Brilliant. My professor threw us that last equation for difference amplifier, but you actually explained how it works. Thank you a ton, my friend.
@MichelvanBiezen3 жыл бұрын
You're very welcome!
@moazelsawaf20004 жыл бұрын
Thanks sir
@gamjam70652 ай бұрын
Great video! The algebra towards the end really had me stuck for a while.
@ezio_g4 жыл бұрын
Beautiful math work out........I tried on my own and gave up. Mine was not bad but didn't get the beautiful part at the end where we can clearly see why making the two ratios R1/Rf = R3/R4 gave us Vo = Rf/R1( V2-V1 ) which is a very easy to see how this circuit is "The Difference Amplifier". I have no problem understanding the electronic but I have to go over the math a couple of times. Nice lecture. Loved it.
@jordanchacko30852 жыл бұрын
best explanation ive ever seen for this topic. analog systems UD class is much easier with playlists
@MichelvanBiezen2 жыл бұрын
Glad it was helpful!
@corysmith45694 жыл бұрын
First and foremost, that's a killer bow-tie. Bow-ties are cool. Secondly, you just saved me a massive headache. I was struggling through this derivation all morning. Your explanation was perfect. I do have a question about this whole circuit though.
@ataurrahman30807 жыл бұрын
Electric field,Electronics etc...All of your Tutorial is best. Good explanation with initial to Application. what a tutorial series.Thank u sir.#Bangladeshi EEE student.
@zamp79276 жыл бұрын
Rahman sab jeety raho
@Sam-rl6ok4 жыл бұрын
Great Dr. Biezen. It is really simplified explaination. Much more simpler than my book's explaination. Best regards to you Dr.
@holmeslaw10194 жыл бұрын
Without deriving the math I had a hard time understanding opamps. Thank you very much.
@أحمدالنقيب-ت3و5 жыл бұрын
Thank you very much, today you have been being my hero.
@punsarawithanage38402 жыл бұрын
Superb❤️ from Sri lanka🇱🇰
@MichelvanBiezen2 жыл бұрын
Glad it is helpful. Welcome to the channel.
@bennetbrooks17 жыл бұрын
Thank you. Your explanation makes the topic easy to understand. What textbook do you recommend for electronics devices and op-amps.
@themanthis8377 жыл бұрын
How do you calculate this if you add a resistor from Va to gnd ( when you want to amplify a bridge case )
@avdallinone37987 жыл бұрын
nice explanation sir I searching for this frm a week and now I got it from your video thank u sir
@morto00x5 жыл бұрын
Had this exact question at a job interview. Got stuck at that very last step lol.
@abutaymiyyahlectures3 жыл бұрын
damn i didnt know jobs ask this kind of questions :/. what job btw?
@Mikebigmike9411 ай бұрын
That's brutal lol, this is more algebra tricks than engineering so i hope it wasn't an engineering job. It's one thing finding the output in terms of the input but to get it into the final equation is just pure maths i think.
@lhaellor Жыл бұрын
What did you do at 6:45 to simplify that fraction what is the story?
@lhaellor Жыл бұрын
Can anyone explain or name what is this algebraic trick at this part?
@MichelvanBiezen Жыл бұрын
Dividing by a fraction is the same as multiplying by its inverse. 12 / (1/2) = 12 x (2/1) = 24 or (2/1) x (12) = 12 / (1/2)
@ander16515 жыл бұрын
Excellent! Thank you so much for your explanation!
@adrianhove62116 жыл бұрын
best explanation ever, thank you Sir
@sandlertossone18135 жыл бұрын
Can you get two different answers if you use the first circled equation and the second shorter one? My Rf/Ri=R3/R4=2 and my V1=-5 and V2=6. Using the longer equation I get 16V and the shorter I get 22.
@lhaellor Жыл бұрын
What did you do here at @8:13 ?
@MichelvanBiezen Жыл бұрын
We multiplied the quantity inside the parentheses by the fraction Rf/R1 and re-arranged the terms.
@audar48322 жыл бұрын
I have an question please we use this law only when resistance are equal? (R1=R4 and Rf=R3)
@MichelvanBiezen2 жыл бұрын
They don't have to be equal, but if you do make them equal you will have that simple relationship for Vo
@audar48322 жыл бұрын
@@MichelvanBiezen i used the law directly to get an unkown in Nelson james reference but it is wrong the reference used th method of node voltage and get a nother solution😅🤔
@MichelvanBiezen2 жыл бұрын
Is the setup exactly the same? Or is there a difference in the way the op amp is connected?
@audar48322 жыл бұрын
@@MichelvanBiezen yeh it's exactly the same
@leonitasn95275 жыл бұрын
so in op amp vb=vs is always the case ? I mean the difference between vb-va must ALWAYS be approx 0 ?
@leonitasn95275 жыл бұрын
O i got it .. it just depends if it’s connected to the ground or not .. if yes the potential is 0, but always vb=va
@johnnycanazon8 жыл бұрын
Would it have been a bad idea to have simply jumped into using voltage devision to solve for Vb considering no current into V+ or could this cause problems in other situations?
@MichelvanBiezen8 жыл бұрын
That should work.
@kochuranilalu4382 жыл бұрын
Thank you sir. You made it clear👍
@MichelvanBiezen2 жыл бұрын
Glad it helped
@luketaylor59177 жыл бұрын
How could you amplify the mV output from a thermocouple to a 1-5 volts signal using an op amp?
@dachew576 жыл бұрын
Use non-inverting Op-Amp (not Difference Amplifier). Av = 1+(Rf/R1). For example, to convert the output voltage of an analog temperature sensor, let's say a TMP35, to a 0-5v for an Arduino, set Av = 4 (Rf = 33k, R1 = 11k). Then, TMP35 maps very nicely to Arduino supply range. Of course, adjust gain for 3.3v system. TMP35: 25C = 0.250v and 125C = 1.25v. Op-Amp transfer function is f(x) = 4x, where x is TMP35 output voltage.
@irmuunbilig8218 Жыл бұрын
thank you so much, god bless you 😇👏🙏
@MichelvanBiezen Жыл бұрын
Thank you. Glad you found it helpful! 🙂
@soningadong86357 жыл бұрын
How is the direction of current across the feedback resistance determined?
@MichelvanBiezen7 жыл бұрын
Current flow from high potential to low potential (conventional current flow). If we don't know, we just pick a direction and if we picked the wrong direction the current will come out negative.
@thomsonkthomas7 жыл бұрын
osm sir... understood the topic clearly...thank you..
@luigimirabelli55046 жыл бұрын
Great explanation! Thanks Prof!
@2TAK3222 жыл бұрын
nice one
@MichelvanBiezen2 жыл бұрын
Thanks
@varnam66464 жыл бұрын
why do we use R4?
@geertvancompernolle25865 жыл бұрын
I find the calculation of vo quite complex (between minute 7 and 8 something). When I do the same calculation my way, the result is vo = v2 (R4 / (R3 + R4)) ((R1 + Rf) / R1) - v1 (Rf / R1) Sorry but it's difficult to type it down like that. Anyway, by going for that shape of formula, it's easier to see what happens if R1 = R3 and Rf = R4 on one side and R1 = R3 = Rf = R4 on the other side. But again, the end result is the same (many paths lead to the same goal...). Apart from that, you're one of the very few that can really explain how a difference amplifier really works. Thumbs up!
@agstechnicalsupport6 жыл бұрын
Thank you Michel !
@Thabang_Kgatla12 жыл бұрын
Thank you so much
@MichelvanBiezen2 жыл бұрын
You are welcome.
@paulferrer21083 жыл бұрын
Prof. van Biezen, are we able to use superposition principle to derive the formula?
@MichelvanBiezen3 жыл бұрын
Any method is a valid method. Some methods are easier for certain applications than others.
@ahmedelaraby76563 жыл бұрын
This guy is the fucking best Thanks prof
@MuhammadUsman-lx6ye Жыл бұрын
Sir what if R3/R4 does not equal R1/RF
@MichelvanBiezen Жыл бұрын
There are many different configurations for different purposes. We cover some of them in other videos. This is the configuration for the difference amplifier.