17.3a Time Graphs and SHM Energy | A2 Oscillation | Cambridge A Level Physics

[@spirall2100]

I can't believe how u can teach such confusing stuff in such an organised yet concise way. Tysm.

[@spirall2100]

14:15 was actually mindblowing XD Been doing d/dx from even before o levels, no one explained it like that.

[@Ahmad-mc2rw]

This is just beautiful specially the wave pattern

[@eshalshoaib5923]

such an organized lecture.... amazing work!

[@trigobrooken6260]

11:20 wait so miss if i start displacement with " cos" (max displacement ) does it mean that velocity is -sin and acceleration is --cos ?

[@trigobrooken6260]

So meaing that acceleration velocity equations differ depending on starting position and this could be figured out by trigo differentiation. AHHHHHHHHHHHHHHHHHH

[@ETphysics]

You got it!

[@Syedhasannn]

Are we supposed to memorize the equations?

[@BOBO_4869]

No need, why would we memorise lol? If you happen to forget them by any chance, just use chain rule and differentiate the trig functions!

[@Heyjudeeeee12321]

how can circular motion be SHM ? there is no mean position and also nowhere the net force is 0. how then ma'am 2:54

[@furqan8201]

it can, because eventually for a body in circular motion, u can get a is proportional to -x, which is the condition for SHM

[@Heyjudeeeee12321]

@@furqan8201 but circular motion is only periodic and not oscillatory because the wheels do not move to and fro about a mean position.

[@furqan8201]

@@Heyjudeeeee12321 "A motion repeating itself is referred to as periodic or oscillatory motion, " from google😅.

[@danishqureshi2]

There is a phase and periodic relationship between UCM and SHM, that's why.

[@BOBO_4869]

You are right, UCM is not a SHM. If it is "uniform", the circle must be symmetrical in any way so acceleration is definitely not changing at all, and it is always directed towards centre so no way it will be opposite to the displacement vector. It is related to sinusoidal graphs because it is treated as a unit circle so values of sin and cos can be determined

[@trigobrooken6260]

Use can really never run way understanding without watching booster video. PLease watch booster video

[@ETphysics]

Yepp, wise advice right there, since most of us may not link our maths knowledge to physics!