Even-odd mode analysis of Wilkinson power divider and its S-parameters by Dr. Niraj Kumar VITCC

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RF Design Basics

RF Design Basics

Күн бұрын

Пікірлер: 33
@harshitakulkarni965
@harshitakulkarni965 2 жыл бұрын
Great video! I understood this better than my college lectures. Thank you!
@shaheerirfan7449
@shaheerirfan7449 3 жыл бұрын
Amazing explanation sir, your microwave series is really helpful in exams. Love from PAKISTAN.
@yaswanthmaradana935
@yaswanthmaradana935 22 күн бұрын
Thank u so much. Today is my exam and it helped me a lot
@ajayddair
@ajayddair 3 жыл бұрын
Neatly presented I could recollect my old lessons.Thanks
@RFDesignbasics
@RFDesignbasics 3 жыл бұрын
Thanku
@wonhyungheo8011
@wonhyungheo8011 Жыл бұрын
Thank you sir. I really appreciate your lecture. It's really helpful to understand well.
@chrisshort4864
@chrisshort4864 Жыл бұрын
You are the best my friend. Thank you so much.
@xabierzu
@xabierzu 4 жыл бұрын
i dont understand how you found out V2E is = V0
@Sheikshameer.
@Sheikshameer. 2 ай бұрын
Sir I have a doubt, if signal is travelling from port 1 to port 2,port 3 and it is -3db . If signal travel from port 2 and 3 then it should add the signal and it should be 0 db.
@Anonymous____________A721
@Anonymous____________A721 8 ай бұрын
Nicely byhearted
@blakecrosby6406
@blakecrosby6406 2 жыл бұрын
for the odd mode analysis why is zin looking into the port infinity and not infinity in parallel with the resistor shorted to ground?
@zhengagata5277
@zhengagata5277 4 жыл бұрын
can you take an example which is not equal power split divider?
@AmitKumarSahoo
@AmitKumarSahoo 2 жыл бұрын
Sir, I have a doubt, in your 2 port network analysis, we saw Γ(L)=V2+/V2-. but here at 15:21 we are using Γ=V-/V+ (quoting as Γ is at load side reflection co-eff). The ratio is inverse here compared to the two port network. I think it's Γ→Γ (out) on load side. Could you kindly clarify on this. Thanks in advance, Sir.
@kanishkaam633
@kanishkaam633 2 жыл бұрын
Sir I am hema can be your student for RF and microwave products
@georgenikakos1065
@georgenikakos1065 Жыл бұрын
Why at minute 6.34 the two parallel 1 does occurring in 2 and not 0.5... What am I missing
@RFDesignbasics
@RFDesignbasics Жыл бұрын
Actually 1 is divided in two parallel parts for making an equivalent circuit to apply odd and even modes.
@georgenikakos1065
@georgenikakos1065 Жыл бұрын
@@RFDesignbasics oh OK so 2ohms parallel equals 1 Thanks for clarifying
@pj_jaswanth
@pj_jaswanth 4 жыл бұрын
Sir, why is Zin(e) equal to z^2/2. How did that formula came. is Zin(e) not equal to (z+2)?
@RFDesignbasics
@RFDesignbasics 4 жыл бұрын
Watch it carefully. It's clearly explained in the video.
@brijbharti
@brijbharti 3 жыл бұрын
Plz make video for gysel power divider
@erikmjelde4428
@erikmjelde4428 4 жыл бұрын
No sure what you are doing with you matching equation. usually the middle impedance is the root of the two outside impedances but you make the root have something to do with the input impedance.
@zhengagata5277
@zhengagata5277 4 жыл бұрын
very clear, thanks!
@tadehmirzakhanian893
@tadehmirzakhanian893 3 жыл бұрын
Thannk you sir!
@bhargavkanjariya2816
@bhargavkanjariya2816 4 жыл бұрын
Clearly explained.
@RFDesignbasics
@RFDesignbasics 4 жыл бұрын
Thanks.
@iqrachaudhary4394
@iqrachaudhary4394 4 жыл бұрын
If we want to design dual band then?
@nguyenbka6525
@nguyenbka6525 4 жыл бұрын
can you simulate one
@RFDesignbasics
@RFDesignbasics 3 жыл бұрын
Uploaded now in HFSS Tutorial playlist.
@srivatsungopalakrishanan9517
@srivatsungopalakrishanan9517 4 жыл бұрын
Neat presentation
@RFDesignbasics
@RFDesignbasics 4 жыл бұрын
Thanks 🙂
@nguyenbka6525
@nguyenbka6525 4 жыл бұрын
thank you so much
@문성준-u1s
@문성준-u1s 9 ай бұрын
korean subtitles plz
@PressStopandgethealt
@PressStopandgethealt 9 ай бұрын
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