MJ22 P42 Q5 Capacitor Series Discharging | May/June 2022 | Cambridge A Level 9702 Physics

[@trigobrooken6260]

I remember this question back then , it created so much discussion on reedit A levels were best time of my life

[@AdamKandil-j6h]

at 22:00 , when you started subbing the values into the exponential equation. Why did you sub C as the total capacitance and not the capacitance of the 22uF capacitor?

[@owaisahmed5265]

Miss, if it was a parallel capacitor circuit, would we still use combined capacitance?

[@lavender127]

Hi mam, your videos are so helpful. Is there a way you could share some commonly asked questions that could come in this year May/June 2023 series?

[@syedrayyan9314]

Thank you so much you r the best 🎉🎉❤❤❤❤

[@Monalisa-f4n]

Thank you so much!!

[@maham22]

To calculate the voltage that the capacitor got from total 12 volts, can we do the following calculation 12/(47+22)=0.1739*47= 8.17V is the part of the voltage the capacitor of 22 microfarad had, because C and V is inversely proportional? I hope my question makes sense. Thank you so much for uploading these wonderful videos, it really helps!

[@lex-is9ge]

yeah

[@ummmm55]

please solve 2023 papers they are out

[@arissmax]

HI teacher, Thanks u for the wonderful classed of Alevel. i think the logic of this question is against with the previous question 19.3b. In here, u mentioned the Q should be equal cause the two capacitors are in series, while in 19.3b u said V should be equal after disconnecting with battery. Which one is right? i am so confused. Could u help. Many thanks.

[@tahabashir9405]

MAM WHY DONT YOU JUST USE Q/C = V FOR CALULCATING THE V NOT, COME ON PLEASE WHY SUCH A LONG METHOD

[@rogue9433]

Heyy thanks a lot guys, ❤️❤️

[@طالبمجتهدجدا]

الله ياخذ اختباراتكم

[@mnolg1330]

هههه صادق