EMF Equation of Transformer

[@talariupender9772]

Rate of change should be wrt time not wrt frequency. Take X-axis as Time axis not as frequency.

[@HemanthKumar-yk8iy]

Excellent for understanding

[@chanduronny2575]

Good explanation brother Please video create on 4th semester AC1 in diploma subjects and also EED (electrical engineering drawing) For all problems

[@Akhila_._kt]

Sir how will come the values of 1.11

[@nalluriaparna9268]

Thank you sir 🤝

[@ChandanTutorial20]

Welcome 👍

[@najmusshakib6984]

Tnx for easy explained 🥰

[@NS_MOVIES_70]

Good sir

[@ArtiRay123-bv8ly]

Nice ❤

[@kolanji-saravanan2542]

Thank you

[@shashikantyadav3133]

Excellent

[@manoharmansinghbhukya5904]

Super Anna

[@h.mohamedakram9778]

Good

[@Nothing90266]

Great

[@talariupender9772]

The explanation is completely wrong. Avarage rate of change of flux linkage is the ratio of change in value of flux from t1=0 sec to t2=T/4 sec ( as he had taken one-fourth of complete cycle) and now change in value of flux for this time period is ∆m (I'm representing flux symbol with delta), Rate of change of flux linkage= ∆m/(T/4)= 4∆m/T Weber's per sec . Or = 4f∆m Weber's per sec. (Since 1/T=f). In this video he had given units as cycles per sec or volts which is wrong.

[@talariupender9772]

Now according to Faradays laws of Electro Magnetic Induction EMF, e=N d∆/dt e= N 4f∆m volts Average EMF per turn = 4f∆m volts (Since per turn means N=1) RMS value = form factor × Average value E = 1.11 × 4f∆m volts per turn Or E=4.44 f∆m volts per turn Now EMF induced in primary winding of Transformer is E1= emf per turn × no. Of turns in primary winding. E1= 4.44f∆m N1 volts. Similarly E2=4.44f∆m N2 volts.

[@ravikumarachooti2070]

Tq sir l

[@aghashahnawazpathan8435]

Lush