propped cantilever beam with point load at center || structural analysis || etution

[@civilguy7818]

Sir in the case of Bending moment diagram you drawn as a curve shape but it is a linear

[@kshitijverma25]

yes right

[@akila3596]

Clear explanation thank u

[@ramanjaneyuludonapati2926]

Good

[@garagasrinivas6026]

thank you sir

[@ymym1175]

sir can u tell the how you get the values of deflection clearly rather than giving answers directly

[@shreenathmukarambi6051]

If u teaching something means clearly everything u should say...how that deflection came..directly putting formula means

[@-Surya-rs8gc]

Same doubt bro if you are clarified with that doubt can you explain this deflection topic to me???

[@palaniappankarthik]

Your BMD is completely wrong. BMD is a first order curve instead of a higher order curve. The location of max BM should be where the shear force becomes zero. Please recheck

[@tafferuddinsha8k611]

How to know where is max deflection and value of max deflection after finding point of contraflecture

[@bhanu.sbhanu.s6477]

For slope and same deflection point load at with cantilever there is no vertical reaction placed..

[@samhithatalks6979]

excuse me sir how did u write that downward deflection eqn by adding both slope and deflection of a cantilever beam

[@doredlanagaraju1472]

For slope and deflection answer you can refer cantilever beams chapter which is subjected to the point load at center ...you can get it in R. K. Bansal

[@doredlanagaraju1472]

I didn't extended it in the lecture

[@Januthepluripotent]

According to mohrs second theorm we equate the both deflection since the load is not at the free end we will find the deflection of eccentric loading by adding deflection to the slope and the ditance btween load and free end tnq🙏

[@civilengineersajalsantra8638]

Sir bm diagram linear hobe

[@Januthepluripotent]

Sir where the shereforce changes its sings the bm is max so u have to draw the bm diagram max at tge point of sf beomes zero and the diagram is linear too but i understood well😃

[@afnaazeez4113]

Sir your explanation was good, but how did you find the deflection? Is there an equation for that? And the BMD is linear not curve

[@satishr5307]

Deflection = (area of BMD* centroid from free end)/EI

[@VasanthKumar-bf9je]

@@satishr5307 bro why can't we take centroid from fixed end

[@satishr5307]

@@VasanthKumar-bf9je we should take centroid from the place where we need to find deflection that's why

[@Januthepluripotent]

Since there are formulas for the all deflections in salient cases

[@Januthepluripotent]

@@VasanthKumar-bf9je since we can not take the reference line on the fixed end we couldn't take the distance from fixed end

[@a_d007_1]

BMD can't be Parabolic in the case of Point Load.

[@madhushankar5359]

Sir, can u please give me link for entire unit notes. It is not clear in r.k bansal and I couldn't find any other references explained in the manner as rk bansal. and my exams are coming up in 4 days. So Plzz upload pdf.🙏

[@sairamladdu4567]

Your SFD is reversed according to ur solution

[@dhananjaysharma9421]

BMD galat hai

[@banothunikhil2655]

BMD is completely wrong it should varie linearly not parabolically