English -Truss Analysis Using Method of Sections

[NOTE: Force HC = -48 kN and is in COMPRESSION]
An video tutorial introducing the method of sections in analyzing a truss along with an example.
#Engineering
#civil_engineering
#structuralengineering
#structural_engineering
#هندسة_مدنية
#تحليل_إنشائي

[@aigoproject]

By spending half an hour here, pausing here and there to soak it in, I finally understand a concept that I have failed to comprehend for the past few months. thank you!

[@baimarrowdeenturay9101]

The tutor has the required patience to pass the message properly. I love this video. God bless you sir.

[@heyitsneel]

This has got to be one of the most clear demonstrations i've ever seen in this subject. Incredible work, thank you very much!

[@sadieadler1072]

sir, if you're reading this, I just want you to know that i am with my utmost gratitude for you have taught me well. Im currently taking 2nd year of civil engineering and was struggling with my topic until ive watched couple of your videos. This really helped me alot and hope this would help others as well. thank you sir

[@CTSCIVIL]

you are very welcome. thank you for stopping by

[@ANYMO5]

One 20 minute video helped me understand Method of Sections better than my 3 hour class. Thank you so much. I wont be failing my final :)

[@CTSCIVIL]

thanks for stopping by and I will see into that Fink truss in the future

[@CTSCIVIL]

You are welcome and thanks for your kind words

[@CTSCIVIL]

Thanks for stopping by :)

[@CTSCIVIL]

you are very welcome and thanks for your kind words

[@mangocakeyumyumyum]

You are so thorough! You've answered all my questions I've had on trusses/ methods by sections, thank you!

[@shaheduzzaman6924]

Just wanna say, you made my day bro.. I felt great for the way you calculated HC :D

[@CTSCIVIL]

shahed uzzaman Good to know that you liked it :)

[@CTSCIVIL]

thanks for stopping by :)

[@andrewepperson269]

Ahhh, because we are only considering external forces. This makes perfect sense. Thank you much.

[@CTSCIVIL]

Thanks for stopping by

[@GerlayKuchiki21]

Thank YOu so much..you'll really help me alot for my exam ..i've understand your explanation more than my teacher..;)

[@CTSCIVIL]

You are welcome. Thanks for your kind words :)

[@maialqattanma]

you're my favorite tutor

[@CTSCIVIL]

Thanks for your kind words

[@aniljkattukaran2415]

it is the most perfect video of method of sections which i was looking for thank you sir

[@sachin_kakade]

i never thought it would be so easy to solve these problems!! your clip was really helpful! thanks a lot sir!! :)

[@CTSCIVIL]

Sachin Kakade Great to know that was useful. Thank you for stopping by

[@CTSCIVIL]

Thanks for watching. Keep on learning though CTSCIVIL

[@asgharasghari4984]

Hi, I just made an account to say many thanks to you.... vary helpful video, greetings from Iran

[@CTSCIVIL]

you are right IF we have a horizontal force acting on the truss. Since we don't, there will be no horizontal reaction AX. Try to do summation of forces in the x direction and see what you get :) Thanks CTS Admin

[@vernonwilliams8644]

Thank you! I was so confused our textbook is errornous and only uses the Moment law, your a life saver!!!

[@961mjazouli1]

AMAZING. NET, SIMPLICITY AND DIRECT FORWARD

[@CTSCIVIL]

Thanks

[@johnnykps318]

Thank you very much. Very clear explanation and easy to understand. Again,Thank you soooo muchhh!!!

[@Falasi21]

Thanks a lot , your explanation is very clear and makes the problems vivid.

[@hiengineer5280]

Expertly done! I wish I watched these videos when I was in school.

[@CTSCIVIL]

Hi Engineer :)

[@actionjessie]

The error he was talking about is that HC is actually in compression not tension fyi, the answer comes out negative 48kN

[@ujjwalsingh3607]

You are right

[@CTSCIVIL]

check the playlist English - Topics in Engineering Statics you should have a video (of two parts) on the method of joints :) thanks for stopping by

[@lllFOT9lll]

wish you were my teacher! 100000 thank you! u saved my year! :)

[@iamwalls]

Awesome video once again, except at the end both values of HC are -48kN, so it would be compression instead of tension.

[@jessalucena3592]

Having an exam tomorrow! :) Thanks for this! :)

[@CTSCIVIL]

The Moment to find BC is taken about Joint ( H ) which makes the rotation clockwise therefore negative. as for the moment to find HG, the rotation is about point ( C ) which makes this rotation counter clockwise, therefore positive. remember, we are rotating about two different points here. although the direction of the forces is the same, tho points we are rotating about are different. Hope that answered your question. CTSCIVIL

[@dinkylicous1234]

thanks soo much.. ill be relying on u for my next 4 years!! haha

[@andreas3861]

:) too late I already trusted you I'm terribly disillusioned.....Great instructional! It was very helpful thankyou

[@CTSCIVIL]

A n d r e a s You are so welcome

[@bashargully2645]

For the last part, an easier method is to find the angle of the triangle which is tan^-1(4/5) = 38.7 degrees, then go sum of Fx=0 , and solve for HC by using it's X component of cos(38.7) .. you're equation will be../ sum of fx = -75 + 112.5 + cos(38.7)xHC = 0 , and when you solve for HC, you get -48kN, which is 48kN in compression

[@aizen09]

Thank you so much, this video was very helpful. You should really have more views you explain in a manner that is very easy to understand. Assalamuakum and hope to see some more videos later.

[@CTSCIVIL]

good to know that. any ideas for future videos?

[@faeriiXD]

Thank you! u teach a lot better than my prof, thanks for clearing things up for me! :D

[@sopheakseng7485]

Thank you so much, now I understand about it because of your explain is very well.

[@CTSCIVIL]

you are welcome

[@rdm2478]

Great Explanation! Thank you soooo much! I will be going to your other videos to freshen my statics up!

[@CTSCIVIL]

Thank you for your kind words John.

[@armaanmcleod2098]

Thankyou for this video man!!! :) So many questions have been answered and I found this video exceptionally helpful. Thankyou very much :)

[@CTSCIVIL]

Armaan McLeod You are so welcome

[@nasratullahamarkhail3217]

Wow!!!! Gr8 video and very easily understood...thanks a lot....

[@CTSCIVIL]

Nasratullah Amarkhail you are welcome

[@user-qr9df1uf8e]

thank you so much, this has made it super easy to understand .. الله يوفقك ويسعدك :")

[@CTSCIVIL]

+The Daisy Thank you جزاك الله خير

[@CTSCIVIL]

It is good t know that helped. thanks for stopping by

[@jagdishchandermoudgil324]

nicely explained and very helpful for students and teachers.

[@CTSCIVIL]

jagdish moudgil great to know that

[@mayvin10]

great video, and very clear audio... nice explanation as well.. i love to see a fink truss example

[@theofficialnba3882]

You are awesome!! Thank you for this explanation. Very much appreciated

[@CTSCIVIL]

you are so welcome

[@CTSCIVIL]

Good to know that thanks for stopping by

[@CTSCIVIL]

Since there are no horizontal forces acting on the truss, the pin connection at A will not provide any reaction in the horizontal direction try to solve the equation "Sigma Fx =0" and let me know Thanks for a nice question :)

[@CTSCIVIL]

to be honest, I never thought of it this way. I think if I do it the way you are suggesting, I am feeling that I am switching my assumption somewhere in the solution. I always assume positive moment counterclockwise and tension as positive as well. do it the way you proposed but for some reason I am feeling that clockwise and tension go together and clockwise and compression go together. sorry for not having a clear answer for now. i need to give it some more thoughts I guess.

[@CTSCIVIL]

Isaac All I need from you to tell me that you nailed that test and we will call it even

[@MuyiFun]

Good job, I admire your approach.

[@dvdcar90]

Hi, for member HC shouldn't HC= -48kN (Compression). Thanks for uploading this video.

[@debasishmajhi687]

Tx for the video sir n u r talking in Russian accent that I really liked

[@CTSCIVIL]

Wa Alikom Alsalam Thank you for the kind words. It is not about the number of views, it is about the number of people who get it, understand it, and implement it. CTSCIVIL

[@bienramos7587]

Very very clear explanation..

[@CTSCIVIL]

good to know thanks for stopping by

[@CTSCIVIL]

I always have problems with people claiming that they are they best or among the best. Teaching is a skill that can be developed. Do not claim to be the best. Let your student decide. Do your part of crossing the idea to others and be thankful if 1 out of 10 people appreciates it. CTSCIVIL

[@FarahmohammadFarah_mohammad7]

Ppeeerfeect *_____* ma Shaa'a Allah Thaaank Yoooou 😄😄😄 👍🏻

[@CTSCIVIL]

+Farạh Mohammad You are so welcome جزاك الله خير

[@Alan-kn4lo]

Very good explanation. Thanks for the video :)

[@paglinawanferlyn4752]

your video is very helpful. nice and clear explanation. thanks:)

[@civilengineeringworld9285]

This video is very helpful for truss

[@CTSCIVIL]

did you assume the positive as tension and the negative as compression along with a counterclockwise moment as positive? if you did, you should not have a different answer as mine.

[@DistinCtiveMoody]

Very very very obvious tutorial .. thank u very much

[@CTSCIVIL]

Thanks for your kind words

[@lumos2maxima]

thanks a lot, very helpful! got my exam in 2 hours hahaha

[@ninchaturtles]

At 5:42 you mention the reaction forces Ay and Ey. Since A is held by a pin, would there be a reaction force in the x direction, Ax? Thank you, great video.

[@MrSilentUser]

Very informative. I'd like to clarify why Ay=Ey=60Kn. Why 30Kn is not part of the equation? Please Explain it more. Thank you very much. :)

[@muhammadismail4708]

bravo, it's very understandable and easier way, thanks

[@CTSCIVIL]

You are so welcome

[@sitges39]

Very good explanation, thank you!

[@ayachitaha8177]

For calculating HC we can use (sin/cos) of the angle after we calculate it by (tang) witch equal to 4/5

[@CTSCIVIL]

yes you can. But the question is, how many numbers after the decimal place will you use? it is always nice to use ALL of them right? However, that is impossible. That is why I use the triangular ratios

[@omaromar-ci6bd]

Salam please other topics if possible could be done in English cos I really understand how you explain very well. Thank you

[@CTSCIVIL]

Nice of you saying that stop by more often :) CTSCIVIL

[@CTSCIVIL]

you are so welcome

[@4775josh]

Awesome video. Which program did you use for the presentation?

[@CTSCIVIL]

Powerpoint and Camtasia Studio

[@tjsh11]

very good at explaining, appreciate the help

[@CTSCIVIL]

tjsh11 thank you for stopping by

[@MohannadGoesRawr]

very well and thoroughly explained

[@jimmerich123]

Thank you! Got perfect on my exam!

[@CTSCIVIL]

Congrats :) So happy for you

[@mohammedalwarfy8031]

You are the best...thank you very much

[@CTSCIVIL]

Thanks for your kind words CTSCIVIL

[@CTSCIVIL]

wishing you the best regards CTSCIVIL Admin

[@marwatalal1450]

thank you so much . best video ever!!

[@CTSCIVIL]

you are so welcome

[@jahbobby3642]

you the real mvp bro

[@ibnzadan]

many thanks < i hope the best life for you

[@janmelfredviray5192]

THANKS BOSS....I AM REFRESH BEFORE I AM CONFUSE HOW TO INVESTIGATE THE TRUSSES IF THE MEMBERS IS COMPRESSION OR TENSION....

[@rahimaharoon1320]

You were amazing literally!!

[@CTSCIVIL]

Thanks :)

[@i6tir]

Excellent video. Thank you so much!

[@CTSCIVIL]

you are so welcome

[@CTSCIVIL]

YOU ARE RIGHT Thank you for pointing that out. I should have been more careful about that. I made a correction in the video CTSCIVIL

[@zprogress4004]

very detailed, well explained, so helpful, thanks!

[@CTSCIVIL]

+z progress You are so welcome

[@CTSCIVIL]

you are very welcome

[@robertwhite2628]

Brilliant job! Thank you!

[@CTSCIVIL]

Robert White Thanks for your kind words

[@firasfreja4560]

masshallaa.. the best

[@theslowsoundtracker]

This is Awesome!

[@nizwan9885]

Amazing explanation. thanks sir

[@Pyccan]

Really good video! i get HC to be in compression though. What am I doing wrong? 4HC/sqrt(41) = -30 so HC = (-30*sqrt(41))/4 = -48

[@DouglasDestro]

I loved this video! Thank you!

[@CTSCIVIL]

You are always welcome keep it up

[@rapiditythurlow5736]

Got a quick question though, couldn't we use the equations for equilibrium in x then equilibrium in y to solve for the unknowns in the truss? this is the first time i saw moments being taken more than once, and is the reason being that you would like to not worry about those annoying reaction forces at the joint?