You are just awesome, people like you make youtube a better place
@fuzzyelectrons3 жыл бұрын
Awesome dissection of scattering on transmission lines! At 9:45, there's a small typo in P_{avg}, the magnitude of V0+ should be squared. Thanks for another great lecture!
@empossible15773 жыл бұрын
Thank you! Let me point you to the official course website. I recommend using this as your portal to the course. You can download the latest version of the notes that usually has corrections that are not in the videos. For example, this is a mistake that I previously caught and fixed, but the mistake still exists in the video. I will be teaching this class this fall so I hope to be adding content, visualizations and rerecord all of the lectures. Here is the link: empossible.net/academics/emp3302/
@fuzzyelectrons3 жыл бұрын
@@empossible1577 Thanks! I didn't realise the slides in the video were different from the slides on the course website. :)
@empossible15773 жыл бұрын
@@fuzzyelectrons The goal is for them to match one-to-one, but it does not seem reasonable to record a whole new video to fix a small error. Also, I used to host the courses and videos from my university, but I they kicked me off. Since then, I have been converting over to the EMPossible format.
@fuzzyelectrons3 жыл бұрын
@@empossible1577 I'm sorry to hear the university kicked you off. Anyway, the EMPossible format seems pretty promising!
@empossible15773 жыл бұрын
@@fuzzyelectrons Life gave me lemons so I have been making lemonade and would never go back.
@eie_for_you4 жыл бұрын
This is JUST the stuff I am trying to come up to speed on. I have successfully constructed a band-reject filter using RG58, but trying to apply the same thoughts to creating a band-pass filter ... so far not so successful. WAY wide pass band as compared to my 3 MHz bandwidth of the band-reject filter.
@empossible15774 жыл бұрын
Very good. There might be something in the following lectures that will help you. Thank you!
@sln77364 жыл бұрын
i did not understand how we found the magnitude of V(z)
@empossible15774 жыл бұрын
Are you asking about the derivation around Slide 14 in the video? The trick here is the complex exponential term. Remember that when the argument of exponential is pure imaginary, it is really a just a cosine function that is bound between -1 and 1. These limiting values are used to determine the maximum and minimum values of the |V(z)|. Also not that we are not finding |V(z)|. Instead we are finding the maximum and minimum values of |V(z)|, which is quite different and easier to do.
@sln77364 жыл бұрын
CEM Lectures e^j2bz term confused me
@meghjitmajumder34684 жыл бұрын
@@sln7736 if you do it by you're you'll get to know...