m still looking a video that’ll explain everything from the start ☹️

[@drofeng]

Check out this video on force resultants kzbin.info/www/bejne/l33ZfWRrl8qtqa8

[@asadgondal3746]

Thanks so much for the tutorial! Please may you elaborate on the "similar triangles" solution to find x on the SF diagram? Also, are there other ways of finding x? Thank you.

[@sacayan_johnn]

So the 50/x is the smaller triangle on the SFD. x is the distance (run) you are looking for. So you divide the 50/x (rise/run). Now equal it to the bigger triangle which has a rise of 10(6) = 60 load and divide it with 3+3 = 6 m. You solve for x by cross multiply it so 50/x = 60/6 would become 60(x)=50(6) and just solve for x. Hope this helps.

[@olevel_maths1470]

BMD and SFD (100%) kzbin.info/www/bejne/eIWTfX-bacSAaaM

[@nirmalrana3538]

Hey there. Your video is really helpful. Which software you are using? I would like to write important notes on this and probably, one example to remind me your teaching.

[@Engineer4Free]

Hey Nirmal, I've got a full list of the hardware and software that I use to make the videos at engineer4free.com/tools ✌️

[@OGTennyson]

This was helpful asf...thank you 😭❤️

[@Engineer4Free]

Glad it helped! Full playlist is here engineer4free.com/structural-analysis 👍

[@hazy7964]

Bro saved me from solid mechanics 🙏

[@Engineer4Free]

I gochu 🙌

[@rogerzheng2814]

just want to say thank you.

[@Engineer4Free]

Thanks for taking time to leave the comment, you're welcome!

[@rahafmadieh6868]

Thank youu very much! What is the name of the program you are using to draw on?

[@Engineer4Free]

You're welcome! All the software and hardware that I use is is listed on engineer4free.com/tools 🤜🤛

[@elvinhasanov5285]

Thanks to you. Question is can we apply this method to the frame problems for finding diagrams?

[@drofeng]

Yes, see my channel for example frame problems.

[@wb3k392]

nice video, thanks!

[@Engineer4Free]

Thanks!

[@Cathodoxism]

Great video

[@Engineer4Free]

Thanks Devin!! 🙃

[@zozz192]

Thank you very much! 👍

[@Engineer4Free]

You’re welcome!! 🙂

[@Sumankumar-zf4fh]

Very nice sir and please make video on RCC

[@Engineer4Free]

Thanks Shekhar, check out videos 32-34 here for RCC beams: engineer4free.com/mechanics-of-matrerials

[@Holyacrobat1]

Could you please do a video on bending & shear force diagrams including equations please

[@Engineer4Free]

Hey Christian I have several that include the equations, they’re just in a different playlist. Please see videos 66-72 here: engineer4free.com/statics 👌👌

[@Holyacrobat1]

@@Engineer4Free thank you ! Love your videos!

[@farasabyan45]

This video alone worths more than my three hours class.

[@Engineer4Free]

Thanks Faras!!!! =)

[@hasanegeylmaz4335]

Thanks so much sincerly

[@Engineer4Free]

Any time!

[@valeriu-iuliansandu-grigor6490]

Nice one, what did you use to draw everything?

[@Engineer4Free]

Thanks! The full list of hardware and software that I use to make the videos is here: engineer4free.com/tools =)

[@maikokyando4596]

Sorry,, clarify me how did you get that value of x?

[@nigel8221]

Hello sir thank you very much. I would like to ask 8:13 is the point of zero shear (crossing zero part in shear) always where you get the maximum moment? Im doing an exercise right now and the maximum moment im getting is not on the point of zero shear.

[@Engineer4Free]

Hey Nigel, yes, where the SFD crosses the x axis you will always have a local max (or min) on the BMD. Also good to know, where the BMD crosses the x axis, you will have an inflection point on the deflected shape. So it sounds like you just have an error somewhere in your work. Double check that you have solved for the reactions correctly.

[@cris660]

Wow!! Thanks sir, I wonder how did you get the 60kN downward force?

[@Engineer4Free]

60kN is just the entire resultant force of the distributed load. It's 10kN/m * 3m = 60kN.

[@cris660]

@@Engineer4Free oh shit hahaha.. I got it now, sorry and thanks sir. God bless! 🤗

[@nnorugaifex9489]

Thanks sir. But I have a question, is the slope for the first parabolic suppose to curve in the 'n' direction or 'u' direction

[@Engineer4Free]

The quickest way to do it is as follows. Pretend that you're going to do a numerical integration, and slice up the triangle shape on the SFD into many skinny rectangles. The area under the curve on the SFD represents change in magnitude across that same section of BMD. So where the rectangles are tall, the change in magnitude will be greater across their skinny width than where they are shorter. If all slices are the same width of dx, then that means a greater change in magnitude corresponds to a greater slope in that region of the BMD. So the tall side of the triangle on the SFD will correspond to the side of the parabola on BMD with steeper slope, and the short side of the triangle will correspond to the more gentle slope on parabola. Also knowing that a positive area on SFD will cause a positive change in magnitude on BMD and a negative area on SFD will cause a negative change in magnitude on BMD, then it always only ever leaves one possible option for the concavity of the parabola. That's a pretty quick and dirty way to do it, but once you get used to it, it's extremely fast. I recommend checking out videos 1-9 here: engineer4free.com/structural-analysis for more examples. I think with more practice it gets easier to notice the pattern.

[@a7medabdelsalam775]

thanks for the great explanation, can you please explain to me how you get A=50KN and why you multiply the 60 by 3m

[@Engineer4Free]

Hey, the A comes from the sum of force equation in y direction. I skipped the work. Sum of forces in y = A + B - 10kN*6m - 20kN = 0 .... A + 50kN - 10kN*6m - 20kN = 0 ... A = 60kN + 20kN - 50kN ... A = 30kN. And for why 60 is multiplied by 3: that is happening in the sum of moments equation about A. The resultant of the distributed load (overall magnitude) is (10kN/m)*6m =60kN. You need to also know how far away from A this is acting, and the location of a resultant for a uniformly distributed load is in the centre of it, so 3m from either side if it's 6m long. So the moment caused by the udl is 60kN*3m =180kN. Hope that clears it up!

[@adoomyforever3673]

@@Engineer4Free thank you so much

[@kingsiddiqi9585]

very nice i like it. sorry could you tell me which software is this.

[@Engineer4Free]

Thanks! I have a full list of all the hardware and software that I use at engineer4free.com/tools Cheers =)

[@faizanalam855]

you missed out in the last part of the SFD part where you are supposed to connect the line back to 0 in the x axis as the last support gives a force of 30 kN upwards so from -30 + 30 = 0 so just draw a perp line from the end point and stop at the y-axis = 0. i hope you get what i meant.

[@Engineer4Free]

Yeah it's true. You will sometimes see them with or without that vertical line. As we take the virtual cut a distance dx away from the right hand side support, and as dx approaches zero, the shear remains unchanged. This value of shear that is infinitesimally close to but not touching the reaction is actually we're concerned with. Like if someone asked you what the shear at B is in this case, we would tell them it's -30kN, not 0kN. But yeah should have drawn in the vertical line anyways I suppose!

[@prmusic3086]

Sir i realy thank for you

[@Engineer4Free]

You're welcome =) =)

[@Hud_Adnan]

So much helpful

[@Engineer4Free]

=) =)

[@ersinortagenc5233]

This is helpful tkans. Which program do you use?

[@Engineer4Free]

If I recal correctly, I drew this one with Krita. You can check engineer4free.com/tools for a full list of all the hardware and software that I use for the videos 👌👌

[@aboromh69]

helped alot thx a ton

[@Engineer4Free]

Glad to hear it! There are some more examples here too: www.engineer4free.com/blog/ultimate-guide-to-shear-force-and-bending-moment-diagrams =)

[@yasithprasad7582]

Hey do you videos for triangular force distribution?

[@Engineer4Free]

Not at the moment, only videos with udl

[@marcomorocho9863]

thank u bro!

[@Engineer4Free]

ur welcome marco👌👌

[@augustamoulton2380]

The load on the beam is 10kn/m covering a distance of 6m at the left. You needed to replace the 10kn/m with 60kn (10kn/m*6m) before solving this problem. Your new results should be A=35kn and B=-45kn.

[@WetPig]

The moment is F(force)*x(distance) - to solve for a force applied at a large area you use the mathematical tool of integrals. So the moments integral is F*xdx - the solution is (10(kN)x^2)/2 = (10*6^2)/2 = 10*36/2 = 180kN, if you do the math it's correct, 50 on A and 30 on B.

[@emily8878]

I thought it was wrong at first too, that 60kn would be the answer for that part, until I realised how the distributed load works. One way to look at it is converting the distributed load to a point load at its center, then multiplying that value by the 3m distance from A (center of W from A).

[@evwerenisaacoghenenyerhovw232]

Sir how do u find point of inflection and point of bending moment of this kind of question