Examples on FSK Frequency Shift Keying | Digital Communication | Engineering Funda

Examples of FSK Frequency Shift Keying is explained by the following outlines:
0. FSK Frequency Shift Keying
1. Examples of FSK Frequency Shift Keying
Chapter-wise detailed Syllabus of the Digital Communication Course is as follows:
Chapter-1 Basics of Digital Communication System: • Introduction to Digita...
Block Diagram of Digital communication system, Advantages, and disadvantages of digital communication system, Scrambling, Regenerative Repeater, Eye Diagram, Attention of signal, Bit rate and Baud rate.
Chapter-2 Digital Modulation Techniques: • Digital Modulation Tec...
Amplitude Shift Keying ASK, Frequency Shift Keying FSK, Phase Shift Keying PSK, Differential Phase Shift keying DPSK, Quadrature Phase Shift Keying QPSK, Binary Phase Shift Keying BPSK, M array Frequency Shift Keying MFSK, Quadrature Amplitude Modulation QAM, Comparison of QAM and PSK.
Chapter-3 Pulse Digital Modulation: • Pulse Digital Modulation
Sampling, Aliasing, Nyquist rate, Types of sampling, Performance comparison of sampling, PWM - Pulse width modulation, PPM - Pulse Position modulation, Performance comparison of PAM, PWM and PPM, Quantization and its parameters, SNR of Quantization, Uniform Quantization, Pulse Code Modulation PCM, Nonuniform Quantization, Companding basics, A law and Mu law for Nonuniform quantization, Differential Pulse Code Modulation DPCM, Delta Modulation DM, Adaptive Delta Modulation ADM.
Chapter-4 Multiple Access Techniques: • Multiple Access Techni...
Examples on TDM, Examples on T1 carrier system.
Chapter-5 Line Coding Techniques: • Line Coding Techniques
Basic of Line Coding Techniques, Pulse shaping techniques, NRZ, RZ & Manchester coding, PSD of NRZ unipolar line coding scheme, PSD of NRZ polar line coding scheme, PSD of NRZ bipolar line coding scheme, PSD of Manchester polar line coding scheme, Comparison of Unipolar, Polar, Bipolar and Manchester Line coding scheme.
Chapter-6 Information theory: • Information Theory
Basics of Information, Basics of Entropy, Shannon Fano Encoding, Huffman Coding, Lempel Ziv Coding, Shannon Hartley theorem, basics of probability, Random variables, Cumulative distribution function CDF, Probability Density function PDF.
Chapter-7 Error detection and error correction codes: • Error Detection and Er...
Block Codes, Hamming Codes, Linear Block Codes, Cyclic Codes, Convolutional Codes, Code Trellis, Viterbi Algorithm, Block Codes for single parity checks, Block Codes for product codes, Block Codes for Repetition codes, Cyclic codes for a systematic codeword, Cyclic codes for nonsystematic codeword.
Chapter-8 Spread Spectrum Modulation: • Spread Spectrum Modula...
Basics of Spread Spectrum Modulation, Frequency Hoping Spread Spectrum FHSS, Direct Sequence Spread Spectrum DSSS.
Engineering Funda channel is all about Engineering, Technology, and Science. This video is a part of Digital communication.
#FSK #FrequencyShiftKeying #DigitalCommunication @EngineeringFunda

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[@saumilshah3532]

Those who are asking d=1 is given but sir has joined the two frequencies: d has nothing to do with distance between frequencies it is individual for each frequency as can be seen in formula of bandwidth of a single frequency is (1+d)r. In previous video d is taken as 0 just to get minimum bandwidth

[@cvagk4754]

Sir, you explained in FSK lesson is- for minimum B.W -when d=0 but in this example you take d=1 for the B.W(min) calculation... If it is correct Need some explanation sir

[@omop5922]

Same doubt

[@rajatsoni6021]

Sir, why did you considered 0 distance between the spectrums?

[@EngineeringFunda]

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[@editztown5262]

In first question why do we calculate the minimum bandwidth the question didn't ask for it ?

[@afzalstories]

i love you and thax alort i am from pakistan and i love you very much

[@namaranelson4935]

from the second example d=1 not d=0 and how comes the spectrum takes the shape for d=0. clarification is highly appreciated

[@devanshjain4659]

Sir d=0 frequency spectrum of both 0 n 1 touches so in question d=1 so how u have done it

[@ranabindumondal9301]

how can I determine the FSK system is 2 levels?

[@Ishaan819]

Hello sir , greetings from Nepal.can you make video on error probability of FSK system? Your videos are great 🌞

[@divyanshsanwal4071]

In the second question, when calculating carrier frequency, the amplitude to frequency graph that you have drawn is correct for d=0 (as explained in previous video) . But in this question d=1. So why are the two waveforms touching?

[@EngineeringFunda]

In FSK, you have two carrier frequency, fc0 for 0's and fc1 for 1's

[@divyanshsanwal4071]

@@EngineeringFunda so why isnt there a gap between the spectrum of fc1 and fc2

[@EngineeringFunda]

It is not complsory to have gap. Even this one channel only . So there will be inter symbol interference after some extent of pulse dispersion.

[@sumitgupta9890]

@@EngineeringFunda then why you said that in previous video that if d=0, there there is no gap between fc0 nd fc1?

[@paidijahnavi]

That's for ASK and this is for FSK

[@overmind15]

at what part did it say that its a two level FSK? or you just assume it?

[@EngineeringFunda]

If it is not mentioned then it's good to calculate by Binary FSK.

[@nikhilKumar-ui8bs]

Sir why did u take 2 level, where is written in that qstn. 2 nd

[@المهندسرسولعباس]

What is the part of the panel that can do the frequency shift?

[@yagzyalcntas553]

last video in fsk there were multiple carrier frecuencies and bw form-ary fsk was (1+d).r + (L-1).(gap bw fo and f1) but here we have only one carrier frequency 10MGHz so how can we frequency shift key if we only have 1 frequency? thanks in advance 2nd question: did we even used carrier frequency in first question?? i mean bw = L.r r is (8.(3mbps/3bits)) = 10MHz but we didnt actually used fc=10Mhz did we?

[@eshwar7105]

a) Its. FSK frequency not carrier. b) 2.(del).f= (1+d).r put this in equation you get BW= L.(1+d).r c)Carrier frequency is typo for fsk frequency.

[@anwarhossainraju3763]

Sir, Please solve this question, I am unable to solve it. A binary fsk modulation has bitrate 140 KBPS and modulation index 0.75 find maximum channel bandwidth?

[@savantsingh4200]

Thanks sir

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Your positive comments motivates me, my goal is to create largest community of engineers in entire globe, so please help me for that by sharing this lecture series(playlist) with your friends in social media (watsapp, telegram etc). Thanks and welcome 🙏

[@md.ashikurrahman7508]

A binary FSK modulation has bit rate 144 kbps and modulation index 0.75. Find the maximum channel bandwidth. Please do it sir

[@devanshjain4659]

Sir may I know ur notes and covered topics are sufficient for UGC net preparation ??

[@EngineeringFunda]

You will have to practice more examples after studying from my videos

[@sshivaji9783]

In the first pb , why we take bw=Lr?

[@eshwar7105]

put value of 2*del*f as (1+d)*r and simplify.

[@RY-uh3dc]

Sir in first question why did you take min B.W.

[@ashishvarghese2684]

He calculated the minimum possible Bandwidth. That means the difference between the two frequencies we take must be at least (1+d)r. Otherwise, it will overlap.

[@RY-uh3dc]

@@ashishvarghese2684 thnx😀

[@chiblackjesus]

How do you know when it's multilevel fsk

[@pottalokesh2039]

Explanations should be improved in the lectures too many reasons and detailing was missing a lot .

[@neelshah1588]

sir make videos on gramschmidit orthogonalization

[@ankitsenentertainment9270]

We can have L =23 =8. The baud rate is S =3 MHz/3 =1000 Mbaud. This means that the carrier frequencies must be 1 MHz apart (211f =1 MHz). The bandwidth is B =8 x 1000 =8000. I don't understand this..this solution is from the book of Behrouz A. Forouzan.