Electrons and Holes in Semiconductors

[@SuryaPrakash-ld9cb]

None of my faculty said about how holes are actually represented , created and moved . Great explanation Made my concepts çlear

[@wjjohns04able]

Just wanted to say that your explanations were very clear and understandable. I’m studying for a Ham radio exam and these videos really helped me understand some of the basic electronic stuff that wasn’t covered well in the manual.

[@omer204]

This video answered all of my questions about this case

[@pineapplesharm2903]

Very good explanation. Thank you !

[@davidle896]

It is often said either hole or electron move. but in my view, "hole" movement is just imagination of what really moving around is electron and the hole position is the result of electron moving under electric field. In fact, the hole (or positive charge) is the result of proton of its atom which is fixed to the lattice and so the proton is never really moved around.

[@Mrnoone9115]

Yes in actual hole is a empty place from where electron moved away! ....

[@benezderking]

Very well explained, thank you

[@Amsemsora]

thanks, man

[@ElectronXLab]

You're welcome. It's nice to see that after 6 years, this is still useful to people.

[@DAHBLIFE]

Hey David! One question, Any ideas on how can we determine the minimum energy required for the electrons to get itself out of the covalent bond? Assuming we know the temperature?

[@learnwithfun2287]

Best video 👍

[@peacebewu]

sorry if this is a dumb question, but: if the electron leaves a hole, where does this positive charge come from? From my knowledge, the protons can't leave the nucleus of an atom... Also, what happens to the movement of the electrons when they share valence electrons?

[@ElectronXLab]

peace bewith u - the atom as a whole entity will have one less electron, so the proton/electron ratio is no longer equal which means the atom as a whole will have a positive charge.

[@peacebewu]

Thanks!

[@takisally]

How do you determine the optimal position for N/P doping??

[@user-cq4zk8mw6r]

Hi man.