Electron Domains, VSEPR and Determining Molecular Geometries

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Пікірлер: 21

@whitwat 7 ай бұрын

I don’t usually find this for most educational videos, but your explanation is so clear. Everything makes perfect sense. Thank you!

@ChemSurvival 7 ай бұрын

Thanks for the kind words. I'm so glad you liked the presentation!

@annabellewatson9325 5 жыл бұрын

Thank's so much for making this video! I just watched my lecturer explain the same thing, but wasn't understanding the seesaw shape until I watched this! You explain it perfectly and thoroughly! I look forward to referring to more of your videos for help.

@JackOfNoTrades_ 8 ай бұрын

Putting this here to ask if you passed your class? :D

@Jessica-dr4wf 3 жыл бұрын

This helped me understand electron domains and molecular geometry so much better! Thanks.

@dr.anwaarabdullah3064 6 жыл бұрын

I have big benefits from this video ,thank you.

@ezekhielahui5503 Жыл бұрын

Why in the AX3E2 case are the non-bonding pairs arranged in an equatorial and not axial position? In the axial position each non-bonding pair interacts with 4 other domains, three of which are at 90° and one at 180°. In equatorial position, however, it has 2 interactions at 90° but two at 120°. So I wonder why one interaction at 90 and one at 180 are not better than two at 120 also considering that with the first configuration the two non-bonding pairs would be as far apart as possible? In molecules like ClF3 a planar trigonal geometry seems more sensible to me rather than a "T" one.

@khryzcv 10 ай бұрын

Big help. Thanks a lot!

@mafuzwane2189 2 жыл бұрын

thanks your so much Mr

@ChemSurvival 2 жыл бұрын

Glad to be of help! Please show your gratitude by subscribing and sharing my channel content!

@jared_kc3155 4 жыл бұрын

Thank you for this, this helped alot

@ChemSurvival 4 жыл бұрын

Glad it helped! Thanks for liking, sharing and subscribing!

@RayDayz7 5 жыл бұрын

Great Work. Very Helpful

@SorareBaller 3 жыл бұрын

very good and informative

@RapManJak 7 жыл бұрын

Do you happen to know if the method based on counting sigma bonds and subtraction 1 to predict hybridization is true for every compound? Or it fails in particular cases? For example: CH4 - 4 sigma bonds - 1 = 3 (sp^3) CO2 - 2 sigma bonds - 1 = 1 (sp)

@ChemSurvival 7 жыл бұрын

This will fail any time there are lone pairs around the central atom (lone pairs also occupy hybrid orbitals). The best mnemonic is to count (sigma bonds) + (lone pairs) - 1 to determine how many p orbitals participate in hybridization. It is also worth noting that this only works up to sp3 hybridization. If 5 or 6 domains are present, then d orbitals get invloved (sp3d and sp3d2).