Electronic Devices: Continuity equation

[@narayansharma8797]

Excellently explained~ You are helping me in my 2nd year Btech in Electronics! God bless you.

[@anshumansingh8513]

Hello sir i am in btech ec 2nd year. Help

[@thanos2101]

Thank you so much. Greetings from an electrical engineer from Greece!

[@gopikrishnan1827]

while exploring the web for EDC content I came across this channel on youtube. wow, I have come to the right place for preparing. content and the way you deliver the concepts are really good. especially this lecture the lake analogy was a great one.

[@maroon_passport]

i never thought it would be this easy!!!! thank you sir, a ton! 😊😍

[@USHAKIRAN-yg2bi]

Excellent video

[@md.arafathossain1025]

Complex explanation from textbook made me think this in a very complex way. I didn't think this could be understood in this easy way. Thank you very much from Bangladesh....

[@deepthi4238]

This is a superb video...understood Continuity equation very welll!!! Thank you so much Sir

[@deepvision8877]

This is a very detailed and most importantly, clear explanation thank you. The only feedback I would give is that you did not fully explain why we consider the current going in and going out as being a separate cause to the generation and recombination rates. In other words, that equation suggests another mechanism for why the current entering the region can be less than the current exiting. I would have thought that the difference in the currents would contain the generation and recombination rates.

[@kamraprdp]

masterpiece!! I bet no one could explain it better than you. Analogy also given. Thanks :)

[@AnilGupta-py6vx]

Thanks a lot sir .. Tomorrow is my exam this help me a lot

[@ramjeetpatel7414]

What a concept sir....

[@trupti4742]

Awesome explanation... finally understood the continuity equation Please sir make videos for EMT

[@pragatisharma111]

Superb explanation!

[@subrotodeb5693]

Thank you..Most of my doubts are clear... Happy Teacher's Day...you people deserves it...for the very suitable analogy provided during the session..

[@alfredoespinoza2968]

Good video, sir. Very well explained. Thanks.

[@prateekverma73]

What a simple n easy to understand. Thk you sir

[@429sahilahammadshaik2]

Simple.... And Excellent explanation

[@AbhishekKumarSinhaGo2]

Very nicely explained and to the point. All 11 mins is worth

[@psinha6502]

Ur explanation is very conceptual unlike others. Keep it up . And also work on perfection

[@ehaba6457]

Great video!! It provides us with simple explanation

[@milandeepsinghbhalla3307]

great u explained it by making it look so easy spatially that LAKE example was awesome.....

[@MohitK96]

best and most easiest explanation ever....

[@arpitjoshi8717]

Gr8 explaination Sir👌

[@mohitjain5685]

Awesome way of explanation

[@anujaggarwal7178]

nice explanation

[@arifkulkarni163]

Very Nicely Explained... Thank you very much... :)

[@ankitjoon7320]

excellent explanation, even a layman can understand!

[@adityasiddheshwar7816]

Amazing Explanation!

[@raghavibhoopathy4651]

Excellent video. Thanks

[@mb083skfaheem9]

Thank you sir i dont know what's going on but i can write this easily in exam 🤝💖

[@MohdHilal]

thank you very much, very well explained

[@emadeddin_]

Best of Best Dear ♥

[@geethanjali1883]

fantastic expln.. no one can better explain than he did....

[@NIDHISINGH-gi7lj]

Thanks.. For making the concepts so clear !!

[@godsrighteousness5003]

how old r u? You must be super smart

[@nishapawar3368]

Ur every video I watch satisfies :)

[@sagarnain7774]

best video ever

[@nagavarshinimayakkannan808]

thanks for providing me such a nice video

[@MrSrinivasbandi]

Excellent explained

[@akashsardar495]

Thanks a lot ..sir 😃😃

[@shobhitpandey8821]

anology fadu thi btw

[@shilpanair9664]

thank u soo much for this video

[@ansaine]

damn nice explanation!

[@curiousbud2366]

Sir haynes Shockley experiment is missing from your lecture series

[@TheMyPgk]

Perfect...

[@shahabuddinshaikh1274]

thank U Sir.................

[@MuhadisaishaqZehra]

Thank u

[@samikshapandey295]

Thnx a lot sir

[@navinrs4910]

In a reference book The continuity equation of electrons in P type semiconductors is having different sign from yours (Can you say about this ?)

[@shubhamnayak9369]

Kindly reply if anyone gets my question: dn/dt is +ve when g is greater and positive and dJ/dx is positive ..but dJ/dx is J(x+∆x)-J(x) .. so for dJ/dx to be positive J(x+∆x)>J(x) ..but we have seen that J(x+∆x) should be less than J(x) for no. Of electrons inside the box to be positive.... Plz clarify

[@navaneeth_anand]

Oh thank you so much.

[@manichandu2406]

thanks you very much

[@sridharchitta7321]

The continuity equation for conductors in simple DC circuits is seldom found and derived in textbooks though derivations in case of semiconductors are found in several textbooks. The charge density and current density functions are related by the continuity equation (see Electricity and Magnetism by Edson Ruther Peck, McGraw Hill, 1953) which maybe derived by applying the principle of conservation of charge. Since most textbooks on circuit theory do not discuss this important aspect of the conduction process in the dc steady state in particular, I have discussed this in textbook 4 (see last frame of video 1 to be discussed below). In its most general form the equation of continuity is ∂J_x/∂x + ∂J_y/∂y + ∂J_z/∂z + ∂ρ/∂t = 0. (Eq. 1) as derived from the conservation of electric charge law. The current density J in an isotropic medium is given by the relation J = σE (Eq. 2) where E is the electric field intensity and where σ is the conductivity of the medium. It is also written from Eq. 1 as ∂J_x/∂x + ∂J_y/∂y + ∂J_z/∂z = 0. (Eq. 3) when there is no excess charge in the conductor or that there is no unpaired charge density (lattice ion and conduction electron). In the absence of emf in a region in the circuit (say, away from the source or battery and within a small section of the conductor or a resistor), the total electric field E, may be expressed in terms of a scalar potential function U; E_x = - ∂U/∂x E_y = - ∂U/∂x, and E_z = - ∂U/∂z (Eq. 4) Eqs. (2), (3) and (4) characterize the current flow within a region of a homogeneous, linear, isotropic conductor where there is no emf. If a dc circuit of a battery and a wire is laid in a straight line along the x-axis then evidently, the presence of surface charges will guarantee that the total field E will be a constant E_x along the axis in the region. Therefore, the solution of Eq. (3) gives J_x = a constant, so using Eq. 2, we get J_x = σE_x = I/A (Eq. 5) where σ is the conductivity of the wire, I is the current in the circuit and A the cross-sectional area of the wire. Eq. 5 is the equation of continuity applicable to the steady-state in a simple DC circuit. Electrostatics and circuits belong to one science not two and it is instructive to understand Current, the conduction process and Voltage at the fundamental level as in the following two videos: i. kzbin.info/www/bejne/iHbWiJeabJukrsU and ii. kzbin.info/www/bejne/bnO0fpKurJeFnNE The last frame References in video #1 lists textbook 4 in which a supplementary article “Charge Densities and Continuity and Prop of em signals in wires.pdf” in the pdf files folder in the CD discusses these topics in more detail with several diagrams using a unified approach and includes a description of the application of the general continuity equation in special situations like conductors in isolation and in semiconductors.

[@rohitkankal2131]

Does someone know , from where to refer Poissons equation?

[@An-wd9kk]

Just pointing out. It's delta x not del x. del (.aka nabla) is the gradient.

[@jrsolomon5960]

Tq Sir.

[@alvinaug3844]

at 4:13 first term indicates no of electrons flowing out of box,because when current enters electrons leave.Am I right?

[@mitultyagi3357]

Thank You.

[@ShivamKumar-jp2mj]

Nice explaination but sir if possible please use better microphone thank you

[@mananbahl4842]

THANKS

[@ROHITGUPTA-dd4iz]

Thank you sir

[@sudhanshukumar3342]

sir electromagnetic field theory par v plss videos bnaiye. humble request

[@DeltaSigma16]

Sehr gut

[@brownnyy5]

Why devide the current density by charge q?

[@techgurukula]

if we divide the current density by charge q - we can get number of carriers flowing per unit area per unit time, which I believe is easier to understand and on top of it +ve charge and -ve charge are brought out to see the difference. Hope that helps. Thanks, Techgurukula.

[@mukeshsah2535]

please sir make video for mosfet before end of this month

[@kautukkundan8001]

thanks a lot

[@ezlearnpoint2357]

Which software used in creating this video sir

[@hardikkhandelwal8697]

Sit 3.0r time par jo current density wala ki x par jyada hogi to hi dn/dt badega kaise

[@saurabhpal9505]

Upload some new videos🤗

[@chathrapathinikhilkandagat7728]

why charge of electron is -q ?

[@ashishrawat770]

abe yaar......

[@godsrighteousness5003]

Because he needed to state the charge of the particle he is taking the count of (in this case a negatively charged electron), to satisfy the current density (Jn) parameter. Essentially he is saying negative current density, becuase current density is usually represented as positive he needs to multiply it by -q so now it is the negative current density, or current density of electrons. To further explain; when doing the math he already stated that Jn(x)>Jn( x+Δx), you can see for the continuity equation for electrons that if ∂Jn/∂x (while strictly holding flow is from the left) the current density is increasing across the material span. If the current density is increasing then we know that the electrons are decreasing because electron current density is -∂Jn/∂x, and so Jn(x)>Jn( x+Δx) holds. We achieved this state by substituiting -q. Furthermore we can see for the holes continuity equation that by leaving q as positive we have a negative infront of ∂Jn/∂x, therefore making decreases current across Δx positive which satisfies Jn(x)>Jn( x+Δx) for positive particles. In summary sub in -q for negative particles electrons for increasing electrons & +q for positive particles increasing positive charges. This video from Khan academy explaining diffusion & drift might help you: www.khanacademy.org/science/in-in-class-12th-physics-india/in-in-semiconductors/in-in-the-pn-junction/v/diffusion-drift-barrier-voltage-class-12-india-physics-khan-academy?modal=1

[@mukeshsah2535]

before gate paper

[@SagarArora1100]

Difficult

[@varunchopra3200]

what is wrong with your accent ?

[@sivatejamattaparthi549]

Thanks a lot sir