Energy and Power of Continuous Time Signals

[@nikolp7701]

Very clear and helpfull video! Congratulations!!!

[@altuber99_athlete]

Around minute 6:00, if we want to generalize the formula for any signal, not only voltage, then why bother assuming/letting _R_ = 1 Ω? I mean, if we really want a general formula, _R_ in general is not equal to one. When I studied this lecture in my Communications class I had the same question, but I never got it answered. Also, at 7:03, you took the absolute value/modulus in order to always have a positive energy. But that's not necessary, because the signal is already squared, and any square is always positive. In books the absolute value is also used, but it's because we generalize even more the formula to include _complex_ signals (with real and imaginary part.)

[@7949RAJ]

I think R is not a variable so it just scaling your answer, It has no use in calculations maybe that is why we can take R as 1

[@akhils350]

R is just kept as a constant here actually its the power here as considered as propotional to either voltage^2 or current^2 I think so

[@akhils350]

as R here is not dependent on time

[@elshazlio]

Energy E promises to do work W in the future.Good way to put it

[@nickthewinner2194]

its good to have straight A's.

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[@zaydibrahim4532]

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[@SureshKumar-zc7rl]

For Total energy calculations, why we need to take integrations from -infinity to +infinity

[@TheIllarious]

I have exactly the same question. Ok it is not so difficult to do it with Chasles or parity proprieties of integration operation. But I wonder why ?

[@aisucks5615]

Maybe coz it’s continuous signal soo its limit are - to +

[@amareswariammu2850]

please include electromagnetics subject sir

[@foreverythings5712]

I have learned a loot from your lectures jizakallah..........

[@ananddhivare892]

Sir,but in techmax book average power for periodic signal is is different .It is To/2 instead of To

[@vaibhavvalandikar3913]

Anand Dhivare don't use techmax😂

[@kotasriveni7914]

Neso Academy sir 1.how come avg power varies to periodic and non periodic signals but not energy. 2.if the energy for energy is equal to both periodic and non periodic can we get it by integrating between fundamental time period? 3.Another thing why to keep limits u can just put it from -infinite to +infinite directly.

[@drvnlrnr]

What is the point of the absolute value operator in the formula if were already squaring the result? Isn't the result going to be positive either way?

[@manohardahal3514]

What if resistor's value was 200 ohms? Is this formula only for resistor 1 ohm?

[@faisalmushtaq3178]

Please use an example for every concept.

[@karan_singh_]

sir plz include these videos in sub-wise playlist

[@karan_singh_]

Neso Academy thank u

[@watchdognepal]

whats the meaning of taking the integration from -infinity to infinity and what does it mean for -t/2 to t/2 t tends to infinity

[@belwizdadimed3967]

The square is already making real signal positive so the absolute value is taken in case of complex value of the signal.

[@altuber99_athlete]

Exactly. You're correct. I just commented this hehehe.

[@JUNGELMAN2012]

At 3:54. Work = "related to energy" , thus not Work=Energy. Work is the transfered/exchanged amount of Energy. You also confuse Energy vs Power. at 5:38 Average Power calculation becomes Average Energy.

[@ahmedkhaled445]

3:30 Is the work the promise made by energy , sir ?

[@ravishankarmishra2903]

Sir, can you please tell us which book you used for recording these lectures??

[@shaansaharan7294]

Why is the range between -infinity to infinity?

[@chireadaniel817]

All finit signals are stable?

[@dwinovianto1250]

Why did u assume that R=1ohm? at 2:19 thanks at first.

[@Optinix-gz1qg]

Its for simplicity so you can calculate the power of the resistance with p(t) = v^2(t) or i^2(t) because p(t)=v^2(t) / R = i^2(t) x R if R =1 then: p(t)=v^2(t) = i^2(t)

[@ImGabrielRios]

I cannot understand how x(t) can be related with v(t)

[@sdolui009]

why is the integration done between -T/2 to T/2

[@devopswallah]

if u will take integration from -t to t then u have to multiply with 1/2t in place of 1/t . answer will be same

[@ganeshdilli2699]

@@devopswallah why we have to multiply with 1/2t.....

[@lovisharora7604]

@@ganeshdilli2699 total time will be the t-(-t) =2t.

[@-Mohamed_bayan]

because it is derrived from the mean value theorem , the upper limit- the lower limit must be equal the time that you divided

[@tusharkarmakar1678]

Do this lecture series is based on the book signals and systems by anand kumar?

[@varunrawat599]

Na na

[@manavsingh8364]

🔥

[@inwarsnighter]

Can anyone tell me, why let r=1?

[@sohaibrumi4495]

Are these lectures for physics or for computer science? IDK why our teacher is teaching these things in physics of first sem in cs degree ☠️

[@nithyar6696]

Is these enough to clear anna university engineering ece signals and systems pls anyone msg me or otherwise suggest any other cls

[@-RaagaviM]

Same doubt for me too😒