Enantiomers

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[@samuraijosh1595]

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[@dhruv1422]

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[@samantharosen7593]

first time i understood that you can either switch the wedges and dashes OR do mirror image. thank you!!

[@samanthaperry7788]

me too! I was so confused

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[@ابوسجاد-ل8ت]

enantiomers have opposite configurations at all chirality centers, whereas diastereomers have opposite configurations at some (one or more) chirality centers but the same configuration at others.

[@siyanastoyanova1294]

I finally understand enantiomers, thank you very much!!

[@nurulamalinaa7954]

Please do the enantiomers for estradiol 🥺

[@sophieh7278]

How can you distinguish between the 2 isomers 2-amino butane? What makes one + and the other - ? Thank you!!

[@serena_bee]

R configuration is (-) and S configuration is (+).

[@w07106123]

@@serena_bee No that is not correct. RS configurations have nothing to do with + or - molecules. The only way to determine whether the molecule is + or - is to put the molecule sample into a polarimeter to measure which way the plane polarised light rotates. RS configurations is just a way to express what kind of enantiomer you're referring to so that others know what you're talking about without measuring the optical activity of the molecule.

[@w07106123]

I would say there is no easy way to distinguish between enantiomers of 2-amino butane. The only way I could think of is to measure their optical activities in a polarimeter but this only works if you have two separate samples of the enantiomers. It doesn't work if you have a racemic mixture.

[@갱갱항상]

@@w07106123 good work lol

[@BanchiwosenEsatu]

I don't know how to tell. You are the best.

[@philipvaskoudis4867]

hello u are awesome!! I cant understand why we have to reverse the hydrogen which is in the front and change tha configuration..thanks

[@tolulopedurosinmi5630]

You reverse it because you want the CH3 (or whatever is higher than H) on the dashed block to go on the wedge and then you swap the configuration since you're taking H to the back.

[@laurenmcgavin7858]

There are two steps to assigning configurations to stereogenic centres: step 1: assign priority based on the atomic number of the attached atoms (e.g. Bromine is labelled as priority one at 1:30 and hydrogen is priority 4) step 2: orientate the molecule so that the lowest priority atom (usually hydrogen) is at the back, furthest away from the viewer (this position is represented by the dashed bond)

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[@kofi8259]

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[@joshuacrow1457]

Why is the Br on the wedge? Does the wedge always go to the highest priority compound?

[@heavenkleinschmidt6340]

Wedge just means it's facing toward you on the page of the plane. The priority is all about the atomic number or Proton number of thr atom. Br has a higher atomic number than say methyl or hydrogen so it's more of a priority

[@kkrampage]

Well done. Activation Mechanisms of the NMDA Receptor in relation to enantiomers=interesting

[@giladbauman6927]

How do I know if i should use th wedge or lines?

[@supreethakumar5063]

when do we swap the dot with the wedge and vice versa?

[@aDrIaNnAjC]

From what I understand, a compound can only have 1 enantiomer. But, for the last problem with trans-1,2-dibromocyclohexane (pretty sure I butchered the naming), you drew 2. Are they the same?

[@aDrIaNnAjC]

I think I answered my own question. If you rotate one of them, it matches the other. They’re the same, just draw differently. I just need to figure out the wedges and dashes🥴

[@justinwhitening4828]

thank you for your help!

[@saidassubhadarshi5496]

Propan-2-ol does not have a chiral center but in our books it's given that they are enantiomers is it correct??

[@rwayle]

If it doesn’t have a chiral centre it doesn’t have an enantiomer.

[@andrewjustin256]

1:11 Aren't they meso compounds? I don't believe they are enantiomers, because if we assume there is a mirror in front of the compound on the left, it should have a mirrored image, implying the chiral chain that is on the backwards now should be on the front and vise versa, while those who are neither front or back should be the way they are.

[@paysonkeown2960]

These are not meso compounds. The mirror plane identification for meso compounds has to put the plane within the molecule. There are no planes of symmetry in the molecule.

[@arifemreagcan6653]

At 5:56 Why it is not like that: bromine is on the left side of the top of the structure, if it is mirror immage, it should be like I said?

[@strawberryskates]

So in this case, its kind of like imagining that the mirror is in front of the molecule. The Bromine which was on a wedge i.e. in front of the plane would appear to be behind the plane in the mirror. Hence why it is on a dash and is not on the left side of the molecule.

[@adansilva6851]

also because stereoisomers have same connectivity so if the bromine is on the second carbon, then in the other enantiomer it must stay on the second carbon (pretty sure this is correct info)

[@vitushka01]

Thank you! But I don't understand the wedge and dash thing Is there a video on it I could refer to?

[@brianshang1069]

No

[@willman1011]

Wedge = Facing towards you, Dash = Facing into the page. Its a way of showing 3D molecules in 2D space

[@vitushka01]

NotaPro Thank you 😊, I truly appreciate it

[@brianshang1069]

I knew that 2

[@rudyg9548]

Brian Shang shut up Brian

[@mik3isme522]

Im in highschool chem and learning for fun. I love chem.

[@juliaarrigale272]

why when doing an enantiomer of bromine, we don't create a line of symmetry and create a mirror image? we just switch it to a dash?

[@rwayle]

There’s more than one way of drawing enantiomers. You just need to rotate what you’re thinking about in your head.

[@toluladeafolabi8871]

But you all start drawing it straight in Fischer or perspective but how do I convert it from CH3ChBrCH2OH to Fischer or perspective formula something like this

[@user-vy8vm5kj7t]

why did you start swapping the wedge and dashed substituents toward the end of vid? isn't it just mirror image so it still would be on the same side?

[@AleGranda1]

For the last example, wouldn't that enantiomer also be a diastereomer?

[@buffylehman]

at 5:40 why would there only be one enantiomer instead of 4? shouldnt there be RR, RS, SR, and SS enantiomers if the original compound has two chiral centers?

[@manikantan4809]

Yeah he is just teaching the basic level but you're correct

[@rwayle]

You can’t have 4 enantiomers by definition, only ever 1. SS would be the enantiomer of RR, SR would be the enantiomer of RS. One of these pairs may be meso, depends on the compound.

[@manikantan4809]

So a enantiomers is a non superimposable mirror image which has a chiral carbon

[@samarahlynn1857]

do all chirals change in an enantiomer?

[@AkindamayoOlaniran]

Hi OCT..does this mean we can't exchange two line bonds to get an enantiomer? I already did that in my test 😢

[@jamesfk6654]

Thank you!

[@fKI65]

Finally I understood

[@chx99]

Thxxx!! finally understand!! 😭😭😭

[@sapanarai2112]

Thankyou so much sir ❤

[@shawtawt12]

What is the name of the molecule?

[@andreapolovina7271]

I love your videos 💗

[@AnyanwuChimebuka]

Where did we get the rule that if he is in the front we reverse the counting?

[@mudassirbaig21]

Thanks buddy, you made me clear about it 😀 !

[@LoVeMyWiShEs]

how do you know how to draw them when youre given the the formula?

[@LoVeMyWiShEs]

I can draw the other enantiomer given one of them, but how do you know where to put from the formula?

[@manikantan4809]

If R or S configuration is given eith the formula then it's possible to draw their structure If not you cannot 😄 hope I solved

[@MrKhan-cd3ju]

What are ths the two enantinomers of Cocl2 (en) +2

[@CODERBOYVANSH]

Love from india😍

[@anas-xp1vg]

thank you.

[@winproduction7585]

Why we need to reverse when H is in the front?

[@smitham4303]

Love it thanks for the good video mate

[@Yash-ek5gq]

thank you sir!!!!!

[@Mark-c9i]

at 6:30 should we not put cl first then br?

[@emanfouad2760]

I think in 4:17 there is something wrong Compound in right side should be S not R ?!!

[@hrekh]

H is in front plane so we take R instead of S

[@lisieuxmoleda5013]

Thank you!!

[@tirththakkar2459]

Bro is goated

[@atharvpandey3636]

I have seen a first KZbinr whose thumbnail only gives the answer of whole topic "enantiomers" non super imposable mirror image

[@dharamnarayanjangid4651]

Very nice

[@arifemreagcan6653]

Isn't it like CH2CH3 (opposite) H3CH2C at 5:35 ?

[@mariamkh7068]

I'm watching this now and I've got the same question

[@ilickcatnip]

It's the same! The "C" atom from the "CH2" group of the "CH2CH3" isn't chiral. So you rotate it anyway it won't matter at all.

[@DJHx1]

As always thank you so much!!!

[@farhanalam7642]

wtf? why does those the configuration change depending on the how H is facing? im talking about the example at 4:08

[@shinrasenpai33]

As a visual learner, why didn't i take to KZbin videos sooner?!! 😅

[@theshadeofjett]

at 5:45 i get confused now u covert the wedges and dashes but earlier on examples you never why? ITS CONFUSING ME PLEASE HELP

[@katianacavric3889]

I know I am 4 months late but just switching the wedges and dashes on the carbon chains is like what he did in the previous problems but now he is doing it without using a "mirror". I find it helps when I use a 3D model.

[@bigilpandi7722]

I want to know how u made the video

[@kinzashahzadi6989]

Too goood

[@toluladeafolabi8871]

How do you convert it from it's normal structural formula to either Fischer projection or prospective formula. That's where the issue is for me

[@sohiladeraz8050]

Thanks 🥺

[@HawauAjetunmobi]

What is the meaning of the line, line

[@scarlettwang1209]

Thank u

[@georgesellers7064]

I'd give you some homemade dumplings if i could. thank

[@taneesharoychoudhury8216]

Can anyone please clarify whether the Carbon from the methyl group at 03:32 is also a chiral carbon or not. Thanks in advance and great video!!

[@gilbertherrera9478]

It’s not because for a tetrahedral carbon to be a chiral center it has to have 4 different substituents. The carbon in the methyl group is bonded to 3 hydrogen atoms, which are not different, therefore it is not chiral

[@elonmusk1270]

It is not because 3 Hydrogen attached to the same Carbon atom.

[@ተሜው7]

Thankyou

[@SuperioMan3432]

you da GOAT

[@elonmusk1270]

I had one question, how high are the chances that what you taught isn't wrong. Which sources do you refer ?

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U brilliant

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Cool

[@cindygrey8233]

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[@Omar-fw2fs]

at 6:33 wont the chlorine be at the left side instead of the right side and the bromine be at the right side because you are changing the sides.

[@manikantan4809]

Yeah this video had many mistakes

[@rwayle]

Sure if you’re drawing it as if a mirror was there. But then flip that over and you get exactly what he drew. Enantiomers have all stereocentres with the opposite configuration which he drew, so it’s valid.

[@SerenityScribbles261]

i dont know about thus compound....

[@simonmavaga12]

U r good very good i wish I could see u r face

[@marishabelova3706]

Didn’t understand a thing

[@theoneclutchgod2885]

Skill issue

[@amirnabil1980]

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[@saraht1280]

I don't like how he says enantiomer,,,

[@messibruh]

Then skip the video

[@HH-nb4tj]

i don t like how you explain, you miss lots of details ]

[@silviorodriguez8164]

Learn to pronounce enantiomer correctly

[@messibruh]

Ahh trying to prove that you smarter than him by correcting him

[@messibruh]

Many people spell the same