Equivalent Weight [TRUE.school - 02.05 ]

Equivalent weight is weight of 1 equivalent of any substance.
It is equal to molar mass divided by N factor.
Normality denotes the number of equivalent of a solute in 1 lt of solution. It is n factor times molarity.
No. of equivalent in a V volume of N normality solution is VxN

[@ganiganesh820]

Very very good and clear definition

[@farhadforoutan1784]

your video is the only video that could explain this concept.

[@TutunChanda]

Great video.. my concepts got more clear

[@abhinabasaikia6377]

mojhaa

[@abhaadhikari809]

It really helped thanks!

[@minimidder2025]

Best video!!! 😍

[@estherchua5428]

Hi! I have a question that I hope you can help me with: At 2:53 you mentioned that if Ca is 18g while O is 8g (correct me if I'm wrong, these 2 weights refer to their individual equivalent weights?), then Ca will be a limited agent. However, I can't see how 1 eq of Ca will ever have 18g. I hope you can explain this concept to me. Thank you!

[@mahadevidevaraj428]

Thank you I understood

[@khushiagrawal5696]

In which video does he discuss about equivalents and substances reacting in equal equivalents?

[@doctorfarrukhiqbal]

awsum yar....

[@shagunchoudhery8407]

But I didn't understand n factor h kya????

[@diwakargairola3206]

The volume occupied by 1 gram equivalent of oxygen at ntp is

[@sssniperwolf6632]

✋✋

[@yukeshthapa7663]

How to find n factor Please tell me?

[@saifnaqvi8732]

the valency of an atom

[@bhartipanjalwar8846]

i want of o2

[@kumarkumar7734]

How to find n-factor sir

[@anjaliarya5326]

kzbin.info/www/bejne/o5ekiYmilpygqc0

[@abhinabasaikia6377]

mojhaa

[@diwakargairola3206]

The volume occupied by 1 gram equivalent of oxygen at ntp is

[@fadilasaeed3343]

Diwakar Gairola 22.4dm^3