Excellently explained~ You are helping me in my 2nd year Btech in Electronics! God bless you.
@anshumansingh8513 Жыл бұрын
Hello sir i am in btech ec 2nd year. Help
@thanos21014 жыл бұрын
Thank you so much. Greetings from an electrical engineer from Greece!
@gopikrishnan18275 жыл бұрын
while exploring the web for EDC content I came across this channel on youtube. wow, I have come to the right place for preparing. content and the way you deliver the concepts are really good. especially this lecture the lake analogy was a great one.
@maroon_passport8 жыл бұрын
i never thought it would be this easy!!!! thank you sir, a ton! 😊😍
@USHAKIRAN-yg2bi5 ай бұрын
Excellent video
@md.arafathossain10253 жыл бұрын
Complex explanation from textbook made me think this in a very complex way. I didn't think this could be understood in this easy way. Thank you very much from Bangladesh....
@deepthi42387 жыл бұрын
This is a superb video...understood Continuity equation very welll!!! Thank you so much Sir
@deepvision88773 жыл бұрын
This is a very detailed and most importantly, clear explanation thank you. The only feedback I would give is that you did not fully explain why we consider the current going in and going out as being a separate cause to the generation and recombination rates. In other words, that equation suggests another mechanism for why the current entering the region can be less than the current exiting. I would have thought that the difference in the currents would contain the generation and recombination rates.
@kamraprdp8 жыл бұрын
masterpiece!! I bet no one could explain it better than you. Analogy also given. Thanks :)
@AnilGupta-py6vx5 жыл бұрын
Thanks a lot sir .. Tomorrow is my exam this help me a lot
@ramjeetpatel74145 жыл бұрын
What a concept sir....
@trupti47426 жыл бұрын
Awesome explanation... finally understood the continuity equation Please sir make videos for EMT
@pragatisharma111 Жыл бұрын
Superb explanation!
@subrotodeb56934 жыл бұрын
Thank you..Most of my doubts are clear... Happy Teacher's Day...you people deserves it...for the very suitable analogy provided during the session..
@alfredoespinoza29685 жыл бұрын
Good video, sir. Very well explained. Thanks.
@prateekverma736 жыл бұрын
What a simple n easy to understand. Thk you sir
@429sahilahammadshaik23 жыл бұрын
Simple.... And Excellent explanation
@AbhishekKumarSinhaGo25 жыл бұрын
Very nicely explained and to the point. All 11 mins is worth
@psinha65024 жыл бұрын
Ur explanation is very conceptual unlike others. Keep it up . And also work on perfection
@ehaba64574 жыл бұрын
Great video!! It provides us with simple explanation
@milandeepsinghbhalla33076 жыл бұрын
great u explained it by making it look so easy spatially that LAKE example was awesome.....
@MohitK967 жыл бұрын
best and most easiest explanation ever....
@arpitjoshi87177 жыл бұрын
Gr8 explaination Sir👌
@mohitjain56856 жыл бұрын
Awesome way of explanation
@anujaggarwal71788 жыл бұрын
nice explanation
@arifkulkarni1638 жыл бұрын
Very Nicely Explained... Thank you very much... :)
@ankitjoon73203 жыл бұрын
excellent explanation, even a layman can understand!
@adityasiddheshwar78164 жыл бұрын
Amazing Explanation!
@raghavibhoopathy46517 жыл бұрын
Excellent video. Thanks
@mb083skfaheem9 Жыл бұрын
Thank you sir i dont know what's going on but i can write this easily in exam 🤝💖
@MohdHilal2 жыл бұрын
thank you very much, very well explained
@emadeddin_3 жыл бұрын
Best of Best Dear ♥
@geethanjali18836 жыл бұрын
fantastic expln.. no one can better explain than he did....
@NIDHISINGH-gi7lj5 жыл бұрын
Thanks.. For making the concepts so clear !!
@godsrighteousness50034 жыл бұрын
how old r u? You must be super smart
@nishapawar33683 жыл бұрын
Ur every video I watch satisfies :)
@sagarnain77748 жыл бұрын
best video ever
@nagavarshinimayakkannan8089 жыл бұрын
thanks for providing me such a nice video
@MrSrinivasbandi3 жыл бұрын
Excellent explained
@akashsardar4955 жыл бұрын
Thanks a lot ..sir 😃😃
@shobhitpandey88215 жыл бұрын
anology fadu thi btw
@shilpanair96645 жыл бұрын
thank u soo much for this video
@ansaine3 жыл бұрын
damn nice explanation!
@curiousbud23665 жыл бұрын
Sir haynes Shockley experiment is missing from your lecture series
@TheMyPgk7 жыл бұрын
Perfect...
@shahabuddinshaikh12747 жыл бұрын
thank U Sir.................
@MuhadisaishaqZehra4 жыл бұрын
Thank u
@samikshapandey2955 жыл бұрын
Thnx a lot sir
@navinrs4910 Жыл бұрын
In a reference book The continuity equation of electrons in P type semiconductors is having different sign from yours (Can you say about this ?)
@shubhamnayak93695 жыл бұрын
Kindly reply if anyone gets my question: dn/dt is +ve when g is greater and positive and dJ/dx is positive ..but dJ/dx is J(x+∆x)-J(x) .. so for dJ/dx to be positive J(x+∆x)>J(x) ..but we have seen that J(x+∆x) should be less than J(x) for no. Of electrons inside the box to be positive.... Plz clarify
@navaneeth_anand7 жыл бұрын
Oh thank you so much.
@manichandu24069 жыл бұрын
thanks you very much
@sridharchitta73212 жыл бұрын
The continuity equation for conductors in simple DC circuits is seldom found and derived in textbooks though derivations in case of semiconductors are found in several textbooks. The charge density and current density functions are related by the continuity equation (see Electricity and Magnetism by Edson Ruther Peck, McGraw Hill, 1953) which maybe derived by applying the principle of conservation of charge. Since most textbooks on circuit theory do not discuss this important aspect of the conduction process in the dc steady state in particular, I have discussed this in textbook 4 (see last frame of video 1 to be discussed below). In its most general form the equation of continuity is ∂J_x/∂x + ∂J_y/∂y + ∂J_z/∂z + ∂ρ/∂t = 0. (Eq. 1) as derived from the conservation of electric charge law. The current density J in an isotropic medium is given by the relation J = σE (Eq. 2) where E is the electric field intensity and where σ is the conductivity of the medium. It is also written from Eq. 1 as ∂J_x/∂x + ∂J_y/∂y + ∂J_z/∂z = 0. (Eq. 3) when there is no excess charge in the conductor or that there is no unpaired charge density (lattice ion and conduction electron). In the absence of emf in a region in the circuit (say, away from the source or battery and within a small section of the conductor or a resistor), the total electric field E, may be expressed in terms of a scalar potential function U; E_x = - ∂U/∂x E_y = - ∂U/∂x, and E_z = - ∂U/∂z (Eq. 4) Eqs. (2), (3) and (4) characterize the current flow within a region of a homogeneous, linear, isotropic conductor where there is no emf. If a dc circuit of a battery and a wire is laid in a straight line along the x-axis then evidently, the presence of surface charges will guarantee that the total field E will be a constant E_x along the axis in the region. Therefore, the solution of Eq. (3) gives J_x = a constant, so using Eq. 2, we get J_x = σE_x = I/A (Eq. 5) where σ is the conductivity of the wire, I is the current in the circuit and A the cross-sectional area of the wire. Eq. 5 is the equation of continuity applicable to the steady-state in a simple DC circuit. Electrostatics and circuits belong to one science not two and it is instructive to understand Current, the conduction process and Voltage at the fundamental level as in the following two videos: i. kzbin.info/www/bejne/iHbWiJeabJukrsU and ii. kzbin.info/www/bejne/bnO0fpKurJeFnNE The last frame References in video #1 lists textbook 4 in which a supplementary article “Charge Densities and Continuity and Prop of em signals in wires.pdf” in the pdf files folder in the CD discusses these topics in more detail with several diagrams using a unified approach and includes a description of the application of the general continuity equation in special situations like conductors in isolation and in semiconductors.
@rohitkankal21318 жыл бұрын
Does someone know , from where to refer Poissons equation?
@An-wd9kk6 жыл бұрын
Just pointing out. It's delta x not del x. del (.aka nabla) is the gradient.
@jrsolomon59602 жыл бұрын
Tq Sir.
@alvinaug38446 жыл бұрын
at 4:13 first term indicates no of electrons flowing out of box,because when current enters electrons leave.Am I right?
@mitultyagi33575 жыл бұрын
Thank You.
@ShivamKumar-jp2mj7 жыл бұрын
Nice explaination but sir if possible please use better microphone thank you
@mananbahl48423 жыл бұрын
THANKS
@ROHITGUPTA-dd4iz6 жыл бұрын
Thank you sir
@sudhanshukumar33427 жыл бұрын
sir electromagnetic field theory par v plss videos bnaiye. humble request
@DeltaSigma165 жыл бұрын
Sehr gut
@brownnyy52 жыл бұрын
Why devide the current density by charge q?
@techgurukula2 жыл бұрын
if we divide the current density by charge q - we can get number of carriers flowing per unit area per unit time, which I believe is easier to understand and on top of it +ve charge and -ve charge are brought out to see the difference. Hope that helps. Thanks, Techgurukula.
@mukeshsah25356 жыл бұрын
please sir make video for mosfet before end of this month
@kautukkundan80017 жыл бұрын
thanks a lot
@ezlearnpoint23574 жыл бұрын
Which software used in creating this video sir
@hardikkhandelwal86976 жыл бұрын
Sit 3.0r time par jo current density wala ki x par jyada hogi to hi dn/dt badega kaise
@saurabhpal95054 жыл бұрын
Upload some new videos🤗
@chathrapathinikhilkandagat77287 жыл бұрын
why charge of electron is -q ?
@ashishrawat7707 жыл бұрын
abe yaar......
@godsrighteousness50034 жыл бұрын
Because he needed to state the charge of the particle he is taking the count of (in this case a negatively charged electron), to satisfy the current density (Jn) parameter. Essentially he is saying negative current density, becuase current density is usually represented as positive he needs to multiply it by -q so now it is the negative current density, or current density of electrons. To further explain; when doing the math he already stated that Jn(x)>Jn( x+Δx), you can see for the continuity equation for electrons that if ∂Jn/∂x (while strictly holding flow is from the left) the current density is increasing across the material span. If the current density is increasing then we know that the electrons are decreasing because electron current density is -∂Jn/∂x, and so Jn(x)>Jn( x+Δx) holds. We achieved this state by substituiting -q. Furthermore we can see for the holes continuity equation that by leaving q as positive we have a negative infront of ∂Jn/∂x, therefore making decreases current across Δx positive which satisfies Jn(x)>Jn( x+Δx) for positive particles. In summary sub in -q for negative particles electrons for increasing electrons & +q for positive particles increasing positive charges. This video from Khan academy explaining diffusion & drift might help you: www.khanacademy.org/science/in-in-class-12th-physics-india/in-in-semiconductors/in-in-the-pn-junction/v/diffusion-drift-barrier-voltage-class-12-india-physics-khan-academy?modal=1