i don't normally comment on videos especially as this was made years ago but i have to say that this is the most helpful video on electrolysis i have seen so far and trust me i have been watch ALOT ahaha
@dog3602 жыл бұрын
probably one of the only educational youtube videos i’ve ever found helpful!
@debra69684 жыл бұрын
Wow, superb explanation. Nicely penetrating and sinking into the system. Thanks so much for this video. Full of passion and commitment. Seems you have done your HW, so well planned and precise. Loads of love from Sri Lanka. God bless you :)
@magnuswootton61813 жыл бұрын
whatever you do, if u actually do this electrolysis stuff watch out for poison gas emission!!!
@omkarpawar15945 ай бұрын
Loved the mehandi on your hand and the lecture too, Thanks a ton.
@yashkhandelwal6414 жыл бұрын
The video was Good and really explained clearly and properly! Thank u so much!
@golammorshed72603 жыл бұрын
OMG I had this one confused for almost months and you made it clear within 5 minutes TYSM :)
@sahilagarwal66014 жыл бұрын
Demn she has got mehendi on
@yashkhandelwal6414 жыл бұрын
Lmaooo
@Rarafb27614 ай бұрын
What I focus on instead of trying to understand chem... 🥲
@samsononi71642 жыл бұрын
Amazing explanation from Henry and Esther Thank you
@SalsaKingoftheApes2 жыл бұрын
Very clear, super stuff! Mr J
@ChemJungle2 жыл бұрын
Glad it was helpful!
@MuhammadHassan-jq8jp10 ай бұрын
What a video, honestly teach me chemistry I'd pay anything to study from you
@omarmoustafa66725 жыл бұрын
That was really helpful!!! Thank you so much!🙏🙏🙏
@drsirmechemistrymaster2 жыл бұрын
Good work... Coincidentally I have done the demonstration experiment for this on my channel.... I see we are in tune... Thank you madam
@jitendraempire56276 жыл бұрын
Well explanation
@SethuChandra3 жыл бұрын
omg explained SO WELLL
@SarahNakalembe-r2k2 күн бұрын
Hi
@angel-nr3vg3 жыл бұрын
perfect explain it is so complete .it make me totally understand.thanks
@ruba5884 жыл бұрын
in love with your channel!! Thank you so much for your videos
@galaxy_tv104 Жыл бұрын
1:22 Can you explain why sulfide never gets discharged? is it because it has a higher reduction potential?
@345surf_excel_washingpowderАй бұрын
Yes it lies at a higher position in the electrochemical series therefore it has a property to undergo reduction better than others
@boliusabol822Ай бұрын
there is no sulfide, it's sulfate. Sulfate has a very low oxidation potential. . You can look up anion discharge series, you'd see sulhate and nitrate low. And Chlorine Bromine and Iodine high. There's OH- in the series too but it's a funny one 'cos while it has a high oxidation potential, it has poor kinetics so its tendency to discharge is not so high. Also when you have a copper anode, the anode itself oxidises, no anion oxides at it.
@readoryx3733 ай бұрын
Could this apply to rocks high in Iron, by placing the iron ore in an electrolyte of iron sulphate, an iron cathode?
@ivygracelane Жыл бұрын
you have saved my life thank you
@energyforever7202 жыл бұрын
@chemjungle i heard you say the sulfate never comes out, but when i did electrolysis of copper sulfate a strange yellow thing appeared. I was using a 5 volt power supply and graphite electrodes, which made it very clear to see the yellow thing on the dark black graphite electrode. Idk what it was but my guess was elemental sulfer. Any ideas why that happened?
@DaveFer4 жыл бұрын
Hey now. Thanks for this educational video. I've been doing chem experiments with my kids while we're quarantined and I have question perhaps you are uniquely qualified to answer: I have several grams of Cu that we precipitated and dried from a reaction of CuSO4 + Al. It's a tiny amount and probably contaminated. I'd like to use electrolysis to purify it and I have copper thread that I can use as an cathode (anode?). I can weigh the precipitate and the copper thread prior to start. And I'd like to show my kids how all the copper in the precipitate is purified and deposited on the copper thread ... both visually and by weight. My question is, which electrolyte should I use, CuSO4 solution? Acetic acid? NaCL solution? Which electrolyte WILL NOT donate Cu or any other atom to the cathode? Will the CuSO4 donate to the cathode? I'll probably do this in a large test tube. I'll try using a graphite rod (pencil "lead"?) on one side and copper thread on the other. (I'll think the pencil graphite will conduct ... I'll test it.) Here's our playlist. You're input would be highly valuable. kzbin.info/aero/PLikL-gQhJ0DmknULDIeGei3l2Q__dEfI7
@ChemJungle4 жыл бұрын
Hey! I think you've probably got an amount of impure copper from your reaction. In order to make this work you need to use your impure copper as the anode and your pure copper as the cathode. If your product isn't suitable to be used as an electrode then you might struggle to purify in this way. At home, I wouldn't use any of these electrolytes though - CuSO4 will deposit Copper from the solution, acetic acid doesn't conduct well, NaCl will produce Chlorine as a byproduct which is super toxic.
@truth31372 жыл бұрын
Great video!
@ChemJungle2 жыл бұрын
Thanks!
@antonisaristidoukokkinou99486 жыл бұрын
how does the copper ion go to the anode when the anode attracts negative ions and why in the half equation for the anode it doesn't have a positive charge but is simply its element? are you saying that it first got purified from the cathode and this whole time nothing was happening at the anode so it went to the anode to oxidise??? I'm a confused 16 year old help.
@ChemJungle6 жыл бұрын
Eeeek I'm sorry this has confused you! The copper ions go to the cathode and get reduced to copper in both scenarios. At the anode, oxidation happens. There are a few things in the solution that could lose electrons: OH- SO4(2-) or the Cu in the electrode , but actually the Cu in the electrode is the most easily oxidised of the 3 options so it goes to Cu2+ in the solution.
@samina91315 жыл бұрын
@@ChemJungle why did copper lose electons just to gain it back
@Alex-xq5qz Жыл бұрын
This help me thanks ( from a prepa french student )
@varpilajain58954 жыл бұрын
hey sis...am in luv with ur channel completely...my doubts are cleared explicitly. i had doubts abt explanation on preferrential discharge but by seeing ur video..i am delighted...keep doing well| "GOOD DAY"!!!!!
@wilsonbashaija22932 жыл бұрын
after the copper from anode goes to cathode and the sand sinks, what is that small thing that is left after copper refining, that is being compared to the recent big pure copper
@ChemJungle2 жыл бұрын
If you let the electrolysis run forever then it would stop as soon as the anode stopped conducting electricity because your circuit would be broken. There might still be very small amounts of metal left but it's mostly going to be the rock it started as remaining :)
@mochimoy88653 жыл бұрын
The Explanation was very clear, thank youuuu
@mariaaxp02 жыл бұрын
i legit love you thank u
@arty62872 жыл бұрын
GOAT video love u
@varpilajain58954 жыл бұрын
i also had a doubt...anode attracts negative ions..but in this case the copper atom turns into ions and gets discharged....and on what basis does copper gets oxidised in preference with sulphate and hydroxide ion....could u pls clear my doubt
@rosemarychacko36903 жыл бұрын
Plz mam I am also confused
@boliusabol822Ай бұрын
Electrons are pulled from the copper anode and that oxidises the copper anode itself. That's the oxidation that occurs there. It's of the anode itself. If it were a graphite anode then it'd attract anions. One has to know whether the electrode itself is reacting, or ions at it are reacting. A metal cathode will not react, but a metal anode will oxidise. Graphite would be inert whether it is the anode or the cathode.
@tashspond3 жыл бұрын
And what amp/volts are necessary?
@turboslayer9473 Жыл бұрын
Thank you so much Really helpful
@CLR-mx4bu6 жыл бұрын
I don’t understand why the copper2+ becomes copper but the SO2- doesn’t become SO4? Why doesn’t the least reactive one always get discharged?
@krivansemlani79844 жыл бұрын
smart
@boliusabol822Ай бұрын
Something at A level or AP, rather than GCSE, would show that The SO4^2- has a very low oxidation potential. (this can be seen looking at a table of reduction potentials). So SO4^2- will stay in solution. The metals below hydrogen in the reactivity series (low in reactivity series), don't tend to stay reacted in their ionic compound, they tend to reduce and become neutral. A table of reduction potentials show that Cu^2+ has a high reduction potential. Very unreactive ones in the reactivity series are strong candidates to get discharged. We don't see reactive metals like potassium getting discharged, but do with a metal much less reactive, like Copper.
@gikscollections62802 жыл бұрын
Good work
@manishkumartiwari67622 жыл бұрын
Please make videos on the whole chemistry part of 11th and 12th.
@abigalebailey1823 жыл бұрын
What was the amperes that was used ?
@sengkathirparri9311 Жыл бұрын
Thank You So Much !
@lahiruperera380510 ай бұрын
Some people write anode reaction like this 2H2O ->O2+ 4H+ + 4e What is the difference
@ChemJungle10 ай бұрын
Both processes happen, and both make the same products so in most syllabuses you can write either answer and score the points... The water one you have here is a little more "correct" as the water would be in higher conc than the OH- so would be more likely to oxidise (the last gcse syllabus I taught wanted the OH- one though hence why it's in this video!)
@aashishgottumukkale30434 жыл бұрын
How about carbon electrodes? Do they get involved?
@ChemJungle4 жыл бұрын
Nope :) Graphite is a form of carbon - these electrodes are inert in this scenario
@covid-21delta992 жыл бұрын
Graphite (Carbon) Electrodes only get involved at high temperatures with Oxygen and some other Elements...
@magnuswootton61813 жыл бұрын
watch out using electrolysis with sulphates, cause u might get mustard gas. it is actually magnesium sulphate that does it, copper sulphate doesnt, cause of extra complications, its not a simple model.
@nellvincervantes32235 жыл бұрын
Why you choose the lower reactivity?
@shreyabhatia55075 жыл бұрын
^^??
@daemonk7568903 жыл бұрын
If it's lower reactivity it is more able to receive an electron and therefore get reduced. It's like the opposite of how you explain the group 1 metals getting more reactive as you go down the group. The outer shell electron is further away from the nucleus so therefore it is more easily lost and the metals get more reactive.
@waseemahmed56825 жыл бұрын
Really informative.... Good work....
@DonaldSleightholme6 жыл бұрын
can copper sulfate be used as a replacement for mercury in a Faraday motor 🤔🤷♂️
@jailnet5 жыл бұрын
OK, why was the solution copper sulfate present in refining of copper if we are not separating anything from the electrolyte?
@magnuswootton61813 жыл бұрын
isnt it copper coming out?
@jailnet3 жыл бұрын
@@magnuswootton6181 concentration of copper ions remains constant in case of using pure copper as cathode and impure copper as anode. Explaination copper ions are both being removed and replaced at the same rate because formation (oxidation) of copper ions at anode happen at same rate of removal (reduction) of copper ions at form atoms at cathode. I hope this made sense
@covid-21delta992 жыл бұрын
You actually are separating Copper +2 ions from the Electrolyte which then gets reduced at the cathode to form Copper Atoms
@leslieedirisingha53332 жыл бұрын
Please explain why in the instance electrolysis of aqueous cuso4 using copper electrodes the anode reaction becomes copper oxidation process 😭
@ChemJungle Жыл бұрын
Because copper is more easily oxidised than the hydroxide ion or the water that's present. It's always the thing that's most easily oxidised that will lose electrons :)
@alcurist2 жыл бұрын
THANK YOU
@hixe73998 ай бұрын
what happens to the SO42- ions and H+ ions?
@ChemJungle8 ай бұрын
They stay in solution :) So you're left with sulphuric acid in the solution
@kurulusxdestan5 ай бұрын
thankyou so much for this ❤❤❤❤❤❤
@mingiiyaa56733 жыл бұрын
Thank you so much ✨✨
@Oli-vj4pi4 жыл бұрын
thanks so much
@minkhant16834 ай бұрын
Thanks alot!
@mechackkaba85784 жыл бұрын
Well done
@nelsonandong263 Жыл бұрын
Good job
@ChemJungle Жыл бұрын
Thanks :)
@TheCerberusInferno4 жыл бұрын
What gases are produced in this reaction ?
@ChemJungle4 жыл бұрын
You get different products depending on which electrodes you use
@manalkhan50486 жыл бұрын
Thank you!
@ChemJungle6 жыл бұрын
You're welcome :) hope it helped!
@dribrahimel-nahhal24772 жыл бұрын
Thanks for this vid
@chamodrashmitha74545 жыл бұрын
Thankyou very much madam
@devanshimishra99695 жыл бұрын
What is the observation? When u used copper electrode in copper(||) sulfate
@ChemJungle5 жыл бұрын
You would see the cathode getting bigger (still orange with the copper) and the anode getting smaller. The blue solution would stay the same colour as every Cu2+ that gets used up, another one gets released into the solution (if you have graphite electrodes it gets paler and eventually colourless). No change to H+/OH- concentration so no change to pH.
@abhilash55654 жыл бұрын
Good
@chandakatongo5992 Жыл бұрын
Thankyou sm
@ChemJungle Жыл бұрын
You’re welcome 😊
@williamtamale94694 жыл бұрын
Supper gal....only the dull wouldn't understand yr crystal klear explanation
@ubinin79236 жыл бұрын
This helped a lot
@aguyfromaimagination9983Ай бұрын
Maccha pls teach me as my teacher pls
@kcaptured64593 ай бұрын
Unne mehndi layi hui aye
@husnainali31235 жыл бұрын
Hi mam i need your help please reply me
@dennismihailov1363 жыл бұрын
what you want
@krivansemlani79844 жыл бұрын
mehandi laga ke rakhna doli sajane ke rakhna
@inkosiivumilethapelo30002 жыл бұрын
Too fast. Had to watch the video many times
@krivansemlani79844 жыл бұрын
why coppaaa! why not copper?
@johhnylhandes1343 жыл бұрын
lol she fitttt
@ssathiabalan3 жыл бұрын
pls slow down with ur explanation, didnt pick up anything from the video. Im sorry. I didnt find this useful.