Extreme SAT Exam Question | Be Careful!

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Higher Mathematics

Higher Mathematics

Күн бұрын

Пікірлер: 10
@AyushAnand-oy1wc
@AyushAnand-oy1wc 12 күн бұрын
Heart touching question ❤
@RyanLewis-Johnson-wq6xs
@RyanLewis-Johnson-wq6xs 14 күн бұрын
x^2-4=Sqrt[x+4] x=(-1-Sqrt[13])/2=-0.5-0.5Sqrt[13] x=(1+Sqrt[17])/2=0.5+0.5Sqrt[17] It’s in my head.
@에스피-z2g
@에스피-z2g 14 күн бұрын
x^2-4=rt(x+4) f(x)=x^2-4 g(x)=rt(x+4) Two graphs of f(x) and g(x) meet at two points of a and b. You can not calculate based on the arithmetic method. But you can find the area where they are. -3
@RealQinnMalloryu4
@RealQinnMalloryu4 14 күн бұрын
(x^2)^2 ➖ (4)^2={x^4 ➖ 16}=12 2^6 2^2^3 1^2^1 2^1.(x ➖ 2x+1) {x+x ➖}+{4+4 ➖}={x^2+8}=8x^2 2^3x^2:1^1^1x^2: 1x^2 (x ➖ 2x+1).
@ChavoMysterio
@ChavoMysterio 13 күн бұрын
Domain x²-4≥0 (x+2)(x-2)≥0 If x=-3 (-3+2)(-3-2)≥0 (-1)(-5)≥0 5≥0 true If x=0 (0+2)(0-2)≥0 -4≥0 false If x=3 (3+2)(3-2)≥0 (5)(1)≥0 5≥0 true x+4≥0 x≥-4 Therefore, x≤-2 or x≥2.
@Tasin_1312
@Tasin_1312 14 күн бұрын
Use calculator instead 💀
@Mack-ed1ig
@Mack-ed1ig 14 күн бұрын
Please say square, not squirrel
@theRosaryMerchandise
@theRosaryMerchandise 13 күн бұрын
ESPAÑA
@sarahpierris3004
@sarahpierris3004 14 күн бұрын
BAD MATHS. BAD PERSONN; BAD LOGARITHM
@marilynman
@marilynman 13 күн бұрын
Why is that bad math? Why is he a bad person? Why is it a bad logarithm?
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