Equations of Motion | Motion | NCERT In-text Questions | Class 9 | PHYSICS | SHIKHAR 2024

[@prajnyaparamitamallick2137]

Thank you sir for the session😊 Home work question- 1 Through 2euation of motion distance will be =s=0+1/2 x 4 x 100 =200m Hw question-2 Through 3 equation of motion =2 x 10 x 20 =v*2 - 0 *2 =v*2=400 =v=20m/s (b) Hw question -3 Through 1 equation of motion =t=0-5/-10=0.5sec Through 2 equation of motion =s=2.5+1/2 x -10 x 0.25 =s=1.25m Hence, time taken =0.5sec and distance travelled =1.25m

[@T_GungunTagore]

Homework Answers :- 1) velocity of the car will be zero , acceleration=4m/s² and time taken is 10sec By using second equation (s)=0+1/2×4×(10)²= 400/2 =200 Hence , the distance covered by the racing car after 10s from start is 200m. 2)1) by using v² = u²+2as Final velocity of the ball just before it strikes the ground will be (v)=20ms-¹ (Option B) 3) velocity is zero and acceleration =10ms-² in the opposite direction of the stone = -10ms-² By third equation (s) =(0² - 5²)/2(10) = Distance (s)= 1.25 m Time = by using v= u +at ( 0=5 -10×t ), t=0.5s Hence ,stone reaches a maximum height of 1.25m in a timeframe of 0.5seconds

[@astha--]

Nice explanation sir😃 you made our concepts clear:) 🔴 Homework- 1) question:- 55:00 Answer- the car will cover 200m after 10 seconds (by 2nd eq.) 2) question:- 55:03 Answer- (b)20m/s (by 3rd eq.) 3) question:-55:16 Answer- (a) the height attained by the stone is 1.25 metre (b) stone will take 0.5 s or 1/2 s to reach there

[@delhiaryan]

Same answer

[@subhashridash9018]

No words for this amazing session. ☺ Thanks a lot sir.😇 📖HW: 1) a= 4m/s², t= 10s, u= 0m/s, s=? Using 2nd equation of motion 🚌 s= ut+ 1/2at² =>s= 0+ 1/2*4*10*10 s=200m 2) s=h=20m, u=0, a=g=10m/s², v=? Using 3rd equation of motion v²=u²+2as =>v= √(0+2*10*20) v=20m/s 3) u= 0m/s, a= 10m/s², v=5m/s, s=?, t=? Using 3rd equation of motion for s v²=u²+2as =>s= (5*5)/(2*10) s= 1.25m Using 1st equation of motion for t t= (v-u)/a =>(5-0)/10 t= 0.5s

[@sitaram2035]

Good explain

[@rajeshwarimalusare3511]

Thank You Sir ... For this amazing session.. Homework.. 1. The car will cover 200 m after 10 sec. 2. 20m/s 3.A. the height attended by stone is 1.25 m B.The stone will take 0.5 s. To reach there .. 😊😊

[@T_GungunTagore]

Thanks a lot for this session 😃😃

[@hydrochloric_x_acid0072]

Yes really❤

[@jhimun09]

Ah! I was waiting for this.. loved the session ❤

[@BeatLearning726]

Thank you sir for this wonderful session... I have a doubt in here.... 23:40... You said m/s multiplied by sec = displacement.... But it should be acceleration....m/s²

[@verostudies9171]

nono m/s multiplied by 1/s is acceleration, but m/s x s/1 is displacement as second at the bottom and at the top cancel out..

[@Saloni-qm2jh]

Sir🔴doubt🔴 - is non -uniform motion is acceleration .if yes why and if no why?

[@Namann_03]

Hey sir it was an amazing session with you. Just loved the session but I was having some doubts they are:- 1. Under what condition, the average speed is equal to the magnitude of the average velocity. Justify this. 2.Can a body have constant speed and still can be accelerated? Explain through an example.

[@astha--]

🔴Doubt🔴- we have to assume (upward and downward) both acceleration during free fall as negative or only one?? If one then which?🤔🤔

[@sitaram2035]

Straight

[@greeshma_priya]

Question = A boy leaves his house at 9.30 a.m. for his school. The school is 2 km away and classes start at 10.00 a.m. If he walks at a speed of 3 km/h for the first kilometer, at what speed should he walk the second kilometer to reach just in time?

[@Avni-447]

Loved the session!❤❤❤But I have a doubt sir. When the SI unit of acceleration is m/s^-2 then why do we write it as m/s^2 when solving questions? Homework Question Answers: (1) The racing car will cover 200m after 10s from start (2) The final velocity would be 20m/s (3) The height attained would be 1.25m and time taken to reach there will be 0.5s

[@krishnapsnair5575]

@Avni-447 the SI unit od acceleration is m/s^2, i guess the - in that was something else

[@Avni-447]

@@krishnapsnair5575 alrr thank you!

[@tanush5885]

Q5 the max height is 1.25m we can calculate it by 3rd equation of motion,the time taken is 0.5 we can calculate it by 1st equation of motion Q4 The distance travelled by the car is 200m we can calculate it by 2nd equation of motion. Mcq:20m/s we can calculate it by 3rd equation of motion.

[@shruthir8203]

Why do we take point A not from origin but after few intervals in y-axis?

[@smartygamerz_5455]

38:8 sir isme m/s ka square nahi hoga kya ?

[@pradeepkushwah5073]

Thanks a million Sir😃 My all doubts are become crystal clear✨✨

[@yugkumarsethy7198]

Sir please tell easy tricks for derived equation of motion from graph

[@narmadasamal3183]

sir is it compulsory to convert the final answer to standard unit

[@MonikaKaushik-nn3rs]

Thankyou so much sirrr

[@tanush5885]

Doubt sir what is speed acquired?

[@shreewaligupta6490]

Tanush Speed acquired meaning is the speed covered in the given time with a certain acceleration

[@shilpaks6509]

I have a doubt

[@abelmundakakulath9555]

the fact that saurav sirs name was not there in any of the comments in the beginning of the vedio

[@AmishaVerma-mh2kq]

Sir what is difference between acceleration and velocity 🙏🙏

[@JoannaDsouza-h2p]

Acceleration (a) defined as rate of change of velocity (b) equation: a= initial velocity- final velocity ÷ time (c) SI unit = m/s²

[@JoannaDsouza-h2p]

Velocity (a) defined as distance by time taken with direction (b) equation : v= distance by time (c) SI unit : m/s

[@gloryr2622]

What is parameter

[@Muslim__960]

Sir g please start class 11

[@sitaram2035]

Constant

[@aiubahmed4113]

Indian toppers attendance here

[@stationary2255]

Present

[@srimeeraenterprises1934]

Present

[@veenaveena5293]

Present

[@shilpaks6509]

can you help mee😢

[@mrkv-6792]

present

[@saketmodi4427]

620 m/s hoga

[@sundarisandhya9533]

Ok

[@sundarisandhya9533]

S how can you explain again

[@sundarisandhya9533]

B

[@sitaram2035]

V-u/t

[@sundarisandhya9533]

A

[@shilpaks6509]

hi

[@sayyadamaan1026]

Parameters😮😢

[@Chiteshsai7.]

hi