Epsilon-Delta Proof (Quadratic)

[@justinetheewordgiver1197]

My first time to appreciate someone on KZbin

[@PrimeNewtons]

Thanks

[@isabellacrow8369]

This is it. Two hours of working on the same delta-epsilon problem, and this is the video that made it click for me. Thank you.

[@VasilEPetkov]

My professor prooved the same thing to us. He skiped all the (un)necessary comments what's coming from where so I was so lost looking back at my notes. Your videos are for sure saving me :D

[@tomtomspa]

The explanation is all wrong.

[@CANALIMG]

Sir, could you recommend a better video? ​@@tomtomspa

[@estangiertmichperipher62]

@@tomtomspait’s not

[@piousmazonde5979]

Mathematics becomes easier for me because of how you explained it in such simple ways....Thank you very much

[@yohannesyebabe7923]

It was wrongly explained!

[@tomtomspa]

@@yohannesyebabe7923 I cannot believe how someone so poorly knowledgeable on limits get to wrongly explain them on yb

[@mrhunterai...331]

You're really making our life much simpler and thanks a lot. You simplified the proofs very well.

[@itsmemario1298]

9:18 I did the same expression and the meme appeared! Truly magnificient! YOU GOT ME! LOVE FROM INDIA

[@EyosiasMulugeta-i7f]

You are One of the Great Teachers i have ever seen Thank a lot!!!!

[@emmanuelnhunde]

I actually appreciate you for the good work ,,,God bless you

[@jeromevatrinet3432]

Each video I saw about the limit using Epsilon-Delta concepts is a delight. Your explanations are clear and your proof is perfect !

[@MathTutor1]

First I need to tell you that you have great videos with excellent explanations. These definitely make math learning interesting, enjoyable and easy to understand. The point of this comment is to let you know about a very important notation matter. When we right limit at the beginning without a parenthesis, the limit only belongs to the first term. So, the correct way to write it is to use a parenthesis around all three terms as lim{ x → 1} (x²+5x+6) = 12. Keep doing what you are doing. Thank you.

[@tomtomspa]

Unfortunately that's the least serious error of the video.

[@hriday8690]

This is the best I have ever heard this concept explained. I was struggling with understanding how the proof worked for the past 2 days, and I finally understand now. Thank you!

[@abnertv22]

SO AM I FROM University of Namibia 👌👌👌👌👌👌

[@kamrulhassan7157]

A very very brilliant lecture from a genius . Thank you sir for your contribution.

[@AdrianYung-oo6qf]

I love the way you are so enthusiastic about teaching!! thank you so much for the video :)

[@solha5751]

Bro you are amazing , i mean you have the talent to be a teacher bc you try to understand the students❤❤

[@PrimeNewtons]

Thank you

[@frinky21]

I spent an hour working on one of these proofs and this video was the one that showed me how to replace the factored part (|x + 6|). Thank you so much

[@lusianelundu2702]

Your handwriting is dope sir and I love the way you have explained.

[@PrimeNewtons]

Thank you!

[@mohammedaminelm7836]

You are the best math teacher that exists!

[@anvarkhaydarov1236]

Thank you so much for the explanation. Watched bunch of other videos and yours was the simplest to understand

[@NourAfifi-g7d]

I didnt understand anything before watching this video. but you made it way easier to understand. thank you brother

[@TinotendaMuchenge]

Plus the way u smile doing some cracks, while solving, its just fantastic, u wont be left with any qsn

[@jhonnatanmontano2921]

OMG !! You are an amazing teacher. Thank you so much 🙏 I’ve been trying to understand this for a lot and is the first time I feel like I get it.

[@TheMariusMan]

Hey, first of all, i really like your videos. You are doing a great job! I am a fan of generalizing the epsilon-delta-criterium and give a specific formula for delta. What I found out was that, if you choose for a general x_0 (which is in this case 1 of course) the formula delta (epsilon) = - abs(x_o) - 5/2 + sqrt( epsilon + (abs(x_0) + 5/2)^2), you get a guaranteed delta for any epsilon > 0 that you choose. Thank you for your great videos again. They are very inspiring!

[@TinotendaMuchenge]

Wooow Man u the best, i actually had a crisis in understanding this, but i just grasped it easily, The best of the Bestest

[@znhait]

best video on the subject so far.

[@NeuCoupAlloi]

You my friend are an excellent tutor. Great job on Precise Definition of a Limit !!! Keep up the good work....sorry... Great Work.

[@SenzeniNxasane]

thank you very much i was really confused on this delta and epsilon proofs you just made my day,thank you sir

[@Mahmoud-p8r]

Even i can miss up a class,, its okay with this handful of skills, i really appreciate you.

[@mkmathstutorials6645]

Like how you explain it my brother.much appreciated.

[@henryfayol6667]

You are good lecturer may the Lord Jesus bless you in all your endeavors 🙏

[@samaunislam7071]

It's Amazing. I watched many videos but after watching this video I understood the math well.

[@arbenkellici3808]

You are really doing an excellent explanation and thus make our life easier in understanding maths even though it is not my proffesion. Awesome! Thank you!

[@piousmazonde5979]

You are a Geneous sir...Excellent in making mathematics simple ..very good in explaining

[@PrimeNewtons]

I want to be a genius. It's just hard 😪 🤣

[@LEBOHANGSEBATA-o4k]

Your enthusiam for maths makes me like it

[@yohannesyebabe7923]

The proof has fundamental error! The correct proof is as follows Let f(x)=x^2+5x+6 We want to show lim x->1 {(f(x))}=12 For all e>0 whenever |f(x)-12|

[@Kittu-uc1yd]

Thanks a lot buddy! ✌🏻💚 This comment deserves a lot more likes.

[@brendawilliams8062]

Why would you need this type of math

[@yohannesyebabe7923]

@@brendawilliams8062 It is the rigorous mathematical analysis called the epsolon delta techniques.

[@brendawilliams8062]

@@yohannesyebabe7923 thx. , but what can you do with it

[@yohannesyebabe7923]

@@brendawilliams8062 To prove mathematical theorem.

[@EbenezerMandala]

Your videos are better enough. Thank a lot sir

[@easylearing87]

Bro keep uploading...Love from Bangladesh 🇧🇩

[@MhamusTyfore]

you are a genius ,thanks for your support

[@trendsacrossafrica]

I understood this today 😢 You are a great teacher 👏

[@NickStark-t6m]

Damn , that's some quality teaching .

[@jhadhiraj147]

You are amazing bro! You teach math as if math is your friend and you are introducing me to him 🤣

[@aliana6039]

A big thank you! I love how you teach, makes me enjoy more solving hahaha.

[@ayalktube5991]

your videos are very interesting keep going on !

[@mikeynavarro3195]

By far best explained thankyou

[@PrimeNewtons]

Glad it helped

[@levailiona3399]

THANK YOU SO SO SO MUCH YOU HELP ME A LOT A REALLY LOVE YOUR EXPLANATION

[@josephmartos]

J has to pass my Calculus I course knowing that i will fail in every question of this type. Great explanation!!! Thank you

[@bouchtaessah1230]

شكرأ جزيلا لك ايها المعلم الرائع .لك مني كل الشكر والتقدير والاحترام. ❤

[@leratomoetinyane]

I finally understand this brother thanks a lot

[@tawandadhlakama3187]

You're so talented

[@epsilonxyzt]

Never Stop Teaching!

[@punditgi]

He does it again! Bam! QED! 😃

[@nuesita]

dude you're a genius! :) tysmmm

[@curious_cat505]

God bless your soul. Thank you

[@PrimeNewtons]

Amen

[@Abhishek-ti5er]

Very helpful master ❤❤❤ from India.

[@AdongaThomas]

I like his content for sure

[@alpmuslu3954]

Can someone please explain when 9:04 he writes x+6 as 8 in the inequality. Because he showed that x+6 is less than 8, but when he inserts 8 in the epsilon inequality, he technically increased the left hand side of the inequality without increasing the right hand side (epsilon). Which makes me a little suspect on whether the inequality will hold true. I am no professor and I respect everything he does, but I get delta=epsilon/6. Please feel free to enlighten me. Cheers from Denmark

[@Udics]

Bravissimo. Con te e con Robert Ghrist la matematica è un incanto. Grazie 😊😊

[@priyom_05]

Thank you very much sir ❤ From india 🇮🇳

[@fikaduwalie6066]

really exciting

[@cristopherurrutia8591]

Thanks man, I finally got it

[@PrimeNewtons]

Glad it helped

[@josephpagapong2498]

thank you so much sir, it really helps me a lot. And now, maybe I can answer our exam tomorrow hhahhaha

[@PrimeNewtons]

Good luck

[@hqs9585]

Great video! Thanks. It would be nice to add some graphics to bring this concept to clarity.

[@meromoz]

holy shit you saved my life here

[@zeusui4934]

Thank you so much for the very clarification🎉❤

[@dilshanwijemanna4898]

wow superb sir ❤

[@krishnashroff657]

Best love from India❤

[@rk-ds4vl]

Very good sir love from antartica

[@KHAYMYA]

AWESOME SIR YOU ARE JUST A GREAT MAN THNX A LOT SIR

[@mrsimphiwebazzano877]

Can you please try this problem Use Epsolon delta Def to show that Lim x-->-1.(2x+3)/(x+2)=1

[@Andalfulfulde]

Respect from Cameroon +237, 3:19 🎉🎉🎉

[@arkoghosh6218]

Hello Sir, there is a mistake in this proof. You cannot replace |x+6| with 8 and be sure that 8|x-1|< E. We can take 6 instead of 8 but in that case in the last step you wont be able to replace |x+6| with 6, hence we get stuck. Could you please check for this.

[@okohsamuel314]

That's exactly what I also figured out...👍

[@m.lkadri6070]

We may take delta=min{1, epsilon/8}

[@nebaofficial3343]

Ohh you are so so good❤

[@trhasamare8865]

wow u r great man

[@hoomaankianooshh]

I didn't get why did you replace the x+6 with 8 and not 7 or 6 or 6.5 where did the 8 come from

[@mathiscool2310]

this is the serious issue what am i going to tell you.... if 6 < x+6 < 8 and at the same time |x+6|.|x-1| 6 and now replace x+6 with 6 then it will be not contradict because the product of |x+6|.|x-1|

[@mathiscool2310]

i dont know you are looking for this or not..... i hv figured out the mistake.. you should not start with lx^2 +5x-6l

[@digbycrankshaft7572]

Yes you are right. I spotted that straight away.

[@ayotundeajamu2720]

When you want to show that the left hand side is less than the right hand side, you should always increase the left hand side. So 8 and not 6 was the correct choice.

[@Tee0313]

Truly amazing

[@Arkapravo]

Love that t-shirt!

[@tahreemrana1125]

So helpful sir amazing ❤

[@randomYTwatcher]

but you can't do the step at 13:20, bc you assume that delta is less than one which inplies epsilon less than 8, which doesn't therefore show FOR ALL epsilon bigger than 0.

[@nigarabdullayeva7902]

why x-6 cannot be replaced with 7? it is smaller than 8 how we replaced that?

[@yuxinhe5987]

Man u save my life

[@سلمانيوسف-ر5خ]

what a nice video to watch

[@bhagirathikashyap6021]

Nice explanation

[@b3ztc1ipz]

holy crap u saved me brotha

[@WritersDigest-b8f]

8:58 We substituted 8 because we |x-1

[@jihansarhan9392]

That is easy and clear , do you do one to one tour ?

[@PrimeNewtons]

Yes. Please send me an email

[@masoudhabibi700]

Thanks for video.... epsilon and delta greater than zero is true

[@ramyramy9620]

Thanks so much 🙏

[@FenetAbilu]

It is good. I am lucky if you add another example.

[@ElishaSotuminu]

well taught sir

[@niharikarajanala9454]

Why do we replace x+6 with 8? How does it still hold the inequality I x+6I I x-1I < ε?

[@adityabhagoria1374]

If not possible thank for your videos

[@Forcus-zs3tu]

Thank you so much sir

[@propoop6991]

8:40 no i dont get that. Why does that work? Why does replacing |x+6| by 8 as a result of that inequality work?

[@PrimeNewtons]

It doesn't have to be 8. You could use another constant. Just keep track.

[@propoop6991]

@@PrimeNewtons I get that part. I'm just wondering how replacing it by 8 keeps the inequality the same!

[@propoop6991]

nvm im so stupid. If ab

[@Labrador.007]

Yes

[@PrimeNewtons]

Correct!

[@CatherineYang-hy4ti]

Thanks help me a lot

[@OpPhilo03]

Love❤ from India

[@digbycrankshaft7572]

Because lx+6l

[@yohannesyebabe7923]

He should replaced by 6. and He should choose delta a min {1, e/6}

[@20tejas]

in the second part can we not substitute delta = epsilon/8 into |(x-1)|< delta for the proof to be satisfied.

[@PrimeNewtons]

It depends on what your teacher wants. Some just want you to show there is a delta. But some want you to show that that value you found truly works. So ask the professor what they want.

[@20tejas]

@@PrimeNewtons thanks professor.

[@Unknown-b7x]

Do we need to delta=min(1,epsilon/8).Because we do not know what the epsilon is.Maybe 1 is less than the epsilon?

[@PrimeNewtons]

Yes

[@Tee0313]

Love the 2+2=4 shirt

[@JoyceNalonja]

What if I have the same equation and the denominator is same to one of the denominator