Establishing the Derivatives of sin x, cos x & tan x

  Рет қаралды 56,052

Eddie Woo

Eddie Woo

Күн бұрын

Пікірлер: 31
@ksrajavel
@ksrajavel 4 жыл бұрын
One of the best math instructions in my entire life. Thank you Mr. Eddie Woo
@alephnull7410
@alephnull7410 5 жыл бұрын
This is how these trig functions should be introduced.
@adiknoxrider1
@adiknoxrider1 7 жыл бұрын
Love your enthusiasm!
@sumithadavid5841
@sumithadavid5841 11 ай бұрын
He’s an underrated teacher and this channel too The quality of video can be improved by jus placing the can bit more closer to board…
@PoliticalEinstein
@PoliticalEinstein Жыл бұрын
Superb explanation ۔ This is what I was looking for
@mkmathstutorials6645
@mkmathstutorials6645 10 ай бұрын
Hey edd...I appreciate your videos man. .thanks
@zachhong554
@zachhong554 4 жыл бұрын
thank you eddie you are a life saver
@ramsesvasquez2131
@ramsesvasquez2131 2 жыл бұрын
I was wondering what the second derivative means about the first derivative....in physics that 's the "impulse". But I had trouble remembering if the point of intersection with the function had any relationship...(the graphs intersections_) .I think if I remember right, that there is none. I used to get this stuff down pat. I still do but it was extremely easy with Mr Woo's help! What a joy Eddie Woo is in the classes he put in his channel.
@carultch
@carultch 2 жыл бұрын
When the first derivative is near zero, the second derivative approximately indicates the curvature of the function. When the first derivative is much larger, a greater slope is gives the second derivative a harder job to do, to make the function curve. For instance, a parabola has a uniform second derivative, but it doesn't have uniform curvature, otherwise it would look like a circle. Locally near the vertex, it approximately looks like a circle, and this is the point where its curvature is maximum. Curvature is a complicated combination of the first and second derivative, but for a first derivative near zero, it approaches being equal to the second derivative. An application of this geometric interpretation, is Euler's beam theory. The theory of the distribution of stress and the way a linear-elastic material responds to stress, tells us that the curvature is directly determined by the bending moment in the beam. Integrating the curvature once, we get the slope. Integrating the slope, we get the deflection, and the equation of the shape of the deformed beam.
@Дмрд.джи
@Дмрд.джи Жыл бұрын
In calculus, students are usually taught "the second derivative test for concavity". The second derivative gives you information about the point of inflection. Namely, whenever the second derivate is positive, the first derivative is concave up; and when it is negative, the first derivative is concave up. (When it's zero the first derivative is horizontal)
@REDandBLUEandORANGE
@REDandBLUEandORANGE 6 жыл бұрын
Why does my teacher not show us this stuff
@jamesveronica124
@jamesveronica124 5 жыл бұрын
I don't know dude. I don't know why teachers don't do this stuff
@alimensah1153
@alimensah1153 4 жыл бұрын
I show these stuffs to my students but they say I m not a good teacher M making things complex and dont go straight to the point
@rhuturajmirashi7369
@rhuturajmirashi7369 4 жыл бұрын
@@alimensah1153 they are not students they are parrots
@alimensah1153
@alimensah1153 4 жыл бұрын
@@rhuturajmirashi7369 😂😂 probably They want to be exercises solver machine
@satvikp3186
@satvikp3186 4 жыл бұрын
@@alimensah1153 Dont worry you are explaining the things right way, your students are bad not you :D
@arlenestanton9955
@arlenestanton9955 8 ай бұрын
I watch math classes from MIT you tube and the professor write really big, so people in the back can see. This would be great here.
@jimcar53
@jimcar53 4 жыл бұрын
Could you please write larger, very diff to see.
@AKS.7
@AKS.7 3 жыл бұрын
You play video on 1080p
@sandstormgamers6295
@sandstormgamers6295 5 жыл бұрын
What an amazing video
@abdullahnarejo1259
@abdullahnarejo1259 2 жыл бұрын
Everything is fine, but how have you start with 1 and then to zero. Fro sinx and then for dy/dx of sinx=cost. Positive & xome down to zero,?
@divyadharshinim1042
@divyadharshinim1042 4 жыл бұрын
Amazing lecture.but could you write a little big.
@buckeyepilot3929
@buckeyepilot3929 3 жыл бұрын
Lost me on that one. First time.
@lsubandtrumpet2014
@lsubandtrumpet2014 5 жыл бұрын
You're so bubbly! I like it!
@Tiger-789
@Tiger-789 4 жыл бұрын
Thanks :) no one explained this before!
@rushikeshpatil1600
@rushikeshpatil1600 6 жыл бұрын
Tutions in whics country Very nice
@artificiallift9110
@artificiallift9110 6 жыл бұрын
School in Australia
@bach556
@bach556 4 жыл бұрын
He proved that the derivative of sin is cos by using some particular points but he has to prove that it is true for all points ... that’s how things work in maths in general
@thinkgrow4296
@thinkgrow4296 4 жыл бұрын
The content and lecture delivery was perfect... the sound quality ruined everything.... I can't use headphones because it gives me headache at least a full day ... so no other option left for me....
@ernestschoenmakers8181
@ernestschoenmakers8181 4 жыл бұрын
A bit confusing cause the local minimum of the sine curve should level up with the local minimum of the cosine curve. He didn't draw it correctly.
@zacharymcguirk6431
@zacharymcguirk6431 2 жыл бұрын
Wait wym, the local minimum is a stationary point?
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