I appreciate the feedback! I will be sure to correct the oversight in the next version of this video!
@thembelihlembayimbayi71527 жыл бұрын
Great job explaining the molecular orbital theory. I was having trouble understanding it, thank you so much. I highly appreciate this video
@RetreatRetreat12310 жыл бұрын
concise and very easily to follow. good work y'all!
@ChemSurvival11 жыл бұрын
Hi Satyaprakash. I use a combination of several software suites, including Microsoft Office, Adobe Illustrator and Photoshop, as well as some specialty chemical drawing programs. Each 5-10 minute micro-lecture takes anywhere from four to twelve hours of work to complete. They are all written, edited and produced entirely by me. I hope that you feel they are worth it!!!! If you agree that they are, please subscribe and pass on the channel to your friends.
@isawang24129 жыл бұрын
I love the video and enjoy the orbital vertulization. Although, there may be 2 mistakes in the video: (1) for the N2 molecule, the 2p pi orbitals should be lower in energy than the case of the 2p sigma ( en.m.wikipedia.org/wiki/Molecular_orbital_diagram#Basics). (2) for the O2 molecule, triplet states should be formed rather than singlet.... -Hai
@magmasurfer11 жыл бұрын
Unbelievable how simple you made it. Thanks alot!
@ChemSurvival11 жыл бұрын
Hi Breanna. I think I was trying to convey that the electrons fail to screen the nuclei from one another, causing the mentioned 'repulsion'. A fair comment, though, as I can see how this could easily be misinterpreted to mean that the electrons are repelling the nuclei (which, of course, they are not!!!).
@ABHI-zm9pi5 жыл бұрын
Thanks
@hafsabahadar72824 жыл бұрын
this visual repsresentation was extremely useful for understanding, thank you so much :)
@froyoyoyo29574 жыл бұрын
I am still confused as to how and where pi bonds come from? Is the pi equal to 180 degrees which is why those particular bonds are flat and straight across compared to the others that are vertical or diagonal?
@jordanwolfman89087 жыл бұрын
Great video! This clears up any questions I had about MO diagrams.
@ChemSurvival7 жыл бұрын
Thanks, Jordan. You may also want to note that I posted a revised version of this lecture, accounting for sigma-pi mixing here kzbin.info/www/bejne/gZa1g6d_j6ukY68
@deerich82808 жыл бұрын
Great job explaining the molecular orbital theory. I was having trouble understanding it, thank you so much.
@ShamoyRahman8 жыл бұрын
Your visualizations are amazing. Let's collaborate together on making the world's best Chemistry guide.
@ChemSurvival11 жыл бұрын
Thanks, Craig. Please subscribe and share with your friends!
@wardahchoudary72769 жыл бұрын
its just awesome thanks alot professor :) stay blessed
@fazeelabintemuhammadyar38828 жыл бұрын
how bonding and antibonding orbitals are arranged in a molecule? do they both form at same time and present at same time
@harshaldabhane79844 жыл бұрын
Nice video sir, make it easy to understand MOT, Thank you
@yannickduchene3057 жыл бұрын
At 00:02:43, sound volume goes down.
@breannacraft455111 жыл бұрын
When you discuss the anti-bonding orbitals as destabalizing the bond...you say that the presence of these electrons in this type of orbital pushes the nucleii closer together by electro-static repulsion. I am certain you mean..."farther apart". Otherwise, a very helpful micro-lesson.
@nishanthbm60792 жыл бұрын
Can anyone pls explain me how can 2 molecular orbitals overlap in phase and out of phase simultaneously ...i mean how can they interfere constructively and destructively at the same time ? ...the orbitals should either overlap in phase and form bonding orbital or should overlap out of phase forming anti bonding orbital ..but how can both happen at a same time ?
@sahirwar11 жыл бұрын
The presentation is made in which software?
@iliriacum6669 жыл бұрын
How I would know that N forms Pi bonds in the diagram of energy..I got sigma bond but this Pi looks like strange.. I mean is any order that I can know how the π bonds form in this diagram... From which orbital is bonding decided (1s, 2s or 2p)?
@mahdaftabkhan93758 жыл бұрын
Thank You Prof. It was really helpful.
@nikkihuang76354 жыл бұрын
This was so helpful, thank you!
@shirleeywang10 жыл бұрын
that was super clear; thank you so much! :D
@ChemSurvival10 жыл бұрын
Thanks for watching! Please pass it on!
@hamahama79828 жыл бұрын
why aint we consider ABMO &BO of s subshell in bond order?
@puttaswamyprajwal82407 жыл бұрын
then how does endothermic & exothermic reaction accure,when there antibonding is there
@HosterJack5 жыл бұрын
Great lesson, keep it up!
@alialyami924210 жыл бұрын
How you did the bond order and ended up with 1 as final answer. 1*0/2= 0 because of the ZERO in numerator. Thank you and please correct.
@ChaosGodII10 жыл бұрын
it's +, not *
@doodh_jalebi9 жыл бұрын
+Ali Alyami The formual is: (Bonding electrons - Anti bonding electrons)/2 There is a '-' in there not a '*'
@sameerkhnl110 жыл бұрын
Thanks professor. Helped a lot
@ChemSurvival10 жыл бұрын
I'm so glad that you found it helpful! Thanks for the feedback.
@hussainashabbir10388 жыл бұрын
Thank you... your explanation was very helpful :)
@divyamsheth87658 жыл бұрын
what about 2s - 2p mixing in molecules formed by atoms of less than 16 atomic number ? I guess it decreases the energy of π and increase the energy of sigma bond in nitrogen , If am not wrong .
@ChemSurvival8 жыл бұрын
+divyam sheth You are correct. The sigma and pi relative energies of nitrogen are not accurately represented here. I've been meaning to update/correct that oversight for a while now. I will be creating a new version of this video later this year as some of my other projects wind down.. Thank for the comment!
@tamoghnahaldar64958 жыл бұрын
Marvelous. Learnt a lot
@alialyami924210 жыл бұрын
You may use this correct formula. 1/5(bonding orbital* anti bonding orbital)
@TommyKonjo10 жыл бұрын
Doesnt oxygen have 6 valence electrons and nitrogen have 5 valence electrons ?
@breannacraft455111 жыл бұрын
Also the ordering in energy of the 2p sigma and pi bonds are different for nitrogen and oxygen homonuclear diatomics. You might want to correct and add these things. I would love to help you edit before you publish if you need it.
@suffixable10 жыл бұрын
Can yo help me out. What does this line mean"Things look different in different directions for molecules than their constituent atoms(mostly losing symmetry due to another atom interacting with electron). Think only of the simplest example, H-h, to appreciate why. Here space is indelibly marked by line joining(bond) the two nuclei, which defines, once and for all, what was previously an arbitrary Z-axis. There is one special direction plain to see. and (owing to this pointer in space) the molecule is denied of the s-p-d-f orbitals of hydrogen atom. Those familiar wave functions derive slolely from 1/r coulomb potential and spherical symmetry of the atom." ( My question, why did those orbitals were denied in hydrogen gas. This paragraph is talking about shape and how orbitals are not looked. I really don't understand. Can you make it clear)
@vfgrfbgrb8 жыл бұрын
what is 2s 2p how do they get labeled Tyler dewitt
@jithinkumar22899 жыл бұрын
very nice can understand clearly
@misseon1 Жыл бұрын
8:40 mistake - paired electrons. Must be unpaired, according to Hund`s rule. You got it right on another video (at ca12 min.) kzbin.info/www/bejne/gZa1g6d_j6ukY68
@pranavdhawan44714 жыл бұрын
thank you this helped a lot
@vadivelang24154 жыл бұрын
i want to this ppt sir....
@craigray104811 жыл бұрын
Very helpful!
@misseon1 Жыл бұрын
Only oxygen molecule have 2 unpaired electrons with same direction? en.wikipedia.org/wiki/Oxygen#/media/File:Oxygen_molecule_orbitals_diagram.JPG Thats why that molecule are paramagnetic...?
@sumitsen588511 жыл бұрын
Thank you very much...
@ChemSurvival11 жыл бұрын
You are welcome! Don't forget to subscribe!
@PreethaDatta10 жыл бұрын
Thanks!
@sollinw4 жыл бұрын
brilliant!
@reeeeeks111 жыл бұрын
yeah the pi for n2 should be lower than sigma......EXCELLENT VIDEO THOUGH
@StayAware98 жыл бұрын
you are awesome thanks
@Windsrave311 жыл бұрын
thank you
@ChemSurvival11 жыл бұрын
Hi Breanna. I am always down for a little 'peer review' when it comes to my videos. Especially some of my older offerings like this one. Contact me by email through my website if you would like to talk.