Energy of CT Signals (Solved Problems) | Part 1

[@AJK-a2j00k4]

Bro your hand writing is awesome! Keep it up!

[@WaleedAbdullahkEE]

All the things going gud, but conduct one lecture for Questioning in comment box

[@sushmasush8953]

if my graduation got completed in EEE only becz of neso academy 🖤 ....not even my college after paying lot of fees 😬

[@Ceyhus]

Same here :))

[@unknownm5255]

Sir in second problem We can use time reversal property The graph will be opposite to the first one But in that graph u(t) - infin to 0 is 0 But u are don't consider that one So I confiuse Pls reply my question sir

[@anlgunes783]

u(t) becomes u(-t) so it is reversed too

[@heanstone1327]

Stop saying sir!!!!

[@rationalthinker9612]

I am pretty sure the third case is wrong: There are again 3 cases, a< 0, a>0 and a=0. When a=0 we just have the equation of x(t) = 1 , a horizontal line that stretches in both directions infinitely so obviously E-total is infinity. When a > 0 , we have X3(t) = e^(-at)*u(t) + e^(-at)*u(-t). When a > 0, we have an exponential decreasing function such that when t < 0 it diverges and when t > 0 it converges. So the e^(-at) portion, starting at (0,1) it decreases and converges for t > 0 and for t < 0 it diverges , but when you multiply by u(t), the diverging part ( t < 0) disappears, it is equal to 0 because u(t) is 0 for t

[@mahmoudmohammed8838]

When you take the time reversal you replace each t with -t so it will be e^(+at) u(-t) not as you wrote so it also converges as t goes to minus infinity

[@joeljohnson5576]

sir, am not sure but the value of energy in 2nd qustn should be -1/2a

[@kirubakaran6758]

Substitute -t in place of t and do the integration, you will get +1/2a.

[@Divyanshusrivastava24]

Take lower limit -infinite and upper limit 0 while integration

[@256pawankumarreddy8]

Sir, in second problem because of t

[@heanstone1327]

Stop saying sir!!!

[@pandeyautkarsh7345]

Sir, you haven't taken the case, when t

[@kirubakaran6758]

question 2 is the case where t

[@billy-cg1qq]

The integration of the unit step function from zero to infinity is one!! What?!!

[@meghana3773]

can anyone please explain the case for a

[@rangbahadursingh9126]

Sir you 3rd on question graph plotted is wrong because the value of x(3) will always be equal to 2 at time t=0. So please correct it

[@ajithlol5174]

Second question, there should be u(-t)

[@princekonwar1672]

sir i dont konow whiy after time reversal my energy is coming negative

[@muhammadmalik2801]

Are you keeping the limits from 0 to (-infinty), not that the answer matters to you now xD

[@heanstone1327]

Stop saying sir!!!!

[@AvinyaSolutions]

Sir a small mistake is there in second condition when energy becomes infinite the exponial must be increasing but u take negitive exponitial signal in second case aslo

[@heanstone1327]

Stop saying sir!!!!

[@ammarkhn6920]

@@heanstone1327 Anything wrong with it?

[@marouanebicher5959]

in the third example i think you did make a mistake when you did (x1 + x2 )^2 you will find a different value wich is infinity and i don't know why

[@collegetv7986]

(a+b)^2 = a^2 + b^2 +2ab and 2u(t)*u(-t)=0, therefore it's correct for this eg not sure about others

[@kalyanprusty5966]

I think this is valid for this case only and not valid for generalized cases

[@dineshnalli5755]

Brother expected link of this playlist in description.

[@nesoacademy]

On our website: www.nesoacademy.org/ee/02-signals-and-systems On KZbin: goo.gl/spqKtg

[@iSARTOO2]

For Energy Signal If the amplitude approaches to zero as the time approaches to infinity .

[@sultanshaik6496]

Sir in second and third case ... Why we are considering from -infinty to 0?.... Didn't We have unit step function there which is 0 from minus infinity to 0....!!!!!!! Plz respond sir

[@fincy8309]

khaja pasha the question is time reversal of case 1 so u(t) becomes u(-t) , so the signal exist from -infinity to 0

[@kumargoutam1473]

Sir when we add rest power system video..

[@10kchennal9]

Sir please upload of the rectangular signal of range vaule sir please send to [e-mail]

[@heanstone1327]

Learn English and stop starting sentences with sir. Nobody uses that.

[@rashedalmulla1811]

for the second case, we are taking the integral this time from 0 to negative infinity and my final result is infinity, so how come the second one has an answer same to the first?

[@pranavbhiungade6754]

bhai t ko -t hi replace karna hei

[@saisumanth8064]

in 2nd sum what would be the limits are...............................................

[@prasannmarwadi9483]

Sir when e^-atu(-t) what will be happened in integration

[@heanstone1327]

Stop saying sir!!!!!

[@supriyachavan7989]

give some e.g to solve as point of our exam

[@gnquince]

The signal energy of the continuous-time signal x(t) =[(t-1)u(t -1)]-[(t-2)u(t-2)]-[(t-3)u(t -3)]+[(t-4)u(t-4)] is (A) 11/3 (B) 7/3 (C) 1/3 (D)

[@bharatsahay2264]

1/3

[@SachinSharma-vf5xh]

S.palani??

[@kutadisaisreekar7850]

Sir what is meant by infinite convergence

[@rangbahadursingh9126]

It means that the value of the function tends to zero when time tens to infinite

[@nagendralee5261]

E=0 for 2 problem

[@datteshpradeepnaik1468]

Yes

[@saurabhmaurya7228]

Sir,when we are integrating energy of a signal from -infinity to +infinity time limit, why we are taking time negative?

[@raghunandan2470]

This is because the question is specified so. In the qustion itslef there is a negative sign. This makes the applying limits also negative.