Expression for relativistic force

[@PhysicsEducator]

Hi viewers , I am currently updating the playlist "Mathematical Tools for Physics Olympiad" by incorporating every math concept used at Physics Olympiad level. Have a watch and leave some nice comments underneath the videos kzbin.info/aero/PLC7TpkjuQjvIfLuVYwZ_yXS98YMj1W2R7

[@edwardgheorghita8077]

So much more helpful than my text, thank you!

[@davidc.dasilva3735]

Thank very much for your work about this derivation, for me it was very important because I did not find this derivation in books about basics Physics, gratulation once Mr. Physics Reporter.

[@CHEESYhairyGASH]

Very nice, our professor did not have the confidence to derive this by hand and presented it as a series of animations on some slides, it was awful. This is fantastic. Thank you.

[@victorsuarez4333]

This was exactly what I was looking for. Thank you so much. Also, your handwriting is amazing haha.

[@PhysicsEducator]

Glad it was helpful!

[@connorkelly865]

At 11:20 why is a dv/dt put at the end of the equation?

[@शब्दसंगीत]

Thats the derivative of v by t, similar to what you get when you derivate any other term(y and not x) with t, it will be dy/dt. Hope this is correct.

[@stevenlin6106]

Beautiful!

[@niteshchandra2796]

Dude, its relativity, u need to explain from reference of frame as well. It's not just about solving equation, it's about understanding how force and momentum is percieved from various frame with relative motion and it's implications. A person who is stationary, and a person who is in relative motion, will observe different magnitude and direction of forces between two bodies. Force is nothing but change in momentum. I.e not only momentum will be percieved differently, but change in momentum of the two bodies will also be percieved differently by the two people in relative motion. Also, the energy of a body will be observed different by the two people. Higher the relative velocity of the body from the observer, higher the observed energy. Energy would be E=E0/sqrt(1-v2/c2). So in order to accelerate a body to c, energy of the body needs to be increased to infinity. Suppose, we apply a constant force,f, for say over x distance in direction of force, energy supplied is just fx. Either you need to apply infinite magnitude f or have to apply the finite force for infinite time to accelerate a body to velocity of light.

[@Long_Live_Bangladesh_71]

THANKS SIR 😍 I had problems in the 3rd line of the differentiation .u explained it well.😇😇I wish u healthy and happy life.

[@rofiqulislam01253]

You can write both mathematical@ theoritical terms plzz

[@JafarIqbal-nl1wb]

It is very nice.

[@monicapym8948]

Very clear and helpful!!

[@surendrakverma555]

Good

[@0Navin0]

good work...but you should have talked a little about the speed which appears in gamma. i have a conceptual difficulty there, because since we're putting speed of particle itself there...that means if i want i can imagine two frames of references - one being the rest frame outside the particle and the second being the frame of the particle itself, now here i get confused, because the particle's frame is accelerated. So in essence we are kind of applying special relativity to an accelerated frame. can that be done?

[@sayantanmukherjee9528]

NAVIN CHAURASIYA the frame is not accelerated. the frame is moving with speed v which is uniform so it's a inertial frame.

[@speckrel4512]

NAVIN CHAURASIYA The speed which appears here in this derivation is the speed of the particle measured from some inertial frame, say ground frame. Everything being done here is in some inertial frame. If you want to solve the problem in the object's frame, the of course special relativity won't work. Even if the object is accelerating, the frame in which we are measuring it's acceleration is not.

[@speckrel4512]

And yes velocity of particle in its own reference frame would be zero not v :)

[@priyankaman9660]

Thank you so much sir. Very well explained 🙂

[@PhysicsEducator]

You are welcome

[@santi_hec]

Gracias!

[@futurestar3348]

People who put dislikes need to say why the are disliking these videos. You cant not like it if its not wrong, like did he miss a minus sign or something? Explain yourself

[@learningpoint2711]

good job

[@sumrasumra2168]

Thank you so much sir g

[@shivanimeharwa8334]

Thank you sir

[@WaiteDavidMSPhysics]

Please go to a real school. Mass in invariant. Four-force=mass x Four-acceleration is the actual physics wherein mass does not depend on speed.

[@africaethiopia6973]

tanks more

[@mrgoodpeople]

a = (ax,ay) = (Fx/(m*γ^3), Fy/(m*γ)), where x - along v, y - across v.

[@macfrankist]

Note that gamma is a function of v not t.

[@garrytalaroc]

THANK YOUUUUU

[@krishnakalita5725]

Thank u sir

[@chhayarahangdale682]

Explain in hindi